Q&A - P5 Math

[heyhoe]

Hi quekcc,


Thanks for the answer

[Jamesbond]

tianzhu:

Jamesbond:

Pl help me solve (b) & (c).

Hi

The answers are

(b) 45 , follow this pattern (n+1)(n+2)/2

(c) pattern 13 , follow this (n+1)(n+1)

n ----- pattern number

Best wishes

Still my ds is not able to follow up...can u pl explain tianzhu....

[sokk]

Hi,


have a question to ask.

Ruby and Sandy had an equal number of chocolates. Each day, Ruby ate 14 chocolates and Sandy ate 21. When Sandy had 49 chocolates left, Ruby had 112 left.
How many chocolates did each of them have at first?

I solved this question by doing this->

Let the number of days by u.
49 + 21u = 112 + 14u
7u = 63
21u = 63x3 =189

49 + 189 = 238

Each of them have 238 chocolates at first.

But how can I teach a P5 student who has not learnt such method before? Is there another way of solving this question for a P5 student?


Appreciate anyone that can help me.
Thanks!

[tianzhu]

Jamesbond:

tianzhu:

[quote=\"Jamesbond\"]

Pl help me solve (b) & (c).

Hi

The answers are

(b) 45 , follow this pattern (n+1)(n+2)/2

(c) pattern 13 , follow this (n+1)(n+1)

n ----- pattern number

Best wishes

Still my ds is not able to follow up...can u pl explain tianzhu....[/quote]Hi

For (b), take the pattern number, in this case 9

Sorry, the sequence is n*(n+1)/2

(9)*(9+1)/2 ------- 9*10/2 --- 90/2 ------ 45

For total, the sequence is ( n+1)*(n+1)

196 ------ 14*14

Hence pattern number is 13.

I am going out. Please let me know if you need more information.I'll do it later

Best wishes

[sokk]

quekcc:

sokk:

Hi,


have a question to ask.

Ruby and Sandy had an equal number of chocolates. Each day, Ruby ate 14 chocolates and Sandy ate 21. When Sandy had 49 chocolates left, Ruby had 112 left.
How many chocolates did each of them have at first?

I solved this question by doing this->

Let the number of days by u.
49 + 21u = 112 + 14u
7u = 63
21u = 63x3 =189

49 + 189 = 238

Each of them have 238 chocolates at first.

But how can I teach a P5 student who has not learnt such method before? Is there another way of solving this question for a P5 student?


Appreciate anyone that can help me.
Thanks!

Each day, Sandy will consume 7 more than Ruby.

Now Sandy had consumed 112 - 49 = 63 more than Ruby, and that will work out to be 63/7 = 9 days.

So at first, Sandy will have 21 x 9 + 49 = 189 + 49 = 238.

Ruby will have the same number.

quekcc, thank you so much!

[snowball]

pr5 school hw, pls help to solve... :?:


Q1
Mr Tan painted 2/5 of his flat yesterday. Today, he continued painting and now he has painted 5/6 of his flat. How much of the flat did he paint today?

Q2
Kate has 3/5m of ribbon. She has 1/4m of ribbon less than Siti. How much metres of ribbon does Siti have?

Q3
Gopal had a coil of wire. He cut 2/7m away and used the remaining 1/6m to make a hook. Find the length of the original coil of wire.

Q4
Mary takes 5/6 h to rake the leaves. David takes 1/4h less than Mary to rake the leaves. Bala takes 1/6h longer than David. How long does Bala take to rake the leaves?

Anyone know whether i can find above solution in \"Onsponge assessment bk?

TIA

[tianzhu]

Jamesbond:

Still my ds is not able to follow up...can u pl explain tianzhu....

Hi

Hope this helps.

Best wishes

http://farm9.staticflickr.com/8211/8419326608_7950c213cc_z.jpg\">

[Jamesbond]

tianzhu:

Jamesbond:

Still my ds is not able to follow up...can u pl explain tianzhu....

Hi

Hope this helps.

Best wishes

http://farm9.staticflickr.com/8211/8419326608_7950c213cc_z.jpg\">

:thankyou: Very clear now.....

[Jamesbond]

http://i48.tinypic.com/23r7950.jpg\">

Pl help me in this.....

[Maths Hub]

Jamesbond:

http://i48.tinypic.com/23r7950.jpg\">

Pl help me in this.....

Hi,

Each division is 0.2. The pointer points between 2.4 to 2.6 and the answer should be 2.48.

Cheers.