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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • Y Offline
      YumYum
      last edited by

      YumYum:
      Hi, need help with this one as well: http://i43.tinypic.com/2wmi8hd.jpg\">


      Dear MathIzzFun, thank you for your usual help.

      1 Reply Last reply Reply Quote 0
      • Z Offline
        Zack7
        last edited by

        thinkgmama:
        Hi,


        Please help me with this question :

        Samuel and Bob shared some stickers in the ratio 2:9.
        The total number of stickers shared was between 120 and 170
        After Bob had given some stickers to Samuel, the ratio became 3:4.
        How many stickers did Bob have at first?

        Thank you in advance.
        before giving
        S:B
        2:9
        total = 2+9 = 11 units

        after giving
        S:B
        3:4 (* this ratio might be intended as 4:3, the question is a little vague)
        total = 3+4 = 7 units

        let the number of stickers given be x
        let total be y

        (9/11)y - (4/7)y = x ,

        hence (19/77) y = x

        this gives you the relationship between total stickers y against stickers given x.
        that is, for every 77 total stickers, 19 stickers have to be given to maintain the ratios above

        so the question says the total stickers is between 120 and 170, so assuming that stickers are whole numbers, 19/77 will be scaled by 2 to 38/154. remember that we are dealing with ratios, not absolute numbers.

        this means for every 154 stickers, 38 have to be given to maintain the above ratios.

        thus, 154 is the total stickers, and BOB had (9/11)y stickers in the beginning,
        which means he has 126

        1 Reply Last reply Reply Quote 0
        • T Offline
          thinkgmama
          last edited by

          Zack7:
          thinkgmama:

          Hi,


          Please help me with this question :

          Samuel and Bob shared some stickers in the ratio 2:9.
          The total number of stickers shared was between 120 and 170
          After Bob had given some stickers to Samuel, the ratio became 3:4.
          How many stickers did Bob have at first?

          Thank you in advance.

          before giving
          S:B
          2:9
          total = 2+9 = 11 units

          after giving
          S:B
          3:4 (* this ratio might be intended as 4:3, the question is a little vague)
          total = 3+4 = 7 units

          let the number of stickers given be x
          let total be y

          (9/11)y - (4/7)y = x ,

          hence (19/77) y = x

          this gives you the relationship between total stickers y against stickers given x.
          that is, for every 77 total stickers, 19 stickers have to be given to maintain the ratios above

          so the question says the total stickers is between 120 and 170, so assuming that stickers are whole numbers, 19/77 will be scaled by 2 to 38/154. remember that we are dealing with ratios, not absolute numbers.

          this means for every 154 stickers, 38 have to be given to maintain the above ratios.

          thus, 154 is the total stickers, and BOB had (9/11)y stickers in the beginning,
          which means he has 126


          Hi,

          Thank you for the help rendered.


          The part that I do not understand id why we have to scale it by 2. Is it because we have to meet the criteria of the 'total stickers is between 120 and 170'? Therefore if its not 19/77 but if it is ('40/120' - fictional) then there will be no need to scale?

          This is the part which I do not understand. Can you help please? Thank you.

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            thinkgmama:

            This is the part which I do not understand. Can you help please? Thank you.
            Hi

            One key point to take note is that the total number of stickers remains the same before and after the transfer.

            Before
            Samuel:Bob ------- 2:9(11) ------- 14:63 (77)

            After
            Samuel:Bob ------- 3:4 (7) -------- 33:44 (77)

            Make the total number of units the same.A common multiple of 7 and 11 is 77.

            The number of stickers is in multiples of 77

            77,154,231.....

            154 is between 120 and 170

            77 units = 154

            1 unit = 2

            Bob = 63 units = 126

            Best wishes

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              thinkgmama:
              Hi,


              Please help me with this question :

              Samuel and Bob shared some stickers in the ratio 2:9.
              The total number of stickers shared was between 120 and 170
              After Bob had given some stickers to Samuel, the ratio became 3:4.
              How many stickers did Bob have at first?

              Thank you in advance.
              Hi
              The transfer is between Samuel and Bob, so the total number of stickers will remain the same --> \"equalize\" the \"before\" and \"after\" ratios.

              Before transfer:
              Samuel : Bob --> 2:9 --> 14u : 63u (total 77u)
              after transfer:
              Samuel : Bob --> 3:4 --> 33u : 44u (total 77u)

              Since the total number of stickers was between 120 & 170, the only multiple of 77 in this range is 77 x 2 = 154
              So, 77u --> 154, 1u --> 2
              At first, Bob --> 63u --> 126 stickers.

              cheers.

              1 Reply Last reply Reply Quote 0
              • T Offline
                thinkgmama
                last edited by

                Thank you all of you. I finally understand šŸ™‚ appreciate the help.

                1 Reply Last reply Reply Quote 0
                • W Offline
                  Winx5015
                  last edited by

                  Hi, got a word problem on Speed. Please help!


                  At 14 30, David left Bedok and cycled towards Pasir Ris at a speed of 10km/h. At the same time, Muthu left Pasir Ris and cycled towards Bedok at 12Km/h along the same road. If the distance between Bedok and Pasir Ris was 6Km/h, how far apart were the boys 15 minutes later?

                  Thanks.

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    small
                    last edited by

                    Winx5015:
                    Hi, got a word problem on Speed. Please help!


                    At 14 30, David left Bedok and cycled towards Pasir Ris at a speed of 10km/h. At the same time, Muthu left Pasir Ris and cycled towards Bedok at 12Km/h along the same road. If the distance between Bedok and Pasir Ris was 6Km/h, how far apart were the boys 15 minutes later?

                    Thanks.
                    Hi,

                    HTH..

                    After 15 mins (1/4 h):
                    David cycled ---- 10 km/h x 1/4 h = 2.5 km
                    Muthu cycled ---- 12 km/h x 1/4 h = 3 km

                    If the distance between Bedok and Pasir Ris was 6km

                    6 km -5.5 km = 0.5 km

                    15 mins later, the two boys were 0.5 km apart.

                    1 Reply Last reply Reply Quote 0
                    • W Offline
                      Winx5015
                      last edited by

                      Thanks small for your help.

                      1 Reply Last reply Reply Quote 0
                      • Z Offline
                        Zack7
                        last edited by

                        thinkgmama:
                        Zack7:

                        [quote=\"thinkgmama\"]Hi,


                        Please help me with this question :

                        Samuel and Bob shared some stickers in the ratio 2:9.
                        The total number of stickers shared was between 120 and 170
                        After Bob had given some stickers to Samuel, the ratio became 3:4.
                        How many stickers did Bob have at first?

                        Thank you in advance.

                        before giving
                        S:B
                        2:9
                        total = 2+9 = 11 units

                        after giving
                        S:B
                        3:4 (* this ratio might be intended as 4:3, the question is a little vague)
                        total = 3+4 = 7 units

                        let the number of stickers given be x
                        let total be y

                        (9/11)y - (4/7)y = x ,

                        hence (19/77) y = x

                        this gives you the relationship between total stickers y against stickers given x.
                        that is, for every 77 total stickers, 19 stickers have to be given to maintain the ratios above

                        so the question says the total stickers is between 120 and 170, so assuming that stickers are whole numbers, 19/77 will be scaled by 2 to 38/154. remember that we are dealing with ratios, not absolute numbers.

                        this means for every 154 stickers, 38 have to be given to maintain the above ratios.

                        thus, 154 is the total stickers, and BOB had (9/11)y stickers in the beginning,
                        which means he has 126


                        Hi,

                        Thank you for the help rendered.


                        The part that I do not understand id why we have to scale it by 2. Is it because we have to meet the criteria of the 'total stickers is between 120 and 170'? Therefore if its not 19/77 but if it is ('40/120' - fictional) then there will be no need to scale?

                        This is the part which I do not understand. Can you help please? Thank you.[/quote]yes, if your fraction obtained is 40/120, 120 falls within the range given, so you 'won't have to scale', because your ratio satisfies the absolute number requirement.

                        but to be very strict, you have actually scaled your ratio by 1.


                        e.g

                        5units : 3 units (This is a ratio)
                        5 stickers : 3 stickers (This is an absolute number relationship)
                        you make the transition from ratio to absolute number relationship by scaling by 1 in this case.

                        e.g

                        my leg is 2 times longer than my hand

                        2 Leg length : 1 hand length (This is a ratio)

                        (below are absolute number relationships)
                        1metre : 0.5metre (scale of 1/2)
                        2m : 1m (scale of 1)
                        3m : 1.5 m (scale of 1.5)
                        ... and the possibilities go on...

                        so in accordance to your problem , it essentially says, my arm and leg adds up to between 2.5metres to 3.5metres... this means the only possible pair is 2m:1m



                        another example that i find funny :roll: ,

                        for every dollar you earn, the govt gives you 2 dollar as cpf

                        so the ratio is 1:2

                        but you don't earn 1 dollar. you earn say 10 000 bucks

                        so

                        your absolute number relationship is

                        10 000 : 20 000

                        if you earn 100 000 bucks, then it becomes 100 000 : 200 000 and so on...



                        the key point here is that ratios give relationships between 2 variables.

                        they are not absolute number relations.

                        you must recognize this(or your kid), because as you progress into higher levels of study, you will be scaling your ratios by fractions, powers, exponentials etc.

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