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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • Xiao HuX Offline
      Xiao Hu
      last edited by

      tianzhu:
      clblinym:

      My son had some problem in solving the question below. Can anyone help? TIA http://i44.tinypic.com/33w43yr.png\">


      Hi

      Good Morning.

      Draw a double sided arrow to show 10cm on the top and left side of the square and you’ll be able to see that the length and breadth of the shaded area are 6cm and 4cm.

      Perimeter of rectangle = 52cm
      Breadth of rectangle = 10cm
      Hence, length of rectangle = (52 – 20)/2 = 16cm

      Area of shaded part = 6*4 = 24 sqcm

      Area of unshaded area = (10*10) + (16*10) – 24 = 236 sqcm

      Best wishes

      Hi Tianzhu,
      May I know how you get the Breadth of rectangle = 10cm? That seems to be key to answering the rest of the question.

      TIA,
      Xiaohu

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Hi moderators


        Please help to delete.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • Xiao HuX Offline
          Xiao Hu
          last edited by

          tianzhu:
          Xiao Hu:


          Hi Tianzhu,
          May I know how you get the Breadth of rectangle = 10cm? That seems to be key to answering the rest of the question.

          TIA,
          Xiaohu

          Hi Xiaohu

          Visualise this, move the rectangle upwards until its top edge touches the top edge of the square.

          Best wishes

          Hi Tianzhu,
          Thx. But I was thinking why can't the breadth be > 10cm? What's stopping the breadth to be say 11cm or 12 cm etc?

          TIA,
          Xiaohu.

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Hi moderators


            Please help to delete.

            Best wishes

            1 Reply Last reply Reply Quote 0
            • Xiao HuX Offline
              Xiao Hu
              last edited by

              tianzhu:
              Xiao Hu:

              Hi Tianzhu,

              Thx. But I was thinking why can't the breadth be > 10cm? What's stopping the breadth to be say 11cm or 12 cm etc?

              TIA,
              Xiaohu.

              Hi Xiaohu

              The breadth of the shaded area is 4cm (10-6).

              As the slide the rectangle upwards till its top edge touches the top of the square, it moves a distance of 6cm.

              Therefore the breadth of rectangle is equal to 4+6 which is 10.

              Alternatively, you may slide the square down till its lower side touches the lower side of the rectangle.

              Best wishes

              Hi Tianzhu,
              If the rectangle's breadth is indeed 10, then yes, moving to the top or bottom will move 6cm up or 4cm down.

              Please see the figure I draw, these are to the scale of mm. The square is same 10mmx10mm as the original question's. The rectangle is bigger at 20mmx 30mm. The perimeter of the rectangle is 100mm. So for this new diagram, the rectangle still moves a distance of 6mm if you slide the rectangle up but it does not make the breadth 10mm, right?

              http://i44.tinypic.com/4uzbww.gif\">

              Is there supposed to be another guess-&-check strategy in order to get the breadth of the rectangle, using the information of the given perimenter to be 52?


              TIA,
              Xiao Hu

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              • Z Offline
                zico
                last edited by

                Is there a algerbra way to solve this?

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                • T Offline
                  tianzhu
                  last edited by

                  Hi moderators


                  Please help to delete.

                  Best wishes

                  1 Reply Last reply Reply Quote 0
                  • Xiao HuX Offline
                    Xiao Hu
                    last edited by

                    tianzhu:
                    Xiao Hu:


                    Is there supposed to be another guess-&-check strategy in order to get the breadth of the rectangle, using the information of the given perimenter to be 52?
                    TIA,
                    Xiao Hu

                    Hi Xiao Hu.

                    This question has multiple answers.

                    Let's wait for TS to tell us what is the expected response from the WS or school.

                    Best wishes

                    Hi Tianzhu,
                    Er, who is TS? Wasn't the question from \"clblinym\"? I was like 喧宾夺主!!
                    But that's exactly what I thought when I first read the question, that it should have more than 1 answer.

                    Thanks for your generous help and expertise in this forum.
                    Xiaohu.

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      Xiao Hu:

                      Er, who is TS? Wasn't the question from \"clblinym\"?
                      Hi Xiao Hu

                      Good Morning.

                      TS refers to Thread /Topic starter. It is similar in meaning to OP (Original poster).

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • W Offline
                        wintay
                        last edited by

                        Can anyone help to solve the problem sum below. Thanks


                        6 hats and 5 belts cost $150. 5 hats and 6 belts cost $147. What is the cost of one belt?

                        1 Reply Last reply Reply Quote 0

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