Q&A - P5 Math

[ppnadh]

1) At a funfair, there were 1/3 as many boys as girls and 2/5 as many adults as children. If there were 24 more adults than boys at the funfair, find the total number of people at the funfair.


2) Inside a bag, there were 3/5 as many red alls as blue balls and 2/3 as many green balls as blue balls. Given that there were 8 more green balls than red balls, how many balls were there in the bag altogether.

Pl help me solve these sums in detail with explanation…Thanks in advance.

[MathIzzzFun]

ppnadh:

1) At a funfair, there were 1/3 as many boys as girls and 2/5 as many adults as children. If there were 24 more adults than boys at the funfair, find the total number of people at the funfair.


2) Inside a bag, there were 3/5 as many red alls as blue balls and 2/3 as many green balls as blue balls. Given that there were 8 more green balls than red balls, how many balls were there in the bag altogether.

Pl help me solve these sums in detail with explanation....Thanks in advance.

Hi

Q1...

http://i41.tinypic.com/vybfbq.jpg\">

cheers.

[MathIzzzFun]

ppnadh:

1) At a funfair, there were 1/3 as many boys as girls and 2/5 as many adults as children. If there were 24 more adults than boys at the funfair, find the total number of people at the funfair.


2) Inside a bag, there were 3/5 as many red alls as blue balls and 2/3 as many green balls as blue balls. Given that there were 8 more green balls than red balls, how many balls were there in the bag altogether.

Pl help me solve these sums in detail with explanation....Thanks in advance.

Hi

Q2..

http://i42.tinypic.com/23m8w0n.jpg\">

you can also use ratio method for these question... for eg.
Q2.
Red : Blue --> 3 : 5 , Blue : Green --> 3 : 2
Red : Blue : Green --> 9u : 15u : 10u, total --> 34u
10u - 9u = 1u
1u --> 8, 34 x 8 = 272

cheers.

[Jamesbond]

Thanks a lot…

[clblinym]

Can anybody help me solve the following math prob? TIA. It is from CHIJ 2010 CA1, paper 2, Q18

http://i42.tinypic.com/pywpe.gif\">

[tianzhu]

clblinym:

Can anybody help me solve the following math prob? TIA. It is from CHIJ 2010 CA1, paper 2, Q18

http://i42.tinypic.com/pywpe.gif\">

Hi

There are multiple answers, 107, 119, 131, and 143.

The number of strawberries chosen by you in (a) will affect the number in (b)

Usually students will solve this question with “Systematic Listing”

A quicker way is to find the multiples of (4 and 6) – 1 between 100 and 150.

Best wishes

[clblinym]

tianzhu:

clblinym:

Can anybody help me solve the following math prob? TIA. It is from CHIJ 2010 CA1, paper 2, Q18

http://i42.tinypic.com/pywpe.gif\">

Hi

There are multiple answers, 107, 119, 131, and 143.

The number of strawberries chosen by you in (a) will affect the number in (b)

Usually students will solve this question with “Systematic Listing”

A quicker way is to find the multiples of (4 and 6) – 1 between 100 and 150.

Best wishes

Thank you ver much. so will tell my son go for “Systematic Listing”. I do not think my son would understand 12u-1, but will try to explain to him anyway.

As for the following Math Q, I do not understand the solution given. Can anyone help to explain. TIA.


A group of boys share a packet of marbles among them. If each boy gets 5 marbles, there will be 4 marbles short. If each boy gets 4 marbles, there will be 3 marbles left over. How many marbles are there in the packet?


The solution given is as follows:

4+3/5-4 = 7/1=7 (there are 7 boys)
7X4+3=31.
I do not understnd 4+3/5-4 . Can anyone explain? TIA.

[MathIzzzFun]

clblinym:

tianzhu:

[quote=\"clblinym\"]Can anybody help me solve the following math prob? TIA. It is from CHIJ 2010 CA1, paper 2, Q18

http://i42.tinypic.com/pywpe.gif\">

Hi

There are multiple answers, 107, 119, 131, and 143.

The number of strawberries chosen by you in (a) will affect the number in (b)

Usually students will solve this question with “Systematic Listing”

A quicker way is to find the multiples of (4 and 6) – 1 between 100 and 150.

Best wishes

Thank you ver much. so will tell my son go for “Systematic Listing”. I do not think my son would understand 12u-1, but will try to explain to him anyway.

As for the following Math Q, I do not understand the solution given. Can anyone help to explain. TIA.


A group of boys share a packet of marbles among them. If each boy gets 5 marbles, there will be 4 marbles short. If each boy gets 4 marbles, there will be 3 marbles left over. How many marbles are there in the packet?


The solution given is as follows:

4+3/5-4 = 7/1=7 (there are 7 boys)
7X4+3=31.
I do not understnd 4+3/5-4 . Can anyone explain? TIA.[/quote]Hi

hope this helps ...

http://i39.tinypic.com/2zzkbxu.jpg\">

cheers.

[YumYum]

Hi, can anyone help with this Qn:


Ashley, Betsy and Carlie shared some sweets.
Ashley received 11/13 of the total number of sweets Betsy and Carlie received.
Betsy received 1/2 of the total number of sweets Ashley and Carlie received.
Carlie had 12 fewer sweets than Ashley.
How many sweets did the 3 girls share altogether?

Thanks

[alan000]

http://i43.tinypic.com/6gy2l3.jpg\">

YumYum:

Hi, can anyone help with this Qn:


Ashley, Betsy and Carlie shared some sweets.
Ashley received 11/13 of the total number of sweets Betsy and Carlie received.
Betsy received 1/2 of the total number of sweets Ashley and Carlie received.
Carlie had 12 fewer sweets than Ashley.
How many sweets did the 3 girls share altogether?

Thanks

Dear Yum Yum,

Hope this helps:-)

Mrs Alan