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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • T Offline
      tianzhu
      last edited by

      concerned1970:
      So sry i dun get u. Why did we have to get common multiple for 3 and 5?

      Hi

      I believe your child should have learned the “Equal concepts” from his school teacher.

      In this question, one part of children is not the same as one part of children as each box in the MD is of different sizes as they represent different objects.

      We want to make a comparison so we equalise the numerators of the two fractions 3/5 and 5/7.

      3 and 5 have a common multiple of 15.

      Please get your child to draw a model as it might help him/her to see better.

      I am sorry, I don't have time to draw one now.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • M Offline
        mrswongtuition
        last edited by

        Something is wrong with the photo uploader here.


        Anyway, the answer is here: https://www.facebook.com/media/set/?set=a.339535342767810.82445.118642878190392&type=1#!/photo.php?fbid=347705798617431&set=a.339535342767810.82445.118642878190392&type=3&theater

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        • C Offline
          concerned1970
          last edited by

          mrswongtuition:
          Something is wrong with the photo uploader here.


          Anyway, the answer is here: https://www.facebook.com/media/set/?set=a.339535342767810.82445.118642878190392&type=1#!/photo.php?fbid=347705798617431&set=a.339535342767810.82445.118642878190392&type=3&theater
          Ty so much Mrs Wong for yr MD.

          1 Reply Last reply Reply Quote 0
          • C Offline
            concerned1970
            last edited by

            No Pb, Tianzhu. U've helped me alot. 😄

            1 Reply Last reply Reply Quote 0
            • ozoraO Offline
              ozora
              last edited by

              MathIzzzFun:
              ozora:

              need some guide in this question. Tank A and Tank B are identical. Tank A is 2/5 full of water while tank B is 6/7 full of water. The mass of Tank A with its contents is 7/10 of The mass of Tank B with its contents. The total mass of the 2 tanks and their contents is 374kg. Find the mass of an empty tank.


              Hi

              mass of tank A with contents --> 7/17 x 374 kg = 154 kg
              mass of tank B with contents --> 374 kg - 154 kg = 220 kg
              (6/7-2/5)tank of water --> 220 - 154 = 66 kg
              16/35 tank of water --> 66 kg
              mass of tank = 220 - 6/7 tank of water = 220 - 30/16 x 66 = 96.25 kg
              (** 6/7 tank of water = 30/35 tank of water = 30/16 x 66 kg)

              most schools are teaching/doing ratio sums at the moment, here's alternate approach using ratio:
              difference in mass of tanks with contents = difference in mass of contents
              mass of water in tank A : tank B = 2/5 : 6/7 = 7 : 15
              mass of tank A with contents : tank B with contents = 7 : 10
              \"equalize\" the difference:
              mass of water in tank A : tank B = 21u : 45u
              mass of tank A with contents : tank B with contents = 56u : 80u
              mass of tank = 56u - 21u = 80u-45u = 35u
              total mass of both tanks with contents = 136u
              mass of tank = 35/136 x 374 = 96.25 kg


              cheers.

              thanks
              i did a different method which is using
              16/35->66
              1/35->4/125
              2/5-> 14/35
              12/35-> 57.75

              154-57.75=96.25kg

              thanks again for confirming my answer.

              1 Reply Last reply Reply Quote 0
              • S Offline
                sunnydays2
                last edited by

                Hi, I’ve got 2 Math questions.


                1. Alan and Dennis had some money. If Alan spends $70 and Dennis spends $35, Alan will have $515 left. If Alan spends $35 and Dennis spends $70, Alan will have $2300 left. How much does each of them have?

                2. Mr Lim had some stickers and stamps for his class. The number of stickers was 1/2 the number of stamps. After each pupil in the class had received 3 stickers and 8 stamps from Mr Lim, he had 39 stickers and 2 stamps left. What was the total number of stickers and stamps Mr Lim had at first?

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                • S Offline
                  speedmaths.012624com
                  last edited by

                  sunnydays2:
                  Hi, I've got 2 Math questions.


                  1. Alan and Dennis had some money. If Alan spends $70 and Dennis spends $35, Alan will have $515 left. If Alan spends $35 and Dennis spends $70, Alan will have $2300 left. How much does each of them have?
                  Hi,

                  Question 1 looks incomplete.
                  (Probably needs to add \"when Dennis has spent all his money\".)

                  Anyway, for such questions, one solution is to look at the ratios rather than the actual numbers.

                  Look at the example given in Chapter 1 of the Raffles Maths Tricks Volume 1 book (see below):

                  http://i50.tinypic.com/2m7aoev.jpg\">

                  Can you use the example given above to solve Question 1?

                  Cheers

                  speedmaths.com

                  -

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    sunnydays2:

                    2. Mr Lim had some stickers and stamps for his class. The number of stickers was 1/2 the number of stamps. After each pupil in the class had received 3 stickers and 8 stamps from Mr Lim, he had 39 stickers and 2 stamps left. What was the total number of stickers and stamps Mr Lim had at first?
                    Hi

                    Hope this helps.

                    Best wishes

                    http://farm8.staticflickr.com/7214/6994422784_250a9bcd20_z.jpg\">

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                    • P Offline
                      prayhardmum
                      last edited by

                      Can someone help the following question, please? Thanks.


                      Three sisters Lisa, Ming and Nora shared the cost of a present to their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        mrswongtuition
                        last edited by

                        prayhardmum:
                        Can someone help the following question, please? Thanks.


                        Three sisters Lisa, Ming and Nora shared the cost of a present to their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?
                        L : N : M : Total
                        1: -- 4 --: 5
                        -- 9--: 1 : 10

                        The total amount is the same.
                        Therefore we need to multiply the first ratio by 2 to make the total number of units the same.

                        L : N : M : Total
                        2: -- 8 --: 10
                        -- 9--: 1 : 10
                        2 : 7 : 1 : 10

                        7 - 1 = 6 units
                        6 u --> $60
                        1 u --> $10
                        10 u --> $100

                        1 Reply Last reply Reply Quote 0

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