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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • ozoraO Offline
      ozora
      last edited by

      Need help in speed question.

      The distance between town A and town B is 180km.
      A van travelled from Town A at 1130am to town B.
      1/2h later, a car travelled from town A to town B at an average speed of 75km/h.
      The car overtook the van and reached town B first. The van reached town B at 2.30pm.
      A) at what time did the car overtake the van?
      B) how far away was the van from town B when the car reached town B?

      1 Reply Last reply Reply Quote 0
      • O Offline
        Oldschool
        last edited by

        ozora:
        Need help in speed question.

        The distance between town A and town B is 180km.
        A van travelled from Town A at 1130am to town B.
        1/2h later, a car travelled from town A to town B at an average speed of 75km/h.
        The car overtook the van and reached town B first. The van reached town B at 2.30pm.
        A) at what time did the car overtake the van?
        B) how far away was the van from town B when the car reached town B?
        Hi,

        Speed of Van = 180 / 3 = 60km/h

        a) At the time of overtaking, both Van and Car have travelled the same distance,

        60(t) = 75 (t - 1/2)
        t = 2.5 hrs

        So, the time is 1400 hrs or 2pm when the Car overtakes the Van.

        b) Time taken for Car to reach B = 180 / 75 = 2.4hrs

        In (2.4+0.5) hrs, the Van travelled = 60 x (2.9) = 174km

        Thus, the Van is 180-174=6 km away from B


        Note: My error for 2nd part, instead of 2.4, it should be 2.9hrs


        Regards

        1 Reply Last reply Reply Quote 0
        • ozoraO Offline
          ozora
          last edited by

          Oldschool:
          ozora:

          Need help in speed question.

          The distance between town A and town B is 180km.
          A van travelled from Town A at 1130am to town B.
          1/2h later, a car travelled from town A to town B at an average speed of 75km/h.
          The car overtook the van and reached town B first. The van reached town B at 2.30pm.
          A) at what time did the car overtake the van?
          B) how far away was the van from town B when the car reached town B?

          Hi,

          Speed of Van = 180 / 3 = 60km/h

          a) At the time of overtaking, both Van and Car have travelled the same distance,

          60(t) = 75 (t - 1/2)
          t = 2.5 hrs

          So, the time is 1400 hrs or 2pm when the Car overtakes the Van.

          b) Time taken for Car to reach B = 180 / 75 = 2.4hrs

          In 2.4hrs, the Van travelled = 60 x 2.4 = 144km

          Thus, the Van is 180-144=36 km away from B

          Regards

          thanks got it correct the first part but should the answer in b) 6 km as the van has travelled extra of 0.5h

          1 Reply Last reply Reply Quote 0
          • O Offline
            Oldschool
            last edited by

            ozora:
            Oldschool:

            [quote=\"ozora\"]Need help in speed question.

            The distance between town A and town B is 180km.
            A van travelled from Town A at 1130am to town B.
            1/2h later, a car travelled from town A to town B at an average speed of 75km/h.
            The car overtook the van and reached town B first. The van reached town B at 2.30pm.
            A) at what time did the car overtake the van?
            B) how far away was the van from town B when the car reached town B?

            Hi,

            Speed of Van = 180 / 3 = 60km/h

            a) At the time of overtaking, both Van and Car have travelled the same distance,

            60(t) = 75 (t - 1/2)
            t = 2.5 hrs

            So, the time is 1400 hrs or 2pm when the Car overtakes the Van.

            b) Time taken for Car to reach B = 180 / 75 = 2.4hrs

            In 2.4hrs, the Van travelled = 60 x 2.4 = 144km

            Thus, the Van is 180-144=36 km away from B

            Regards

            thanks got it correct the first part but should the answer in b) 6 km as the van has travelled extra of 0.5h[/quote]
            Hi,

            Yep, for Part (B), you are correct.

            Thanks

            1 Reply Last reply Reply Quote 0
            • ozoraO Offline
              ozora
              last edited by

              Oldschool:
              ozora:

              Need help in speed question.

              The distance between town A and town B is 180km.
              A van travelled from Town A at 1130am to town B.
              1/2h later, a car travelled from town A to town B at an average speed of 75km/h.
              The car overtook the van and reached town B first. The van reached town B at 2.30pm.
              A) at what time did the car overtake the van?
              B) how far away was the van from town B when the car reached town B?

              Hi,

              Speed of Van = 180 / 3 = 60km/h

              a) At the time of overtaking, both Van and Car have travelled the same distance,

              60(t) = 75 (t - 1/2)
              t = 2.5 hrs

              So, the time is 1400 hrs or 2pm when the Car overtakes the Van.

              b) Time taken for Car to reach B = 180 / 75 = 2.4hrs

              In (2.4+0.5) hrs, the Van travelled = 60 x (2.9) = 174km

              Thus, the Van is 180-174=6 km away from B


              Note: My error for 2nd part, instead of 2.4, it should be 2.9hrs


              Regards

              thanks

              1 Reply Last reply Reply Quote 0
              • Y Offline
                YumYum
                last edited by

                Hi, can someone pls help with this Qn? thanks!


                http://i34.tinypic.com/121fyih.jpg\">

                1 Reply Last reply Reply Quote 0
                • Y Offline
                  YumYum
                  last edited by

                  Hi, one more Qn:


                  Derrick and John shared a sum of money.
                  Derrick received 2/7 of the sum of money.
                  Both of them spent part of their money and saved the rest.
                  The amount of money Derrick spent was 3/5 the amount he saved.
                  The amount of money John spent was 1/9 the amount he saved.
                  Express the amount of money John spent as a ratio of the amount John saved. thks!

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    YumYum:
                    Hi, can someone pls help with this Qn? thanks!


                    http://i34.tinypic.com/121fyih.jpg\">

                    unshaded area = 1/3 area of original rectangle.
                    shaded area = 1/3 area of original rectangle = 28 cm2

                    area of original rectangle = 84 cm2

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      YumYum:
                      Hi, one more Qn:


                      Derrick and John shared a sum of money.
                      Derrick received 2/7 of the sum of money.
                      Both of them spent part of their money and saved the rest.
                      The amount of money Derrick spent was 3/5 the amount he saved.
                      The amount of money John spent was 1/9 the amount he saved.
                      Express the amount of money John spent as a ratio of the amount John saved.
                      thks!
                      pls check the last sentence --- I think it is probably
                      Express the amount of money Derrick spent as a ratio of the amount John saved.

                      or

                      Express the amount of money John spent as a ratio of the amount Derrick saved..

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • Y Offline
                        YumYum
                        last edited by

                        MathIzzzFun:
                        YumYum:

                        Hi, one more Qn:


                        Derrick and John shared a sum of money.
                        Derrick received 2/7 of the sum of money.
                        Both of them spent part of their money and saved the rest.
                        The amount of money Derrick spent was 3/5 the amount he saved.
                        The amount of money John spent was 1/9 the amount he saved.
                        Express the amount of money John spent as a ratio of the amount John saved.
                        thks!

                        pls check the last sentence --- I think it is probably
                        Express the amount of money Derrick spent as a ratio of the amount John saved.

                        or

                        Express the amount of money John spent as a ratio of the amount Derrick saved..

                        cheers.


                        Hi, apologies. My mistake, the last sentence is \"Express the amount of money Derrick spent as a ratio of the amount John saved.\"

                        1 Reply Last reply Reply Quote 0

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