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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • Y Offline
      YumYum
      last edited by

      MathIzzzFun:
      YumYum:

      Hi, I need help with this qn:


      Jane has some one-dollar and some fifty cent coins. The number of one-dollar coins is thrice the number of fifty cent coins. If the total value of the coins is $171.50, how many fifty cent coins does Jane have? Thks

      Hi
      use grouping concept...

      Put 3 x $1 and 1x $0.50 in a packet --> total value in 1 packet = $3.50
      $171.50 / $3.50 = 49 packets
      there is 1 x 50 cents coin in each packet,
      number of fifty cents coins --> 49

      cheers.


      Thanks šŸ˜„

      1 Reply Last reply Reply Quote 0
      • C Offline
        Cpy2001
        last edited by

        Please help



        Jewel bought some strawberries and wanted toput them into boxes. If she put 4 strawberries into each box, there would be 3 strawberries left. If she put 6 strwaberries into each box,she would have 5 strawberries left.

        A) if the number of strawberries was between 100 and 150, how many many strawberries did Jewel buy?

        B) Jewel decided to put all the strawberries equally into bags of 16. Find the min. Number of bags that she would need.

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          Cpy2001:
          Please help



          Jewel bought some strawberries and wanted toput them into boxes. If she put 4 strawberries into each box, there would be 3 strawberries left. If she put 6 strwaberries into each box,she would have 5 strawberries left.

          A) if the number of strawberries was between 100 and 150, how many many strawberries did Jewel buy?

          B) Jewel decided to put all the strawberries equally into bags of 16. Find the min. Number of bags that she would need.
          Hi

          there are multiple answers for the question.

          4 strawberries/box, 3 strawberries left --> short of 1 to make 4,
          6 strawberries/box, 5 strawberries left --> short of 1 to make 6.
          By adding 1 more strawberry to the total number, the new total can be packed into boxes of 4 and boxes of 6 exactly.

          Lowest common multiple of 4 & 6 in the range of 100 to 150 --> 108, 120, 132, 144
          So, possible number of strawberries --> 107, 119, 131, 143

          number of bags needed for bags of 16 --> 7, 8, 9, 9

          cheers.

          1 Reply Last reply Reply Quote 0
          • K Offline
            ksasalways
            last edited by

            Received note that HCI is organising a Mathematics Workshop run by an experience trainer, targeting the current Primary 5 & 6 students to excel in their PSLE mathematics.


            Thoughts some of the parents who are thinking of sending your child IP school like HCI might want to consider writing to them at [email protected] for details and registration.

            The first of the two parts workshop details:
            Topics : Area, Volume, Angle and Speed.
            Date : 14 July 2012 (Saturday)
            Time : 9.15 am. to 12.15 pm. (Tea break from 10.15 am. to 10.35 am.)
            Venue : HCI High School Section Lecture Theatre 2
            Who should attend : Parents and P5 & P6 Children
            Registration Fee : Per Adult : $20
            Per Child: $10
            Walk in : Per Adult : $25 and Per Child : $ 15
            Registration Deadline : 7 July 2012

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            • C Offline
              concerned1970
              last edited by

              Hi guys, pls help me solve the following 3 ques without using algebra method. Ty in adv.


              1) The figure is made up of two circles P & Q. The ratio of the area of Circle P to the area of Circle Q is 3:2. The shaded part is 5/8 of Circle Q. What is the ratio of the unshaded area of the figure to the area of the figure? ( Circle P is bigger than Circle Q and they intersect each other in between which is 5/8. )

              2) Miss Ling spent 5/9 of her money on 10 stuffed bears and 5 dolls. She could buy 20 stuffed bears with the rest of her money. What was the ratio of the cost of a doll to the cost of a stuffed Bear?

              3) Wendy and Kelly had $128 altogether. Wendy spent 1/2 of her money on a blouse while Kelly spent 2/5 of her money on a dress. The dress cost $8 more than the blouse. How much money did Wendy have at first?

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              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                concerned1970:
                Hi guys, pls help me solve the following 3 ques without using algebra method. Ty in adv.


                1) The figure is made up of two circles P & Q. The ratio of the area of Circle P to the area of Circle Q is 3:2. The shaded part is 5/8 of Circle Q. What is the ratio of the unshaded area of the figure to the area of the figure? ( Circle P is bigger than Circle Q and they intersect each other in between which is 5/8. )
                Hi
                Q1. P : Q = 3 : 2 = 12u : 8u
                Shaded Q = Shaded P = 5u
                Unshaded P : Unshaded Q : Shaded : Total --> 7u : 3u : 5u: 15u
                Unshaded/Total = 10/15 = 2/3

                cheers.

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  concerned1970:
                  Hi guys, pls help me solve the following 3 ques without using algebra method. Ty in adv.



                  2) Miss Ling spent 5/9 of her money on 10 stuffed bears and 5 dolls. She could buy 20 stuffed bears with the rest of her money. What was the ratio of the cost of a doll to the cost of a stuffed Bear?
                  Hi
                  Q2.
                  Total amount --> 9 units
                  10 bears + 5 dolls --> 5 units
                  20 bears --> 4 units, 10 bears --> 2 units, 5 bears --> 1 unit
                  5 dolls --> 5 units - 2 units = 3 units
                  Cost of a doll : Cost of a bear = 3 : 1

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    concerned1970:
                    Hi guys, pls help me solve the following 3 ques without using algebra method. Ty in adv.



                    3) Wendy and Kelly had $128 altogether. Wendy spent 1/2 of her money on a blouse while Kelly spent 2/5 of her money on a dress. The dress cost $8 more than the blouse. How much money did Wendy have at first?

                    Hi

                    cost of blouse --> 2 units, Wendy --> 4 units
                    cost of dress --> 2 units + $8, Kelly --> 5 units + $20
                    total --> 9 units + $20 = $128
                    1 unit --> 12
                    Kelly --> 5 x $12 + $20= $80
                    Wendy --> 4 x $12 = $48

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      concerned1970
                      last edited by

                      MathIzzzFun:
                      concerned1970:

                      Hi guys, pls help me solve the following 3 ques without using algebra method. Ty in adv.


                      1) The figure is made up of two circles P & Q. The ratio of the area of Circle P to the area of Circle Q is 3:2. The shaded part is 5/8 of Circle Q. What is the ratio of the unshaded area of the figure to the area of the figure? ( Circle P is bigger than Circle Q and they intersect each other in between which is 5/8. )

                      Hi
                      Q1. P : Q = 3 : 2 = 12u : 8u
                      Shaded Q = Shaded P = 5u
                      Unshaded P : Unshaded Q : Shaded : Total --> 7u : 3u : 5u: 15u
                      Unshaded/Total = 10/15 = 2/3

                      cheers.

                      Hi, how did u get 12u for Circle P? And 7u for unshaded P?

                      1 Reply Last reply Reply Quote 0
                      • C Offline
                        concerned1970
                        last edited by

                        MathIzzzFun:
                        concerned1970:

                        Hi guys, pls help me solve the following 3 ques without using algebra method. Ty in adv.



                        3) Wendy and Kelly had $128 altogether. Wendy spent 1/2 of her money on a blouse while Kelly spent 2/5 of her money on a dress. The dress cost $8 more than the blouse. How much money did Wendy have at first?


                        Hi

                        cost of blouse --> 2 units, Wendy --> 4 units
                        cost of dress --> 2 units + $8, Kelly --> 5 units + $20
                        total --> 9 units + $20 = $128
                        1 unit --> 12
                        Wendy --> $80

                        cheers.

                        Could u pls show me the model diagram in how u worked out this pb? Totally clueless how u got the answer.

                        1 Reply Last reply Reply Quote 0

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