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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Oracle:
      Hi Tianzhu/007, I have another question here:


      A badminton racket costs $24 more than a table tennis bat and $9 more than a basketball. Benedict bought 2 badminton rackets, 3 table tennis bats and 3 basketballs and paid a total of $279. How much did the basketball costs?

      Thank you very much.
      using MD..

      http://i50.tinypic.com/swboug.png\">

      cheers.

      1 Reply Last reply Reply Quote 0
      • S Offline
        snowball
        last edited by

        MathIzzzFun:
        snowball:

        [quote=\"snowball\"]pr5 school hw, pls help to solve... :?:


        Q1
        Mr Tan painted 2/5 of his flat yesterday. Today, he continued painting and now he has painted 5/6 of his flat. How much of the flat did he paint today?

        Q2
        Kate has 3/5m of ribbon. She has 1/4m of ribbon less than Siti. How much metres of ribbon does Siti have?

        Q3
        Gopal had a coil of wire. He cut 2/7m away and used the remaining 1/6m to make a hook. Find the length of the original coil of wire.

        Q4
        Mary takes 5/6 h to rake the leaves. David takes 1/4h less than Mary to rake the leaves. Bala takes 1/6h longer than David. How long does Bala take to rake the leaves?

        Anyone know whether i can find above solution in \"Onsponge assessment bk?

        TIA

        still :?: :?: :frustrated: :imdrowning: :imdrowning: 😢 😢
        anyone there to help me solve the above?

        Q1.
        painted today --> completed - painted yesterday
        = 5/6 - 2/5
        = 13/30

        Q2.
        Kate --> 3/5 m ribbon
        Siti --> 1/4 more --> 3/5 m + 1/4 m = 17/20 m

        Q3.
        Original length --> cut away + remaining
        = 2/7 m + 1/6m
        = 19/42 m

        Q4.
        Mary --> 5/6h
        David --> 1/4h less than Mary --> 5/6h - 1/4 = 7/12 h
        Bala --> 1/6 h more than David --> 7/12h + 1/6 h = 9/12h = 3/4 h

        cheers.[/quote]
        your solution is so amazing!!! :please:
        Looking from the angle of your solution, the question seems so much easier and 😓 simple !

        1 Reply Last reply Reply Quote 0
        • O Offline
          Oracle
          last edited by

          Thank you Snowball & MathIzzzFun!

          1 Reply Last reply Reply Quote 0
          • O Offline
            Oracle
            last edited by

            Hi Math Gurus,


            Please may I know how to solve this using the supposition method:
            Kumaran had 64 coins in his coin box. There were 20-cent coins and 50-cent coins. The total value of all the coins was $18.50. How many 20-cent coins and how many 50-cent coins were there? Thank you very much.

            1 Reply Last reply Reply Quote 0
            • O Offline
              Oracle
              last edited by

              One more?


              A sweet cost 15 cents and a packet of 8 similar sweets cost $1. Clement bought exactly 37 sweets. What was the least amount of money that Clement spent on the sweets?

              1 Reply Last reply Reply Quote 0
              • P Offline
                php
                last edited by

                Oracle:
                One more?


                A sweet cost 15 cents and a packet of 8 similar sweets cost $1. Clement bought exactly 37 sweets. What was the least amount of money that Clement spent on the sweets?
                4 packets -> 4 x 8 = 32 sweets ($1 x 4 = $4)
                5 sweets ($0.15 x 5 = $0.75)

                Total spent : $4.75

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  Oracle:
                  Hi Math Gurus,


                  Please may I know how to solve this using the supposition method:
                  Kumaran had 64 coins in his coin box. There were 20-cent coins and 50-cent coins. The total value of all the coins was $18.50. How many 20-cent coins and how many 50-cent coins were there? Thank you very much.
                  assume all are 50-cent coins --> 64 x $0.50 = $32
                  $32-$18.50 = $13.50 --> excess value assumed for 20-cent coins
                  Number of 20-cent coins = $13.50 /($0.50-$0.30) =45
                  number of 50-cent coins = 64 - 45 = 19

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • O Offline
                    Oracle
                    last edited by

                    Thanks PHP. So the last 5 sweets that do not form a packet need to be accounted for individually i.e., 15 cents each.

                    1 Reply Last reply Reply Quote 0
                    • O Offline
                      Oracle
                      last edited by

                      Here’s another:


                      During a mathematics test, Raymond scored 14 marks more than Krishnan and 7 marks more than Edison. Given that Raymond and Krishnan scored 73 marks more than Edison, what was Raymond’s score for the test?

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Oracle:
                        Here’s another:


                        During a mathematics test, Raymond scored 14 marks more than Krishnan and 7 marks more than Edison. Given that Raymond and Krishnan scored 73 marks more than Edison, what was Raymond’s score for the test?
                        Raymond scored 7 more than Edison
                        Raymond and Krishnan scored 73 more than Edison
                        so, Krisnan's score = 73-7=66
                        Raymond's score = 66 + 14 = 80
                        Edison's score = 80-7 =73


                        cheers.

                        1 Reply Last reply Reply Quote 0

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