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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • B Offline
      Breadandmuffins
      last edited by

      THank you everyone. Will continue to learn . Just last nite, I was cracking my head over some more questions to help DS revise for his SA1.


      Hi Optimistforum, that qn is taken from the Onsponge book which DS used in school. I had a hard time trying to figure out as well. See stars every nite.

      1 Reply Last reply Reply Quote 0
      • T Offline
        teh_oh
        last edited by

        atutor2001:
        ozora:

        need help:

        1)2 similar shirts cost $26 more than 3 pairs of shoes. If their total cost is $158. find the cost of 1 shirt.

        2) shop A had 164 more customers than shop B.
        after 1/4 of the customers in shop A went to shop B. there were 48 more customers in shop B than shop A.
        How many customers were there in shop A and shop B now?

        Algebra is the easier way. Anyway, if you wish to solve it using logical thinking, a possible way is as follows :

        A is 164 more than B.
        To make A and B equal, 164/2 = 82 must move from A to B
        To make B more than A by 48, another 48/2 = 24 must move from A to B
        (common mistake is in forgetting to divide by 2)

        So a total of 82 + 24 = 106 must move from A to B so that B will be 48 more than A.

        This 106 is 1/4 of the original number in A.

        So the original number in A is 4 quarters, that is 106 x 4 = 424
        So the original number in B is 424 - 164 = 260

        The number in A now is 424 - 106 = 318
        or
        The number in A now is 3/4 of the original 3/4 x 424 = 318

        The number in B now is 260 + 106 = 366

        Personally I don't recommended this way to solve. Too much thinking needed.

        Hi atutor2001,

        My child's working is as follows:
        164 - 48=116
        116 divide 2 = 58
        58 + 48 = 106
        1/4 --> 106
        4/4 - 1/4 = 3/4
        106 x 3 = 318 (Shop A)
        318 + 48 = 366 (Shop B)

        Is my child's workings acceptable?

        Thank you.

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        • 2 Offline
          24hr-mum
          last edited by

          small:
          24hr-mum:

          for qn such as: if the teacher shares her sweets wf 5 pupils she wil hv 3 sweets left, if she share wf 6 pupils she wil b short of 7 sweets, how many sweet she has?any shortcut besides listg the multiples of 5 n 6? the clue gvn is she has more than 40 sweets


          Hi 24hr-mum,

          HTH...

          As the number of sweets in both cases is the same thus the answer is 53 sweets.

          Case 1: 5 students with extra of 3 sweets
          Case 2: 6 students with short of 7 sweets



          my gal math teacher say conceptuallu wrong to say 1 student has 10 sweets

          5 students + 3 sweets = 6 students - 7 sweets
          1 student = 10 sweets

          From case 1 ------(5x10 )+3 = 53 sweets

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          • S Offline
            sunshine0809
            last edited by

            http://i49.tinypic.com/5k3nyh.jpg\">

            Ans 146

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            • S Offline
              Sharmum
              last edited by

              Hi,


              May i know if theres a shorter method?

              :?

              http://i50.tinypic.com/dfehhg.jpg\">

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              • S Offline
                small
                last edited by

                small:
                24hr-mum:

                for qn such as: if the teacher shares her sweets wf 5 pupils she wil hv 3 sweets left, if she share wf 6 pupils she wil b short of 7 sweets, how many sweet she has?any shortcut besides listg the multiples of 5 n 6? the clue gvn is she has more than 40 sweets


                Hi 24hr-mum,

                HTH...

                As the number of sweets in both cases is the same thus the answer is 53 sweets.

                Case 1: 5 students with extra of 3 sweets
                Case 2: 6 students with short of 7 sweets

                24hr-mum:
                my gal math teacher say conceptuallu wrong to say 1 student has 10 sweets

                5 students + 3 sweets = 6 students - 7 sweets
                1 student = 10 sweets

                From case 1 ------(5x10 )+3 = 53 sweets
                Hi 24hr-mum,

                Pictorial diagram will be easier to understand. šŸ™‚

                http://i50.tinypic.com/9an6v6.jpg\">

                1 Reply Last reply Reply Quote 0
                • S Offline
                  small
                  last edited by

                  Sharmum:
                  Hi,


                  May i know if theres a shorter method?

                  :?

                  http://i50.tinypic.com/dfehhg.jpg\">

                  Hi Sharmum,

                  Please refer to attached pic, HTH. šŸ™‚

                  http://i48.tinypic.com/2llecjs.jpg\">

                  1 Reply Last reply Reply Quote 0
                  • J Offline
                    Jamesbond
                    last edited by

                    A set of two blouses costs $41. Ivy found out that she could only buy 4 blouses but not more than 6 blouses with the amount of money she had. What is the possible amount of money she had?

                    1) $50 2) $90
                    3) $150 4) $250

                    Answer is option 2.

                    Pl explain me this in detailllll....VVVVV urgent......I donno..... :yikes:

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      Champion
                      last edited by

                      Jamesbond:
                      A set of two blouses costs $41. Ivy found out that she could only buy 4 blouses but not more than 6 blouses with the amount of money she had. What is the possible amount of money she had?

                      1) $50 2) $90
                      3) $150 4) $250

                      Answer is option 2.

                      Pl explain me this in detailllll....VVVVV urgent......I donno..... :yikes:
                      P4 dd1 answer: 2 blouses $41 then 4 blouses will be $41 x 2 = $84. Therefore $84 nearest is $90; Answer (2).

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        Jamesbond
                        last edited by

                        thanks a lot

                        1 Reply Last reply Reply Quote 0

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