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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • J Offline
      jieheng
      last edited by

      lost boy:
      Thank u jieheng šŸ™‚ can u pls help me another ques


      Solve the simultaneous equations.

      2x - 5y= 12
      3x - 2y = 7

      Thanks
      2x - 5y= 12 -----(1)
      3x - 2y = 7 -----(2)

      (1) x3 , 6x - 15y = 36 => 6x = 36 + 15y

      (2) x2 , 6x - 4y = 14 => 6x = 14 + 4y

      36 + 15y = 14 + 4y
      11y = - 22
      y = -2

      6x = 14 + 4y
      6x = 14 + 4(-2)
      x= 1

      1 Reply Last reply Reply Quote 0
      • L Offline
        lost boy
        last edited by

        Thank you Jieheng.

        1 Reply Last reply Reply Quote 0
        • L Offline
          lost boy
          last edited by

          Pls help me to solve sec 3 a math


          Use suitable substituitions to solve each of the following equations.

          a) 5^x + 5 = 30(5^x-1)

          b) 9^x + 10(3^x) = 3^x+2 + 12

          Thanks

          1 Reply Last reply Reply Quote 0
          • J Offline
            jieheng
            last edited by

            lost boy:
            Pls help me to solve sec 3 a math


            Use suitable substituitions to solve each of the following equations.

            a) 5^x + 5 = 30(5^x-1)

            b) 9^x + 10(3^x) = 3^x+2 + 12

            Thanks
            Pls note the difference between (5^x-1) = (5^x) - 1 and [5^(x-1)]


            a)

            5^x + 5 = 30[5^(x-1)]

            5^x + 5 = 30[(5^x)/5]

            5^x + 5 = 6(5^x)

            5(5^x) = 5

            5^x = 1

            x= 0

            b)

            9^x + 10(3^x) = 3^(x+2) + 12

            3^(2x) + 10(3^x) = 3^x * 9 + 12

            3^(2x) + 3^x - 12 = 0

            Let y = 3^x

            y^2 + y -12 = 0

            (y + 4)(y - 3) = 0

            y = -4 (reject) or y = 3

            when y =3

            3^x = 3

            x = 1

            1 Reply Last reply Reply Quote 0
            • S Offline
              S-H
              last edited by

              Can somebody help me with this question:-


              Differentiate the following, where a, b and c are constant, with respect to x.
              ax^2+bx+c / ax^2-bx-c

              Thank you very much.

              1 Reply Last reply Reply Quote 0
              • J Offline
                jieheng
                last edited by

                S-H:
                Can somebody help me with this question:-


                Differentiate the following, where a, b and c are constant, with respect to x.
                ax^2+bx+c / ax^2-bx-c

                Thank you very much.
                http://i48.tinypic.com/347ywsw.jpg\">

                1 Reply Last reply Reply Quote 0
                • S Offline
                  S-H
                  last edited by

                  jieheng:
                  S-H:

                  Can somebody help me with this question:-


                  Differentiate the following, where a, b and c are constant, with respect to x.
                  ax^2+bx+c / ax^2-bx-c

                  Thank you very much.

                  http://i48.tinypic.com/347ywsw.jpg\">

                  :thankyou:

                  1 Reply Last reply Reply Quote 0
                  • L Offline
                    lost boy
                    last edited by

                    Thanks Jieheng .

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      KiausuLormee
                      last edited by

                      Hi Jieheng


                      Can help me to solve this question:

                      Showing your working clearly, Express 0.368 as a fraction in its lowest terms.
                      Thanks

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        jieheng
                        last edited by

                        KiausuLormee:
                        Hi Jieheng


                        Can help me to solve this question:

                        Showing your working clearly, Express 0.368 as a fraction in its lowest terms.
                        Thanks
                        0.368
                        =368/1000
                        =46/125

                        1 Reply Last reply Reply Quote 0

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