2012 PSLE Discussions and Strategy

[charsen]

Math was okay.I am praying hard that many pupils would say hard as the aggerate score would go down,which means that the a star qualification would be 87-90.

[Big fish]

ultimateschooler:

DD says English was very easy and Math was even easier. She says it was so easy she could finish the paper in 1h O: anyone can confirm paper 2 18a)?

She must be a genius.
Is she gifted??

[ximinful]

charsen:

Math was okay.I am praying hard that many pupils would say hard as the aggerate score would go down,which means that the a star qualification would be 87-90.

I find it harder than my school prelim which I scored 100 marks in.

[wsywin2012]

ximinful:

charsen:

Math was okay.I am praying hard that many pupils would say hard as the aggerate score would go down,which means that the a star qualification would be 87-90.

I find it harder than my school prelim which I scored 100 marks in.

\\

which sch you from?

[Be a mom]

cccleo:

You are exactly like my DS

Today, he brought 5rulers, 5corection tapes, 8earsers, 4set square, more than 30 pen, more than 10pencils and 4calculators!!! :yikes: :yikes: :yikes:

champion kid!

[moon143]

Last Question of Paper 2:


(34-4)/2 = 17
1750cm100cm = 85 000cm3
85 000cm3+100^2cm3 = 95 000cm3 –> area of footpath
50cm/2 = 25cm –> radius of circle
(3.1425^238)cm3 = 74 575cm3 –> area of all circles (38 circles)
95 000cm3-74 575cm3 = 20425cm3 (a)

1750cm2 = 1700cm or 17m (b)

Hope this helps!

Q Pan : How did you get 34?

[hunnypie]

Typo… 38…

[charsen]

I did expect some tricky questions,like questions 15 to 18.

But there are some questions in paper one ,likeQ 29.That was a very nice question.
I was shell-shocked about the B part in question 30 in the paper 1.Just have to write the 8-letter word decrease and you’ll get 1 mark.

[wsywin2012]

moon143:

Last Question of Paper 2:


(34-4)/2 = 17
17*50cm*100cm = 85 000cm3
85 000cm3+100^2cm3 = 95 000cm3 --> area of footpath
50cm/2 = 25cm --> radius of circle
(3.14*25^2*38)cm3 = 74 575cm3 --> area of all circles (38 circles)
95 000cm3-74 575cm3 = 20425cm3 (a)

17*50cm*2 = 1700cm or 17m (b)

Hope this helps!

Q Pan : How did you get 34?

supposed to be 38...

[moon143]

wsywin2012:

moon143:

Last Question of Paper 2:


(34-4)/2 = 17
17*50cm*100cm = 85 000cm3
85 000cm3+100^2cm3 = 95 000cm3 --> area of footpath
50cm/2 = 25cm --> radius of circle
(3.14*25^2*38)cm3 = 74 575cm3 --> area of all circles (38 circles)
95 000cm3-74 575cm3 = 20425cm3 (a)

17*50cm*2 = 1700cm or 17m (b)

Hope this helps!

Q Pan : How did you get 34?

supposed to be 38...

Where u get 38 from? :? :?: