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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • O Offline
      Oracle
      last edited by

      Also, how should we approach a problem as such:


      Stephanie and Jolene shared a total of 88 stickers. Stephanie gave half of her stickers to Jolene. Jolene in return gave half of what she had to Stephanie. In the end, Stephanie had 40 more stickers than Jolene. How many stickers did Stephanie have at first?

      Thank you very much.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Oracle:
        Also, how should we approach a problem as such:


        Stephanie and Jolene shared a total of 88 stickers. Stephanie gave half of her stickers to Jolene. Jolene in return gave half of what she had to Stephanie. In the end, Stephanie had 40 more stickers than Jolene. How many stickers did Stephanie have at first?

        Thank you very much.
        Hi

        You may use \"Work backwards\"

        A quick check, the answer is 80 stickers for Stephanie.

        I'll work out the slide tomorrow.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • O Offline
          Oracle
          last edited by

          Thank you very much Tianzhu, know what, I am still now struggling with this question & it still eludes me. Am feeling spaced out now. Can’t think anymore. Will look at your slide when it becomes available & try to figure it out. Sigh … learning is no longer fun … poor children …


          Anyway, am very grateful for the help that I have received thus far.

          Am totally drained now. Good night Tianzhu, MathIzzzzFun (urm really?) and Jamesbond.

          1 Reply Last reply Reply Quote 0
          • O Offline
            Oracle
            last edited by

            Hey Quekcc, thanks. Yes indeed the same save for the names … thank you. Hope Tianzhu sees this then Tianzhu won’t need to take the trouble.

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            • O Offline
              Oracle
              last edited by

              Hi Quekcc, the number of bars used as representation is just an assumption to assist in deriving the steps that follow?


              Tianzhu, please may trouble you to show me how I can work backwards to derive the answer? I tried doing it based on Quekcc’s solution but still cannot see.

              Thank you very much.

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              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                Oracle:
                Hi Quekcc, the number of bars used as representation is just an assumption to assist in deriving the steps that follow?


                Tianzhu, please may trouble you to show me how I can work backwards to derive the answer? I tried doing it based on Quekcc's solution but still cannot see.

                Thank you very much.
                Stephanie and Jolene shared a total of 88 stickers. Stephanie gave half of her stickers to Jolene. Jolene in return gave half of what she had to Stephanie. In the end, Stephanie had 40 more stickers than Jolene. How many stickers did Stephanie have at first?

                you can work backwards .. start from the end...

                In the end, Stephanie had 40 more stickers than Jolene
                Jolene --> (88-40)/2 = 24 (*this represents 1/2 of what Jolene had before she gave to Stephanie)
                Stephanie --> 24 + 40 = 64

                Before Jolene gave half to Stephanie
                Jolene --> 24 + 24 = 48
                Stephanie --> 64 - 24 = 40 (this represents 1/2 of what Stephanie had at first)

                At first, Stephanie --> 40 + 40 = 80

                cheers.

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                • O Offline
                  Oracle
                  last edited by

                  Got it, MathIzzzFun, thank you.


                  Is it possible to solve this question at all:

                  The length of a rectangle is thrice its breadth. After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square. What is the area of the square after adjustment?

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                  • J Offline
                    Jamesbond
                    last edited by

                    Oracle:
                    Got it, MathIzzzFun, thank you.


                    Is it possible to solve this question at all:

                    The length of a rectangle is thrice its breadth. After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square. What is the area of the square after adjustment?
                    12+2=14
                    14/2=7
                    7+12=19
                    7*3=21
                    21-2=19
                    19*19=361....
                    Hope I am Correct 🕺

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                    • T Offline
                      tianzhu
                      last edited by

                      Oracle:

                      The length of a rectangle is thrice its breadth. After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square. What is the area of the square after adjustment?
                      Hi

                      It helps to draw a simple sketch.

                      Length of rectangle ----- 3u

                      Breadth of rectangle ------ 1u

                      After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square.

                      3u – 2 ------- 1u + 12

                      2u ------- 14

                      1u ------- 7

                      Side of square --------12+7 ------- 19

                      From here, you may work out the area (19*19).

                      Please refer to your PM for the WB solution.

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • E Offline
                        elisammom
                        last edited by

                        Hi pls help. This is the 2011 CA1 Nanhua paper

                        http://i46.tinypic.com/29bo9ro.jpg\">
                        TIA

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