Q&A - P5 Math
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Thank you Snowball & MathIzzzFun!
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Hi Math Gurus,
Please may I know how to solve this using the supposition method:
Kumaran had 64 coins in his coin box. There were 20-cent coins and 50-cent coins. The total value of all the coins was $18.50. How many 20-cent coins and how many 50-cent coins were there? Thank you very much. -
One more?
A sweet cost 15 cents and a packet of 8 similar sweets cost $1. Clement bought exactly 37 sweets. What was the least amount of money that Clement spent on the sweets? -
Oracle:
4 packets -> 4 x 8 = 32 sweets ($1 x 4 = $4)One more?
A sweet cost 15 cents and a packet of 8 similar sweets cost $1. Clement bought exactly 37 sweets. What was the least amount of money that Clement spent on the sweets?
5 sweets ($0.15 x 5 = $0.75)
Total spent : $4.75 -
Oracle:
assume all are 50-cent coins --> 64 x $0.50 = $32Hi Math Gurus,
Please may I know how to solve this using the supposition method:
Kumaran had 64 coins in his coin box. There were 20-cent coins and 50-cent coins. The total value of all the coins was $18.50. How many 20-cent coins and how many 50-cent coins were there? Thank you very much.
$32-$18.50 = $13.50 --> excess value assumed for 20-cent coins
Number of 20-cent coins = $13.50 /($0.50-$0.30) =45
number of 50-cent coins = 64 - 45 = 19
cheers. -
Thanks PHP. So the last 5 sweets that do not form a packet need to be accounted for individually i.e., 15 cents each.
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Here’s another:
During a mathematics test, Raymond scored 14 marks more than Krishnan and 7 marks more than Edison. Given that Raymond and Krishnan scored 73 marks more than Edison, what was Raymond’s score for the test? -
Oracle:
Raymond scored 7 more than EdisonHere’s another:
During a mathematics test, Raymond scored 14 marks more than Krishnan and 7 marks more than Edison. Given that Raymond and Krishnan scored 73 marks more than Edison, what was Raymond’s score for the test?
Raymond and Krishnan scored 73 more than Edison
so, Krisnan's score = 73-7=66
Raymond's score = 66 + 14 = 80
Edison's score = 80-7 =73
cheers. -
Oracle:
Thanks PHP. So the last 5 sweets that do not form a packet need to be accounted for individually i.e., 15 cents each.
yes, because the question stated he bought 37 sweets exactly. -
tayobus:
6+2=8There were twice as many red marbles as yellow marbles in a box.
When 2 red marbles were put into the box and 6 yellow marble were taken out, there was 3 times as many red marbles than yellow marble in the box.
What was the total number of marbles at 1st?
:?: :imdrowning: :thankyou:
8*4=32
32-2=30
30+6=36.
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