Q&A - PSLE Math
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2632parent:
HiAny one more question
1) Mr lim had some red and green beads. 60% of his beads were red and the rest were green. He lost some of his red beads and the percentage of the beads which were red decreased by 40%. He then had 760 red and green beads left. How meant red beads did he lose?
Many thanks in advance.
Good Morning.
Red ----- 60 units ------ 600
Green ----- 40 units
After a decrease of 40%
Red ----- 36 units ------ 360
36 + 40 ------ 76
76 units ------- 760
1 unit ------10
In the end, red ------ 360
Therefore, he lost 600 - 360 ---- 240
Best wishes -
Need help !
The table below shows the admission fees to a circus for an adult and a child. There were 50 more children than adults at the circus. If a total of $5614 was collected, how many children were at the circus ? Given each adult admission fee is $25 Ang child admission fee is $8. -
Shimmer:
HiNeed help !
The table below shows the admission fees to a circus for an adult and a child. There were 50 more children than adults at the circus. If a total of $5614 was collected, how many children were at the circus ? Given each adult admission fee is $25 Ang child admission fee is $8.
You may use “Grouping Concept”.
Fees collected from 50 children ------- 400
5614 – 400 ------ 5214
Fees for 1 group or 1 set of (1 adult + 1 children) -------- 25 + 8 ------ 33
Number of groups ------- 5214/33 ------ 158
Number of children ------- 158 + 50 ----- 208
Best wishes -
Would appreciate some help with this question.
![](\"http://i1197.photobucket.com/albums/aa424/pixie_dust8/mq6.jpg\")
http://i1197.photobucket.com/albums/aa424/pixie_dust8/mq6.jpg\">
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pixiedust:
HiWould appreciate some help with this question.
This question has been discussed before.
Time taken by tortoise ----- 5.2/3 ------ 104min
For rabbit
60min -----20km
1min ----- 1/3km
1min -----1/3
2mins -----2/3
3mins -----3/3
4mins ----4/3
5mins -----5/3
Total distance travelled in 15mins ---- 5km
The rabbit takes 0.6min to travel remaining 0.2km
Total time taken -----100+15.6 ----115.6
Therefore 115.6 -104 ----11.6min
Best wishes -
Hi, would appreciate help for this Qn, part (b): thanks!
![](\"http://i49.tinypic.com/2s8fok6.jpg\")
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YumYum:
Hi, would appreciate help for this Qn, part (b): thanks!
Hi
This question has been discussed before.
Hope this helps.
Best wishes![](\"http://farm7.staticflickr.com/6063/6139917034_a6c214361a_z.jpg\")
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tianzhu:
YumYum:
Hi, would appreciate help for this Qn, part (b): thanks!
Hi
This question has been discussed before.
Hope this helps.
Best wishes
Tianzhu: thanks for your usual help
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need explanation on math qn, from MO advanced by Terry Chew. Its from chapter 8, qn no. 7.
car A departed from town A and travelled toward town B. At the same time, car B started its journey in the direction of town A from town B. the two cars passed each other 64km away from town B and carried on with their journey. They made U turn upon arriving at the destination so as to return to their town. they passed each other again, this time 52 km away from town A. find the distance between the two point where they passed each other.
key answer:
analysis: the total distance of covered by the two cars is 3 times the distance between town A and town B.
distance covered by car B = 64 x 3
= 192 km :? **this part really blur**
distance between town A and B = 192-52
= 140km
140 - 64 - 52 = 24km
the distance between the two points where they passed each other was 24km.
anyone can explain the highlighted blue part? the rest is understood. thanks... -
CDE:
Hineed explanation on math qn, from MO advanced by Terry Chew. Its from chapter 8, qn no. 7.
car A departed from town A and travelled toward town B. At the same time, car B started its journey in the direction of town A from town B. the two cars passed each other 64km away from town B and carried on with their journey. They made U turn upon arriving at the destination so as to return to their town. they passed each other again, this time 52 km away from town A. find the distance between the two point where they passed each other.
key answer:
analysis: the total distance of covered by the two cars is 3 times the distance between town A and town B.
distance covered by car B = 64 x 3
= 192 km :? **this part really blur**
distance between town A and B = 192-52
= 140km
140 - 64 - 52 = 24km
the distance between the two points where they passed each other was 24km.
anyone can explain the highlighted blue part? the rest is understood. thanks...
when the two cars first met (say at X), Car B travelled 64km; total distance covered by both cars = distance between A & B.
when the two cars met again the second time (say at Y), the total distance covered by both cars = 3 x distance A & B
--> at first meeting point, distance covered by both cars = AX (car A)+ BX (Car B) = AB
--> when the cars reach town A & B, total distance travelled by both cars = XA (car B) + XB (car A) = AB
--> when the cars turn round meet at Y, distance travelled by both cars = AY (car B) + BY (car A) = AB
so, total distance travelled when the cars meet a second time = 3 x AB
When total distance travelled is AB, car B travelled 64 km
When total distance travelled is 3x AB, car B would have travelled 3 x 64 km = 192 km
cheers.
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