Q&A - PSLE Math

[lotto]

Bookwrappers:

MathIzzzFun:

[quote=\"Bookwrappers\"]Can someone answer this question?


7 ____ 7 ____2 ___ 7 = 5

Fill in blanks with +, -, x or /.

-, x, ÷

cheers

Thks thks. I waited for reply and thought nobody responding to me.[/quote]If u ask your question here, i don't think u can expect people to reply u that fast leh.
Btw will this type of question come out in the PSLE?

[Laura02]

MathIzzzFun:

Bookwrappers:

Can someone answer this question?


7 ____ 7 ____2 ___ 7 = 5

Fill in blanks with +, -, x or /.

-, x, ÷

cheers

If I give the answer as +, -, - will it also be marked as correct?

[dazzlego]

Laura02:

MathIzzzFun:

[quote=\"Bookwrappers\"]Can someone answer this question?


7 ____ 7 ____2 ___ 7 = 5

Fill in blanks with +, -, x or /.

-, x, ÷

cheers

If I give the answer as +, -, - will it also be marked as correct?[/quote]Yes, it is correct!
Unless the question states you can't use the same operation more than once

[superhappy]

Hi, pls help ;

1. 3/5 of Albert’s money is equal to 1/4 of Bernard’s money. The difference in Albert’s and Bernard’s money is equal to 1/2 of Caleb’s money. If Caleb has $210, what is the total amount of money the three boys have?

Thanks!

[weatherbee]

Need to draw the model but I don’t know how to draw here to show you. Basically, make the numerator the same. So 1/4 = 3/12. Albert has 5 units in total and Bernard has 12 units. Their difference is 12-5=7. Since 7 is 1/2 of what Caleb has, therefore Caleb has 14 units. So,


14 units —> $210
1 unit —> $210/14 = $15
Total: 31 units
31 units —> $15 X 31 = $465

[superhappy]

weatherbee:

Need to draw the model but I don't know how to draw here to show you. Basically, make the numerator the same. So 1/4 = 3/12. Albert has 5 units in total and Bernard has 12 units. Their difference is 12-5=7. Since 7 is 1/2 of what Caleb has, therefore Caleb has 14 units. So,


14 units ---> $210
1 unit ---> $210/14 = $15
Total: 31 units
31 units ---> $15 X 31 = $465

Oh.. Thanks!
I get it now after drawing the model.

[dazzlego]

superhappy:

weatherbee:

Need to draw the model but I don't know how to draw here to show you. Basically, make the numerator the same. So 1/4 = 3/12. Albert has 5 units in total and Bernard has 12 units. Their difference is 12-5=7. Since 7 is 1/2 of what Caleb has, therefore Caleb has 14 units. So,


14 units ---> $210
1 unit ---> $210/14 = $15
Total: 31 units
31 units ---> $15 X 31 = $465

Oh.. Thanks!
I get it now after drawing the model.

However it would not be a good choice to draw model every time you solve this. The figure given in the question might not always be convenient for you to draw the model.
Therefore in future, just remember that the key point to answer this question is to make the numerator to be the same units.

Cheers :celebrate:

[Bookwrappers]

Hi all, i hv a question to ask.


Danny needs to send a parcel which requires postage of $3.35 and $2.35 respectively.
He has 10 stamps each of denomination 26c, 32c, 50c and 80c. Find out the best combination of stamps that he could use so that he would overpay the least.

Ans:
For $3.35 parcel
26c - _______
32c - _______
50c - _______
80c - _______

For $2.35 parcel
26c - _______
32c - _______
50c - _______
80c - _______

Is this guess and check? Any other methods other than guess and check?

[MathIzzzFun]

Bookwrappers:

Hi all, i hv a question to ask.


Danny needs to send a parcel which requires postage of $3.35 and $2.35 respectively.
He has 10 stamps each of denomination 26c, 32c, 50c and 80c. Find out the best combination of stamps that he could use so that he would overpay the least.

Ans:
For $3.35 parcel
26c - _______
32c - _______
50c - _______
80c - _______

For $2.35 parcel
26c - _______
32c - _______
50c - _______
80c - _______

Is this guess and check? Any other methods other than guess and check?

There are multiple answers for this question.

note that all the stamp denomination is even, so the least amount to overpay is 0.01 ie total to $3.36 and $2.36

There are many combinations to get a \"6\" --> 6 x 26 or 3 x 32 or 1 x 26 or a combination of multiples of 32 and multiples of 26 (eg 2 x32 + 2 x 26)

One possible solution
For $3.35 parcel, $3.36 --> 3 x $0.32 + 3 x $0.80
For $2.35 parcel, $2.36 --> 6 x $0.26 + 1 x $0.80

If required least number of stamps:
For $ 3.35 parcel (6 stamps)
$3.36 --> 3 x $0.80+ 3 x $0.32 or (2 x $0.80 + 3 x $0.50 + 1 x $0.26)

For $ 2.35 parcel (4 stamps)
$2.36 --> 2 x $0.80 + 1 x $ 0.50 + 1 x $0.26


cheers.

[Robertpattinsonidle]

MathIzzzFun:

Bookwrappers:

Hi all, i hv a question to ask.


Danny needs to send a parcel which requires postage of $3.35 and $2.35 respectively.
He has 10 stamps each of denomination 26c, 32c, 50c and 80c. Find out the best combination of stamps that he could use so that he would overpay the least.

Ans:
For $3.35 parcel
26c - _______
32c - _______
50c - _______
80c - _______

For $2.35 parcel
26c - _______
32c - _______
50c - _______
80c - _______

Is this guess and check? Any other methods other than guess and check?

There are multiple answers for this question.

note that all the stamp denomination is even, so the least amount to overpay is 0.01 ie total to $3.36 and $2.36

There are many combinations to get a \"6\" --> 6 x 26 or 3 x 32 or 1 x 26 or a combination of multiples of 32 and multiples of 26 (eg 2 x32 + 2 x 26)

One possible solution
For $3.35 parcel, $3.36 --> 3 x $0.32 + 3 x $0.80
For $2.35 parcel, $2.36 --> 6 x $0.26 + 1 x $0.80

If required least number of stamps:
For $ 3.35 parcel (6 stamps)
$3.36 --> 3 x $0.80+ 3 x $0.32 or (2 x $0.80 + 3 x $0.50 + 1 x $0.26)

For $ 2.35 parcel (4 stamps)
$2.36 --> 2 x $0.80 + 1 x $ 0.50 + 1 x $0.26


cheers.

good answer...but is there a shorter answer...like using LCM?