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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • K
      kiasuaunt
      last edited by

      Thank you, MathIzzzFun and 2cor41618 - appreciate your help. I understand now - will get my dd to try out later. God Bless.

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      • C
        Chan09
        last edited by

        Need help

        There were twice as many red pens as blue pens.he sold the pens in bundles of 2 red and 3 blue.
        After selling all the blue pens, he still had 120 red pens left. How many penns did he have at first?
        Ans: 270

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        • T
          tianzhu
          last edited by

          Chan09:
          Need help

          There were twice as many red pens as blue pens.he sold the pens in bundles of 2 red and 3 blue.
          After selling all the blue pens, he still had 120 red pens left. How many penns did he have at first?
          Ans: 270
          Hi

          You may use MD or UM.

          Red : Blue ------ 2:1 -------- 6:3

          He sold 2 units of red pens and 3 units of blue pens.

          Hence, 4 units ------ 120

          This gives 1 unit ------ 30

          Number of pen@first ------ 9 units ------- 270

          Best wishes

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          • isetanI
            isetan
            last edited by

            Hi, need help to cross check the ans to this question:


            Two boxes, A and B, contain some red and blue beads. In box A, the ratio of the no. Of red beads to the no. of blue beads is 2:1. In box B, the ratio of the no. Of red beads to blue beads is 1:3. Box A has thrice as many beads as Box B.

            A) find the ratio of the no. of Red beads in box A to the no. of blue beads in box B.

            B) if 105 red beads are taken out from box A and placed in box B, the ratio of the no. of the red beads to the no. of blue beads in box B becomes 3:2. What is the total no. of beads in the 2 boxes?

            Our working leads ans A is – 8:1, ans B is – 480.

            Appreciate anyone helps if the ans is correct. Many thanks.

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            • isetanI
              isetan
              last edited by

              Hi, another question:


              Tan, Lim and Wong had some pens to sell. Tan had the least no. of pens. Wong’s no. of pens was 30% less than Lim’s. After Tan and Lim had each sold 50% of their pens, Lim had 95 more pens than Tan. If the three men had a total of 330 pens left, what is the total no. of pens they had at first?

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              • K
                ksoh3000
                last edited by

                tks

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                • 2
                  2cor41618
                  last edited by

                  isetan:
                  Hi, need help to cross check the ans to this question:


                  Two boxes, A and B, contain some red and blue beads. In box A, the ratio of the no. Of red beads to the no. of blue beads is 2:1. In box B, the ratio of the no. Of red beads to blue beads is 1:3. Box A has thrice as many beads as Box B.

                  A) find the ratio of the no. of Red beads in box A to the no. of blue beads in box B.

                  B) if 105 red beads are taken out from box A and placed in box B, the ratio of the no. of the red beads to the no. of blue beads in box B becomes 3:2. What is the total no. of beads in the 2 boxes?

                  Our working leads ans A is -- 8:1, ans B is -- 480.

                  Appreciate anyone helps if the ans is correct. Many thanks.
                  I think he answer to part a should be 8:3. Part b is correct 😄

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                  • 2
                    2cor41618
                    last edited by

                    isetan:
                    Hi, another question:


                    Tan, Lim and Wong had some pens to sell. Tan had the least no. of pens. Wong's no. of pens was 30% less than Lim's. After Tan and Lim had each sold 50% of their pens, Lim had 95 more pens than Tan. If the three men had a total of 330 pens left, what is the total no. of pens they had at first?
                    At first

                    Wong---70%
                    Lim---100%

                    After T and L sold 1/2 of their share,

                    Lim---50%
                    Tan---95 less than 50%
                    Wong---70%

                    Thus, 50% + 50% + 70% ----330+ 95
                    170%---425 (Wong + Lim at first)
                    1%----2.5
                    Tan---2x ( 50 x 2.5 - 95) = 60

                    Total at first----60 + 425 = 485

                    😄

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                    • T
                      tutorsg_punggol
                      last edited by

                      ksoh3000:
                      tks

                      U're welcome! Hope it's not too difficult to understand. 🙂

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                      • T
                        tamunawara
                        last edited by

                        thanks a lot . that was really useful

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