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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • F Offline
      ftwm
      last edited by

      Another question, pls help:


      0.25 of the coins in a box were 20¢ coins 0.5 of the remaining coins were 10¢ coins and the rest were 50¢ coins. The total value of the coins in the box was $101.20.
      (a) Find the value of 50¢ coins in the box in dollars.
      (b) If all the 20¢ coins were exchanged for 10¢ coins, express the number of 10¢ coins as a fraction of the total number of coins in the box? Give your answer as a decimal (Can you discover a shortcut?)

      1 Reply Last reply Reply Quote 0
      • F Offline
        ftwm
        last edited by

        Pls help.


        There were some red, blue and green jelly beans in a bag. The number of red jelly beans was 2 1/3 times the number of green jelly beans. The number of blue jelly beans was 0.5 times the total number of the red and green jelly beans. When 200 jelly beans were added into the box, the number of green beans become 1.5 times the original number of green jelly bean, the number of red jelly beans was increased by 1/7 and the number of blue beans was increased by 50. Find the total numberof jelly beans in the bag in the end.

        Thank you.

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          ftwm:
          Pls help.


          There were some red, blue and green jelly beans in a bag. The number of red jelly beans was 2 1/3 times the number of green jelly beans. The number of blue jelly beans was 0.5 times the total number of the red and green jelly beans. When 200 jelly beans were added into the box, the number of green beans become 1.5 times the original number of green jelly bean, the number of red jelly beans was increased by 1/7 and the number of blue beans was increased by 50. Find the total numberof jelly beans in the bag in the end.

          Thank you.
          Hi

          for questions involving decimals, change the decimals to fractions first, and the questions will not be that daunting.

          Q3. There were some red, blue and green jelly beans in a bag. The number of red jelly beans was 2 1/3 (=7/3)times the number of green jelly beans. The number of blue jelly beans was 1/2 times the total number of the red and green jelly beans. When 200 jelly beans were added into the box, the number of green beans become 1 1/2 (=3/2) times the original number of green jelly bean, the number of red jelly beans was increased by 1/7 and the number of blue beans was increased by 50. Find the total numberof jelly beans in the bag in the end.

          At first,
          Red : Green : Blue = 7 : 3 : 5 --> 14u : 6u : 10u
          in the end,
          Red : Green : Blue --> 16u : 9u : 10u + 50 -- total = 35u + 50

          added --> 2u + 3u + 50 = 200
          1u --> 30
          Total --> 35 x 30 + 50 = 1100

          cheers.

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            ftwm:
            Another question, pls help:


            0.25 of the coins in a box were 20¢ coins 0.5 of the remaining coins were 10¢ coins and the rest were 50¢ coins. The total value of the coins in the box was $101.20.
            (a) Find the value of 50¢ coins in the box in dollars.
            (b) If all the 20¢ coins were exchanged for 10¢ coins, express the number of 10¢ coins as a fraction of the total number of coins in the box? Give your answer as a decimal (Can you discover a shortcut?)
            Hi
            Total coins --> 8u
            20c : 10c : 50c = 2u : 3u : 3u
            Value of 20c : 10c : 50c = $0.4u : $0.3u : $1.5u --> total $2.2u
            2.2u --> 101.20
            1u --> 46
            Value of 50c coins --> 1.5 x 46 = $69

            Number of 50c coins --> 3 x 46 = 138

            All 20c coins exchanged to 10c coins,
            new value of 10c --> $0.4 x 46 + $0.3 x 46 = $ 32.20
            Number of 10c coins = 322

            number of 10¢ coins as a fraction of the total number of coins in the box
            = 322 / (138+322) = 322/460 = 7/10

            cheers.

            1 Reply Last reply Reply Quote 0
            • H Offline
              happyheart
              last edited by

              MathIzzzFun:
              happyheart:

              Need help on this questions. Kindly illustrate with model. Thank you.


              Q) A restaurant had the same number of apples, pears and oranges at first. After 38 pears , some oranges and apples were used, there were 90 fruits left. The number of oranges is 1/2 the number of apples. The number of pears left is 15 fewer than the number of apples left. How many oranges were left?


              Hi

              http://i46.tinypic.com/29w21bl.png\">

              cheers.


              Thank you for the solution.

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                ftwm:
                Hi need help.


                Ali has some singaore stamps, malaysia stamps & australia stamps in two albums. There were 765 stamps altogether. He moved 0.25 of the australia stamps, 0.6 of the malaysia stamps and 45 singapore stamps from the first album to the second album. He now found that there were 2 1/4times as many australia stamps in the first album. How many stamps did ali move from the first album to the second album?
                Hi

                Where is this question from?

                It appears that there are some missing information.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • F Offline
                  ftwm
                  last edited by

                  tianzhu:
                  ftwm:

                  Hi need help.


                  Ali has some singaore stamps, malaysia stamps & australia stamps in two albums. There were 765 stamps altogether. He moved 0.25 of the australia stamps, 0.6 of the malaysia stamps and 45 singapore stamps from the first album to the second album. He now found that there were 2 1/4times as many australia stamps as Malaysia stamps and 0.5 times as many Malaysia stamps as Singapore stamps in the first album. How many stamps did ali move from the first album to the second album?

                  Hi

                  Where is this question from?
                  Its from challenging math P5

                  It appears that there are some missing information.
                  Yup so sorry key in too much anyway ive edit the answer is 261 but i yet to found out the working.

                  Best wishes

                  Thanks a lot for the solution guys

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    ftwm:

                    Ali has some singaore stamps, malaysia stamps & australia stamps in two albums. There were 765 stamps altogether. He moved 0.25 of the australia stamps, 0.6 of the malaysia stamps and 45 singapore stamps from the first album to the second album. He now found that there were 2 1/4times as many australia stamps as Malaysia stamps and 0.5 times as many Malaysia stamps as Singapore stamps in the first album. How many stamps did ali move from the first album to the second album?
                    Hi

                    Album A ----- after the transfer

                    Australia stamps -------- 9 units
                    Malaysia stamps -------- 4 units
                    Singapore stamps ------- 8 units

                    Album A ---- at first

                    Australia stamps -------- 12 units
                    Malaysia stamps -------- 10 units
                    Singapore stamps ------- 8 units + 45

                    30 units + 45 -------- 765

                    1 unit ------ 24

                    Number of stamps transferred from A to B -------- 3 units + 6 units + 45 ------ (9*24) + 45 ----- 261

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      Goodluck8:

                      At the meeting, there are 18 more women than men. The number of women is 45% more than the number of men. How many people were there at the meeting?
                      45% ---> 18
                      100 % ---> 40 people
                      Hi

                      Good Morning

                      45% ---> 18

                      5% ---> 2

                      100% ---> 40 men

                      Number of women ------- 58

                      Number of people ------ 58+40 ------ 98

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        Goodluck8:
                        Thanks Tianzhu

                        But i saw a similiar question in onsponge book
                        Hi Goodluck8

                        I am sorry.I made a mistake in my post this morning.

                        The total number of people ------ number of men + number of women.

                        Please refer to my revised post.

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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