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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      peggy:
      Please help with this.


      Denise had 288 beads more that Annie. After Denise lost 1/6 of her beads and Annie lost 75% of her beads, Denise had 303 more beads that Annie. How many beads did Denise have at first ?

      thanks.
      Hi

      Annie --> 12 units (** 1/6 & 3/4 --> lowest common denominator = 12)
      Denise --> 12 units + 288

      After Denise lost 1/6 beads and Annie lost 3/4 of her beads:
      1/6 of Denise --> 2 units + 48
      Denise, left --> 10 units + 240
      Annie, left --> 1/4 x 12 units = 3 units

      10 units + 240 = 3 units + 303
      1 unit --> 9

      Denise, at first --> 12 x 9 + 288 = 396
      Denise had 396 beads at first.

      cheers.

      1 Reply Last reply Reply Quote 0
      • P Offline
        peggy
        last edited by

        MathIzzFun,


        Thanks so much for your prompt reply.

        Have a nice day !

        1 Reply Last reply Reply Quote 0
        • D Offline
          Dreamerz
          last edited by

          tianzhu:
          Dreamerz:

          Hi tianzhu,

          Q1 the total of the two baskets is given as 960.
          Basket A has 600 while B has 360.

          dont know y they test understanding of our language rather than being straight forward ... sigh

          Hi

          First thing first, did you make any changes to the original question?

          Do take note that 600 and 360 were not given in your original question.Please post the original question as it is shown in your source.

          1) mr tan had a total of 960 fruits. 30% of the 600[/u] fruits in basket A were oranges and the rest were pears. 40% of the fruits in basket B were pears and the rest were oranges. after some fruits were transferred from A to B and B to A, 25% of the fruits in basket A and 75% of the fruits in basket B were oranges. how many fruits are there in basket A in the end?

          Best wishes[/quote]

          sorry just realised that the 600 was missing 😞

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Dreamerz:

            sorry just realised that the 600 was missing 😞
            Hi

            With the inclusion of 600 in the original question, then it becomes a regular question seen in past years papers.

            This question touches on simultaneous concept.

            Students who are familiar with SE may use them. Otherwise, they may solve the two equations pictorially or use Units and Parts or letters of alphabet to represent the two variables.

            Due to time constraints, I’ll not be doing the slide, but will be using Units and Parts as an illustration. To convert to MD way, just substitute the Units with boxes or other shapes and the Parts with circles or other shapes

            Basket A
            Oranges ------ 180
            Pears ------ 420

            Basket B
            Oranges ------ 216
            Pears ------ 144

            After the transfer

            Basket A
            Oranges ------ U
            Pears ------ UUU

            Basket B
            Oranges ------ PPP
            Pears ------ p

            U + PPP ------- 396
            UUU + P -------564

            UUUU + PPPP ------- 960
            U + P ------ 240

            UU + (U + P) ------564
            UU + 240 ------ 564
            U ------ 162

            Number of fruits in Basket A in the end ------ UUUU -------162*4 -------- 648

            Best wishes

            1 Reply Last reply Reply Quote 0
            • J Offline
              jarenchuatw
              last edited by

              Thanks…but still can’t really understand the 2nd part added on:


              After 43x27=1161 rectangles have been For the width 166cm, there is a leftover of 166 - 27x6 = 4cm
              Of which, 173/6 = 28 (round down) more rectangles can be cut.
              Total = 1161 + 28 = 1189

              Tot that we have already cut out some rectangles from 173, how come can still divide by 6 again??

              1 Reply Last reply Reply Quote 0
              • C Offline
                CRAZYBANANA
                last edited by

                jarenchuatw:
                Thanks...but still can't really understand the 2nd part added on:


                After 43x27=1161 rectangles have been For the width 166cm, there is a leftover of 166 - 27x6 = 4cm
                Of which, 173/6 = 28 (round down) more rectangles can be cut.
                Total = 1161 + 28 = 1189

                Tot that we have already cut out some rectangles from 173, how come can still divide by 6 again??
                Ya! Since the 173cm side has been cut into 43pc x4cm, then balance is only 1cm, cannot use liao! :?

                1 Reply Last reply Reply Quote 0
                • S Offline
                  small
                  last edited by

                  Please help and TIA


                  Questions:
                  Three groups of pupils, A, B and C, worked on a project at different stages. Group B worked on the project during the first 4 days. Group A and C the n took over and worked together for the next 6 days.After which, Group A was left to complete the remaining work in 9 days. In this arrangement, Group B did 1/3 as much work as Group A while Group C did twice as much as Group B. How long will each group take to do the project without the involvement of other groups?

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    speedmaths.012624com
                    last edited by

                    small:
                    Please help and TIA


                    Questions:
                    Three groups of pupils, A, B and C, worked on a project at different stages. Group B worked on the project during the first 4 days. Group A and C then took over and worked together for the next 6 days.After which, Group A was left to complete the remaining work in 9 days. In this arrangement, Group B did 1/3 as much work as Group A while Group C did twice as much as Group B. How long will each group take to do the project without the involvement of other groups?
                    Hi,

                    One possible method of solving this (without using any fractions in the working):

                    Let the ratio of work done by A:B:C be 3:1:2;
                    Total work to be done is 3 + 1 + 2 = 6 units.

                    [Group B did 1/3 as much work as Group A, while Group C did twice as much as Group B.]

                    Group A worked for 6 + 9 = 15 days.
                    Group B worked for 4 days.
                    Group C worked for 6 days.

                    Group A took 15 days to complete 3 units.
                    Group A will take 30 days to complete 6 units.

                    Group B took 4 days to complete 1 unit.
                    Group B will take 24 days to complete 6 units.

                    Group C took 6 days to complete 2 units.
                    Group C will take 18 days to complete 6 units.

                    Hope this helps.

                    Cheers


                    speedmaths.com


                    .

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      small
                      last edited by

                      speedmaths.com:
                      small:

                      Please help and TIA


                      Questions:
                      Three groups of pupils, A, B and C, worked on a project at different stages. Group B worked on the project during the first 4 days. Group A and C then took over and worked together for the next 6 days.After which, Group A was left to complete the remaining work in 9 days. In this arrangement, Group B did 1/3 as much work as Group A while Group C did twice as much as Group B. How long will each group take to do the project without the involvement of other groups?

                      Hi,

                      One possible method of solving this (without using any fractions in the working):

                      Let the ratio of work done by A:B:C be 3:1:2;
                      Total work to be done is 3 + 1 + 2 = 6 units.

                      [Group B did 1/3 as much work as Group A, while Group C did twice as much as Group B.]

                      Group A worked for 6 + 9 = 15 days.
                      Group B worked for 4 days.
                      Group C worked for 6 days.

                      Group A took 15 days to complete 3 units.
                      Group A will take 30 days to complete 6 units.

                      Group B took 4 days to complete 1 unit.
                      Group B will take 24 days to complete 6 units.

                      Group C took 6 days to complete 2 units.
                      Group C will take 18 days to complete 6 units.

                      Hope this helps.

                      Cheers


                      speedmaths.com


                      .

                      Hi speedmaths.com,
                      Thank you very much... :thankyou:

                      1 Reply Last reply Reply Quote 0
                      • L Offline
                        lousymum
                        last edited by

                        Hi,

                        Need help.
                        If Ahmad and Ben work together, they can complete a job in 12 days.
                        If Ahmad and Ben worked together for 3 days, followed by Ben who worked along for the newxt 5 days, they can finish 5/12 of the job.
                        How many days will each of them need to complete the job if they were to work alond?
                        Thanks.

                        1 Reply Last reply Reply Quote 0

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