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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • S Offline
      speedmaths.012624com
      last edited by

      Shimmer:
      Shimmer:



      If a director get two designers work together Work will be completed in 6 days. If A work alone it wil completed in 10 days. He hired A to work on it for a few days and remaining B will do it.How many days A must spend so that it is done in 12 1/2 days?


      Can someone help on these 3 questions ?

      Hi

      Q3

      One possible solution/method:

      A and B take.... 6 days to do 1 job
      A takes............10 days to do 1 job

      A and B take.... 60 days to do 10 jobs
      A takes.............60 days to do 6 jobs

      B takes.............60 days to do 4 jobs
      (10 - 6 = 4)

      B takes.............60 days to do 4 jobs
      B takes.............15 days to do 1 job
      A takes.............10 days to do 1 job

      B takes.............7.5 days to do 0.5 job
      A takes.............5 days to do 0.5 job

      In this way, they will take 12.5 days to do 1 job.

      Hope this helps.

      Cheers


      speedmaths.com


      PS.
      There is actually a PSLE Maths book that has 4 chapters to teach students how to solve such/similar Maths questions.
      .

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      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        ozora:
        MathIzzzFun:

        [quote=\"whitety\"]Hi, need help on 2 qns.


        2) Huiling had 160 less marbles than George. George gave 75% of his marbles to Huiling. Huiling then gave 20% of her marbles to George. If Huiling had 192 more marbles than George in the end, how many marbles did Huiling have at first?

        Thanks!

        At first,
        Huiling --> 16u
        George --> 16u + 160 --- 75% = 12u + 120

        After George gave 75% to Huiling
        Huiling --> 28u + 120 -- 20% = 5.6u + 24
        George --> 4u + 40

        After Huiling gave 20% to George
        Huiling --> 22.4u + 96
        George --> 9.6u + 64
        Huiling had 192 more, so
        9.6u + 64 + 192 = 22.4u + 96
        4u --> 50

        at first, Huiling --> 200

        cheers.

        Sorry may I know how to get 16units for huiling n 12units +120 for75%?[/quote]One can start with 1 unit or 10 unit but the working will involve fraction/decimal; 16 units was chosen cos it \"matches\" 160 and is divisible by 4.

        75% of (16 units + 160) = 3/4 x (16 unit + 160)= 3/4 x 16 + 3/4 x 160 = 12 + 120

        cheers.

        1 Reply Last reply Reply Quote 0
        • ozoraO Offline
          ozora
          last edited by

          [

          At first,
          Huiling –> 16u
          George –> 16u + 160 — 75% = 12u + 120

          After George gave 75% to Huiling
          Huiling –> 28u + 120 – 20% = 5.6u + 24
          George –> 4u + 40

          After Huiling gave 20% to George
          Huiling –> 22.4u + 96
          George –> 9.6u + 64
          Huiling had 192 more, so
          9.6u + 64 + 192 = 22.4u + 96
          4u –> 50

          at first, Huiling –> 200

          cheers.[/quote]
          Sorry may I know how to get 16units for huiling n 12units +120 for75%?[/quote]

          One can start with 1 unit or 10 unit but the working will involve fraction/decimal; 16 units was chosen cos it "matches" 160 and is divisible by 4.

          75% of (16 units + 160) = 3/4 x (16 unit + 160)= 3/4 x 16 + 3/4 x 160 = 12 + 120

          cheers.[/quote]
          thanks. I have tried using 1 unit and working really involved alot of fractions. THanks for sharing the method.

          1 Reply Last reply Reply Quote 0
          • R Offline
            Robertpattinsonidle
            last edited by

            what is the solution for these questions?


            A rectangle tank was empty at first. Tap A was turned at a rate of 6 litres per min. After 2 min, B drain water at 2liters per min. Both tap turned off after 6 min after Zb was turned on. The tank was 28 cm in height and hold 56 litres find the height of water level in tank when both tank turn off.

            Isaac read a book. 1st day he read 2/5 of it unread. 2nd day he read another 24 page of the book . In the end he read was 5/9the pages did not read. If he finish the rest in 4 days. What was the average number he read for the rest of the book?

            1 Reply Last reply Reply Quote 0
            • K Offline
              kiasustar
              last edited by

              Mr Dano sold 3 types of durian.3/8 were D24, 40%of the remainder were XO n bal were Segamat. The amt of money earned fr 1j

              Kg each type are as follow: D24 $3, XO $4.50 & Segamat $5. The ratio of D24 to XO and Segamat sold on Monday are 4:3:2. In total, he sold 6/7 of the total durians at his stall that day and earned $568. How many Segamat durians did he have at first?

              Anyone can help?

              :thankyou:

              1 Reply Last reply Reply Quote 0
              • 2 Offline
                2DMommy
                last edited by

                tianzhu:
                2DMommy:


                It was my boy school homework. As the teacher was on MC the last 2 days, we are still unable to solve or check the answer. Will get him to check the question again. Thank you !

                Hi

                It's an interesting question.

                One possible scenario is to assume Mr Lim taking 25 minutes to return home at 9am.In this case, the distance of 16 km is between Mrs Lim and the house after a period of 50 minutes.

                Best wishes

                Hi Tianzhu

                Indeed there's an error in this question. It should be :

                Mr and Mrs Lim travelled in opposite directions after leaving their house at the same time. Mr Lim travelled towards Ponggol while Mrs Lim travelled towards Jalan Elias. Mrs Lim drove at a speed which was 12km/h slower than Mr Lim. After 25 min, Mr Lim had to turn back towards home for his misplaced keys while Mrs Lim continued with her journey to Jalan Elias without stopping. At 8am the distance between Mr and Mrs Lim was 16 km. How far was Mrs Lim from her home at 9am?

                😄

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                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  kiasustar:
                  Mr Dano sold 3 types of durian.3/8 were D24, 40%of the remainder were XO n bal were Segamat. The amt of money earned fr 1j

                  Kg each type are as follow: D24 $3, XO $4.50 & Segamat $5. The ratio of D24 to XO and Segamat sold on Monday are 4:3:2. In total, he sold 6/7 of the total durians at his stall that day and earned $568. How many Segamat durians did he have at first?

                  Anyone can help?

                  :thankyou:
                  Hi

                  at first:
                  D24: XO : Segamat --> 3 : 2 : 3 --- total 8


                  Durian sold on Monday:
                  D24: XO : Segamat --> 4:3:2 --- total 9

                  Consider every group of 9 durians sold,
                  Total amount earned
                  = 4 x $3 (D24) + 3 x $4.50 (XO) + 2 x $5 (Segamat)
                  = $35.50

                  Number of groups sold --> $568 ÷ $35.50 = 16
                  Total number of durians sold --> 16 x 9 = 144

                  Number of durians at first --> 7/6 x 144 = 168
                  Number of Segamat durians, at first --> 3/8 x 168 = 63

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • K Offline
                    kiasustar
                    last edited by

                    :thankyou:

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      mumworks
                      last edited by

                      Given that 2/3 of Xavier’s money is equal to 75% of Ian’s money, what fraction of Ian’s money is the total sum of money?


                      what is the answer, 8/17 or 17/8,and why ?

                      Thank you

                      1 Reply Last reply Reply Quote 0
                      • S Offline
                        speedmaths.012624com
                        last edited by

                        speedmaths.com:
                        Essential:

                        Hi please help.... Q10) given that 2/3 of xiacer \"s money is equal to 75 percent of Ian\"s money , what fraction of ian \"s money is the total sum of money


                        Hi,

                        One possible solution:

                        2/3 x Xiacer = 3/4 x Ian

                        (Use equal/common numerators)

                        6/9 x Xiacer = 6/8 x Ian

                        (Now look at the denominators)

                        Xiacer = 9 uints
                        Ian = 8 units
                        Total = 17 units

                        Can you solve from here?

                        Cheers


                        speedmaths.com


                        .

                        Hi,

                        Answer is Total / Ian = 17/8

                        Hope this helps.

                        speedmath.com

                        .

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