Q&A - P5 Math

[YumYum]

Dear Mrs Alan,


Thank you for your detailed working. Can you pl explain why you took 24/3?

Thanks.

[small]

Hi YumYum,


HTH...

Differentiate the unit of these two case with 'parts and units' then you will be able to understand the solution.

As the total unit should remain as the both case thus 24 parts in case 1 is same as 3 units in case 2

[Jamesbond]

1)3/4 of chelsia’s money is the same as 2/3 of benson’s money. If chelsia had $18 less than benson, what is the total sum of money of chelsia and benson?


2) There is a total of 620 apples and oranges at a stall. 3/8 of the oranges is equal to 2/5 of the apples. How many apples are there at the stall?

3)Daniel bought 75 pencil and pens. 3/5 of the pencils is equal to 2/5 of the pens. How many pencils did daniel buy?

Pl explain detail how to solve the prolems…Thanks in advance.

[clblinym]

Dear MathIzzzFun,


Thank you very much for your help. My son and I can understand. Really appreciate it.

[MathIzzzFun]

Jamesbond:

1)3/4 of chelsia's money is the same as 2/3 of benson's money. If chelsia had $18 less than benson, what is the total sum of money of chelsia and benson?


2) There is a total of 620 apples and oranges at a stall. 3/8 of the oranges is equal to 2/5 of the apples. How many apples are there at the stall?

3)Daniel bought 75 pencil and pens. 3/5 of the pencils is equal to 2/5 of the pens. How many pencils did daniel buy?

Pl explain detail how to solve the prolems....Thanks in advance.

Hi

Q1. 3/4 of chelsia's money = 2/3 of benson's money
--> 6/8 of Chelsia's money = 6/9 of Benson's money
So,
Chelsia's money --> 8 units
Benson's money --> 9 units
1 unit --> $ 18
Total 17 units --> $ 18 x 17 = $ 306

They had $306 altogether.

You can use the same approach for Q2 and Q3.

cheers.

[clblinym]

My son had some problem in solving the question below. Can anyone help? TIA http://i44.tinypic.com/33w43yr.png\">

[tianzhu]

Hi moderators.


Please help to delete.

Best wishes

[Xiao Hu]

tianzhu:

clblinym:

My son had some problem in solving the question below. Can anyone help? TIA http://i44.tinypic.com/33w43yr.png\">

Hi

Good Morning.

Draw a double sided arrow to show 10cm on the top and left side of the square and you’ll be able to see that the length and breadth of the shaded area are 6cm and 4cm.

Perimeter of rectangle = 52cm
Breadth of rectangle = 10cm
Hence, length of rectangle = (52 – 20)/2 = 16cm

Area of shaded part = 6*4 = 24 sqcm

Area of unshaded area = (10*10) + (16*10) – 24 = 236 sqcm

Best wishes

Hi Tianzhu,
May I know how you get the Breadth of rectangle = 10cm? That seems to be key to answering the rest of the question.

TIA,
Xiaohu

[tianzhu]

Hi moderators


Please help to delete.

Best wishes

[Xiao Hu]

tianzhu:

Xiao Hu:

Hi Tianzhu,
May I know how you get the Breadth of rectangle = 10cm? That seems to be key to answering the rest of the question.

TIA,
Xiaohu

Hi Xiaohu

Visualise this, move the rectangle upwards until its top edge touches the top edge of the square.

Best wishes

Hi Tianzhu,
Thx. But I was thinking why can't the breadth be > 10cm? What's stopping the breadth to be say 11cm or 12 cm etc?

TIA,
Xiaohu.