Logo
    • Education
      • Pre-School
      • Primary Schools Directory
      • Primary Schools Articles
      • P1 Registration
      • DSA
      • PSLE
      • Secondary
      • Tertiary
      • Special Needs
    • Lifestyle
      • Well-being
    • Activities
      • Events
    • Enrichment & Services
      • Find A Service Provider
      • Enrichment Articles
      • Enrichment Services
      • Tuition Centre/Private Tutor
      • Infant Care/ Childcare / Student Care Centre
      • Kindergarten/Preschool
      • Private Institutions and International Schools
      • Special Needs
      • Indoor & Outdoor Playgrounds
      • Paediatrics
      • Neonatal Care
    • Forum
    • ASKQ
    • Register
    • Login

    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
    2.8k Posts 273 Posters 1.2m Views 1 Watching
    Loading More Posts
    • Oldest to Newest
    • Newest to Oldest
    • Most Votes
    Reply
    • Reply as topic
    Log in to reply
    This topic has been deleted. Only users with topic management privileges can see it.
    • C Offline
      ChewingPencilLine
      last edited by

      Jamesbond:
      ChewingPencilLine:

      [quote]2. Mary spent $270 on a necklace. She spent 1/7 of her money on a dress. She then had 3/8 of her money left. How much money did she have at first?


      It might be good to draw the model for this question (if you have trouble visualizing) although I am not going to provide one in the following solution.

      After spending $270, Mary has some money left. Let us call that the remainder.
      She then spent 1/7 of the remainder on a dress.
      Thereafter, she is left with 6/7 of the remainder.

      Therefore, 6/7 of remainder = 3/8 of her total money
      For reasonable comparison, you need the unit size to be the same!

      As such, find the lowest common multiple of 6 and 3. Then make the numerator the same (same amount represented by the same number of units -> units are of the same size), i.e.

      6/7 of remainder = 6/16 of her total money

      As such, her total money can be represented using 16 units. The remainder is then represented using 7 units.

      The money spent on the necklace is hence represented by
      16 - 7 = 9 units

      9 units = $270
      1 unit = $270 / 9 = $30
      16 units = $30 x 16 = $480

      Hi, Sorry to interrupt..She only spent 1/7 of the money on the dress and not the remainder. So the steps are

      1/7=8/56
      3/8=21/56
      21/56+8/56=29/56
      56-29=27
      270/27=10
      56*10=560
      Correct me if I am wrong.[/quote]You are quite right in your workings and correction, thank you! Can't believe I actually misread the question! My apologies and thank you!

      1 Reply Last reply Reply Quote 0
      • C Offline
        chloecube
        last edited by

        Jim and Andy had 522 cards. Jim gave 4/7 of his cards to Andy. Andy then gave 2/5 of the total number of cards he had to Jim. In the end, each of them had the same Nos of card. How many cards did each of them have at first?

        1 Reply Last reply Reply Quote 0
        • J Offline
          Jamesbond
          last edited by

          http://i48.tinypic.com/24biv4n.jpg\">


          Pl help.

          1 Reply Last reply Reply Quote 0
          • C Offline
            ChewingPencilLine
            last edited by

            chloecube:
            Jim and Andy had 522 cards. Jim gave 4/7 of his cards to Andy. Andy then gave 2/5 of the total number of cards he had to Jim. In the end, each of them had the same Nos of card. How many cards did each of them have at first?

            Total number of cards does not change so Jim and Andy each have
            522 / 2 = 261 cards at the end.

            Working backwards...
            This is after Andy gave away 2/5 of his total number of cards to Jim, which means he was left with 1 - 2/5 = 3/5 of his cards.

            Therefore, before giving away some cards to Jim, Andy had
            261 / 3 * 5 = 435 cards
            and Jim had 522 - 435 = 87 cards.

            This is after Jim gave 4/7 of his cards to Andy.
            Similarly, 1 - 4/7 = 3/7

            Therefore, before giving away some cards to Andy, Jim had
            87 / 3 * 7 = 203 cards

            Hence, the final answer is as follows:

            Jim had 203 cards at first while Andy had 522 - 203 = 319 cards at first.

            1 Reply Last reply Reply Quote 0
            • C Offline
              ChewingPencilLine
              last edited by

              Jamesbond:
              http://i48.tinypic.com/24biv4n.jpg\">


              Pl help.
              Unshaded area = half the area of a square + half the area of 3 squares
              (the bottom row of 3 squares form a rectangle which is half shaded)

              Since 1 square is 16 x 16 = 256 cm square,
              The total unshaded area is 1/2 x 256 + 1/2 x 3 x 256 = 2 x 256 = 512 cm square.

              1 Reply Last reply Reply Quote 0
              • C Offline
                chloecube
                last edited by

                I see, thks šŸ™‚

                1 Reply Last reply Reply Quote 0
                • O Offline
                  Oracle
                  last edited by

                  Thanks Tianzhu but i just need to understand why Wee Teck is given 3 units because the question says Robert paid 1/3 of the amount paid by Henry AND Wee Teck. By using 3 units to represent Wee Teck, we would be assuming that both Wee Teck and Henry paid equal amount which might mot be the case.


                  Your thoughts?

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    Oracle:
                    Thanks Tianzhu but i just need to understand why Wee Teck is given 3 units because the question says Robert paid 1/3 of the amount paid by Henry AND Wee Teck. By using 3 units to represent Wee Teck, we would be assuming that both Wee Teck and Henry paid equal amount which might mot be the case.


                    Your thoughts?
                    Hi

                    Please read your PM.

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      carol73
                      last edited by

                      hi


                      1)An egg-seller had some chicken eggs and duck eggs. He had 96 more chicken eggs than duck eggs. After he had sold 3/4 of the chicken eggs and 2/3 of the duck eggs, he found that he had 150 eggs left. Find the total number of eggs he had at first?

                      2)Miss Lee baked 24 more chocolate muffins than banana muffins. After she gave away 1/6 of the chocolate muffins and 3/8 of the banana muffins, she was left with 35 more chocolate muffins than banana muffins. How many chocolate muffins did she bake at first?

                      1 Reply Last reply Reply Quote 0
                      • C Offline
                        carol73
                        last edited by

                        hi

                        can you explain this step

                        Therefore, before giving away some cards to Jim, Andy had
                        261 / 3 * 5 = 435 cards
                        and Jim had 522 - 435 = 87 cards.

                        why 261 / 3 * 5?

                        ChewingPencilLine:
                        chloecube:

                        Jim and Andy had 522 cards. Jim gave 4/7 of his cards to Andy. Andy then gave 2/5 of the total number of cards he had to Jim. In the end, each of them had the same Nos of card. How many cards did each of them have at first?

                        Total number of cards does not change so Jim and Andy each have
                        522 / 2 = 261 cards at the end.

                        Working backwards...
                        This is after Andy gave away 2/5 of his total number of cards to Jim, which means he was left with 1 - 2/5 = 3/5 of his cards.

                        Therefore, before giving away some cards to Jim, Andy had
                        261 / 3 * 5 = 435 cards
                        and Jim had 522 - 435 = 87 cards.

                        This is after Jim gave 4/7 of his cards to Andy.
                        Similarly, 1 - 4/7 = 3/7

                        Therefore, before giving away some cards to Andy, Jim had
                        87 / 3 * 7 = 203 cards

                        Hence, the final answer is as follows:

                        Jim had 203 cards at first while Andy had 522 - 203 = 319 cards at first.

                        1 Reply Last reply Reply Quote 0

                        Hello! It looks like you're interested in this conversation, but you don't have an account yet.

                        Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.

                        With your input, this post could be even better šŸ’—

                        Register Login
                        • 1
                        • 2
                        • 216
                        • 217
                        • 218
                        • 219
                        • 220
                        • 281
                        • 282
                        • 218 / 282
                        • First post
                          Last post



                        Online Users

                        Statistics

                        1

                        Online

                        211.3k

                        Users

                        34.5k

                        Topics

                        1.8m

                        Posts
                        Popular Topics
                        New to the KiasuParents forum? Tips and Tricks!
                        P1 Registration 2027 Changes
                        DSA Discussions and Strategies
                        PSLE Discussions and Strategies
                        How much do you spend on the kids' tuition/enrichments?
                        SkillsFuture course recommendations

                          About Us Contact Us forum Terms of Service Privacy Policy