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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Herbie:
      I hv two qn


      1. 5/6-2x + 2x-7/x^2-9

      2. X^2-4xy+4y^2 =0, find 2x/y

      Thanks
      Hi

      I believe you have omitted some brackets in the question 1, I have re-write it below - hope it is correct.

      http://i50.tinypic.com/14ebdhe.png\">

      cheers.

      1 Reply Last reply Reply Quote 0
      • H Offline
        Herbie
        last edited by

        Thanks!


        Can assist on the following qns?

        Factorise a(b^2-c^2)-bc(b-c)
        Wat do we look out for when doing such qn?

        Factorise 4a^2-b^2a-b completely.

        Factorise 8/25a^2 -32b^2.
        Do u hv any tips in solving qn?

        1 Reply Last reply Reply Quote 0
        • H Offline
          Herbie
          last edited by

          Deleted

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Herbie:
            Thanks!


            Can assist on the following qns?

            Factorise a(b^2-c^2)-bc(b-c)
            Wat do we look out for when doing such qn?

            Factorise 4a^2-b^2a-b completely.

            Factorise 8/25a^2 -32b^2.
            Do u hv any tips in solving qn?
            Hi

            the questions are practices for factorisation of
            (a+b)(a-b) = a^2-b^2

            you may want to try it - factorise a^2-b^2 into (a+b)(a-b) and then look for the common factors, taking note that 4a^2-b^2 can be factorised into (2a+b)(2a-b) ie 4a^2 = (2a)^2.

            cheers.

            1 Reply Last reply Reply Quote 0
            • O Offline
              ongmt
              last edited by

              1) At a party, there were some ballons, 25 ballon burst & 10% of remaining ballons fly away. If only 60% of the ballons were left, how many ballons were there at first?


              2) Pkt A, B and C each contained some cement. 1/3 of cement was transferred from Pkt A to B. Then 1/3 of the cement transfer from Pkt B to C. Finally, 1/3 of cement transferred from Pkt C to A. In the end, there were 12kg of cement in each pkt. Whar was the mass of cement in Pkt B at first?

              3) A fan club had 150 member last yr. This yr, the no of male member reduced by 20% and number of female member increas by 20%. As a result, there are now as man male member as female members. How many memebers does the club have this year?

              Plse help :udaman:

              1 Reply Last reply Reply Quote 0
              • J Offline
                josephgiri
                last edited by

                ongmt:


                2) Pkt A, B and C each contained some cement. 1/3 of cement was transferred from Pkt A to B. Then 1/3 of the cement transfer from Pkt B to C. Finally, 1/3 of cement transferred from Pkt C to A. In the end, there were 12kg of cement in each pkt. Whar was the mass of cement in Pkt B at first?
                This is a 'constant total' or 'internal transfer' type of qn.

                Working backward

                At the end,
                A:B:C = 12:12:12

                1/3 from C to A,
                2 units left in C
                1 unit -> 6 kg
                A:B:C = 6:12:18

                1/3 from B to C,
                2 units left in B
                1 unit -> 6 kg
                A:B:C= 6:18:12

                1/3 from A to B,
                2 units left in A
                1 unit -> 3 kg
                A:B:C=9:15:12

                Pkt B had 15 kg of cement initially.

                1 Reply Last reply Reply Quote 0
                • J Offline
                  josephgiri
                  last edited by

                  ongmt:
                  1) At a party, there were some ballons, 25 ballon burst & 10% of remaining ballons fly away. If only 60% of the ballons were left, how many ballons were there at first?
                  9 units -> 60%
                  1 unit -> 6 2/3%
                  10 units -> 66 2/3%

                  100% - 66 2/3% = 33 1/3%
                  33 1/3% -> 25 balloons
                  100% -> 75 balloons

                  There were 25 balloons at first.

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    ongmt:
                    1) At a party, there were some ballons, 25 ballon burst & 10% of remaining ballons fly away. If only 60% of the ballons were left, how many ballons were there at first?



                    3) A fan club had 150 member last yr. This yr, the no of male member reduced by 20% and number of female member increas by 20%. As a result, there are now as man male member as female members. How many memebers does the club have this year?

                    Plse help :udaman:
                    Hi

                    Q1.
                    9/10 remaining balloons (after 25 burst)= 3/5 Total = 9/15 Total
                    Total --> 15units
                    Remaining balloons --> 10 units
                    5 units --> 25
                    15 units --> 75
                    There were 75 balloons at first.

                    Q3.
                    4/5 male = 12/10 female
                    12/15 male = 12/10 female
                    Last year
                    Male --> 15 units
                    Female --> 10 units
                    total 25 units --> 150
                    Male --> 90
                    Female --> 60
                    This year, Male --> 72, Female --> 72, total 144 members.

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • I Offline
                      imacsg
                      last edited by

                      Hi,

                      Can you help to solve the below question

                      find x : 10, 16, 26, 40, 58, x

                      Thanks

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        imacsg:
                        Hi,

                        Can you help to solve the below question

                        find x : 10, 16, 26, 40, 58, x

                        Thanks
                        Hi

                        x = 80

                        One way to solve number pattern is to find the difference of two consecutive terms... and repeat for pattern of \"difference\" until the difference is a constant.

                        For this case, you can work out the 1st level difference pattern : 6,10,14,18
                        and then down one more level and get the 2nd level difference pattern :
                        4,4,4
                        So, the 5th number in the 1st level difference pattern is 18+4 = 22
                        and x = 58 + 22 = 80

                        cheers.

                        1 Reply Last reply Reply Quote 0

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