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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • T Offline
      tianzhu
      last edited by

      Hi moderators


      Please help to delete.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • Xiao HuX Offline
        Xiao Hu
        last edited by

        tianzhu:
        Xiao Hu:

        Hi Tianzhu,

        Thx. But I was thinking why can't the breadth be > 10cm? What's stopping the breadth to be say 11cm or 12 cm etc?

        TIA,
        Xiaohu.

        Hi Xiaohu

        The breadth of the shaded area is 4cm (10-6).

        As the slide the rectangle upwards till its top edge touches the top of the square, it moves a distance of 6cm.

        Therefore the breadth of rectangle is equal to 4+6 which is 10.

        Alternatively, you may slide the square down till its lower side touches the lower side of the rectangle.

        Best wishes

        Hi Tianzhu,
        If the rectangle's breadth is indeed 10, then yes, moving to the top or bottom will move 6cm up or 4cm down.

        Please see the figure I draw, these are to the scale of mm. The square is same 10mmx10mm as the original question's. The rectangle is bigger at 20mmx 30mm. The perimeter of the rectangle is 100mm. So for this new diagram, the rectangle still moves a distance of 6mm if you slide the rectangle up but it does not make the breadth 10mm, right?

        http://i44.tinypic.com/4uzbww.gif\">

        Is there supposed to be another guess-&-check strategy in order to get the breadth of the rectangle, using the information of the given perimenter to be 52?


        TIA,
        Xiao Hu

        1 Reply Last reply Reply Quote 0
        • Z Offline
          zico
          last edited by

          Is there a algerbra way to solve this?

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Hi moderators


            Please help to delete.

            Best wishes

            1 Reply Last reply Reply Quote 0
            • Xiao HuX Offline
              Xiao Hu
              last edited by

              tianzhu:
              Xiao Hu:


              Is there supposed to be another guess-&-check strategy in order to get the breadth of the rectangle, using the information of the given perimenter to be 52?
              TIA,
              Xiao Hu

              Hi Xiao Hu.

              This question has multiple answers.

              Let's wait for TS to tell us what is the expected response from the WS or school.

              Best wishes

              Hi Tianzhu,
              Er, who is TS? Wasn't the question from \"clblinym\"? I was like 喧宾夺主!!
              But that's exactly what I thought when I first read the question, that it should have more than 1 answer.

              Thanks for your generous help and expertise in this forum.
              Xiaohu.

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                Xiao Hu:

                Er, who is TS? Wasn't the question from \"clblinym\"?
                Hi Xiao Hu

                Good Morning.

                TS refers to Thread /Topic starter. It is similar in meaning to OP (Original poster).

                Best wishes

                1 Reply Last reply Reply Quote 0
                • W Offline
                  wintay
                  last edited by

                  Can anyone help to solve the problem sum below. Thanks


                  6 hats and 5 belts cost $150. 5 hats and 6 belts cost $147. What is the cost of one belt?

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    wintay:
                    Can anyone help to solve the problem sum below. Thanks

                    6 hats and 5 belts cost $150. 5 hats and 6 belts cost $147. What is the cost of one belt?
                    Hi

                    If you’re familiar with SE, you may use it.

                    Otherwise, you may work using MD or letters of the alphabet.

                    HHHHHH (6H) + BBBBB(5B) ------- 150
                    HHHHH(5H) + BBBBBB(6B) ------- 147

                    Hence, H ----- B + 3

                    BBBBBB + 18 + BBBBB ------- 150

                    BBBBBBBBBBB(11B) + 18 ------ 150

                    BBBBBBBBBBB(11B) + 18 ------ 150

                    BBBBBBBBBBB(11B) ------ 132

                    B ------ 12

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • W Offline
                      wintay
                      last edited by

                      tianzhu:
                      wintay:

                      Can anyone help to solve the problem sum below. Thanks

                      6 hats and 5 belts cost $150. 5 hats and 6 belts cost $147. What is the cost of one belt?

                      Hi

                      If you’re familiar with SE, you may use it.

                      Otherwise, you may work using MD or letters of the alphabet.

                      HHHHHH (6H) + BBBBB(5B) ------- 150
                      HHHHH(5H) + BBBBBB(6B) ------- 147

                      Hence, H ----- B + 3

                      BBBBBB + 18 + BBBBB ------- 150

                      BBBBBBBBBBB(11B) + 18 ------ 150

                      BBBBBBBBBBB(11B) + 18 ------ 150

                      BBBBBBBBBBB(11B) ------ 132

                      B ------ 12

                      Best wishes

                      Hi Thanks. Btw what is SE? And is that the only way to solve the problem sum?

                      1 Reply Last reply Reply Quote 0
                      • R Offline
                        rocklee
                        last edited by

                        Hi can someone please help on the following question from SA1 2011 Nanyang:


                        Q1. Hui Hui had some stickers. She gave 18 stickers to her sister and 5/7 of the stickers to Mary. Then she used 3/4 of the remainder for her project and had 35 stickers left. How many stickers did she have at first?

                        Q2. Ali, Bala and Carl shared 90 marbles. If Ali gave 6 marbles to Bala, Bala gave 2 marbles to Carl amd after that Carl gave 1/4 of what he had then to Ali, the three boys will have the same number of marbles in the end. How many more marbles than Ali did Carl have?

                        Thanks.

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