Q&A - P5 Math

[babies]

Anyone to help me in the questions?


1/3 of the amount of money Oliver has is the same as 2/3 of the amount of money Kayla has.
a) If Oliver has $60 more than Kayla, how much money does Oliver have?
b) If Oliver has $120 more than Kayla, how much money does Oliver have than Kayla?


Kamal bought 143 red markers and black markers. After he gave the same number of red markers and black markers, he was left with 3/7 of the red markers and 1/3 of the black markers. How many black markers did he have left?

Thanks in advance!

[MathIzzzFun]

2632parent:

Can anyone help me with the following questions,


1) A container when 5/6 filled with water weighs 454kg. When it is 1/4 filled with water, it weighs 321kg. What is the mass of the container?

Thank you

similar questions -
When a bucket was 1/7 filled with water, its weight was 5kg. The weight of the bucket was 23kg when water was filled to its brim. What was the weight of the empty bucket?
- http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=67&t=25121&start=1480


http://i44.tinypic.com/33kymaa.png\">

cheers.

[MathIzzzFun]

babies:

Anyone to help me in the questions?


1/3 of the amount of money Oliver has is the same as 2/3 of the amount of money Kayla has.
a) If Oliver has $60 more than Kayla, how much money does Oliver have?
b) If Oliver has $120 more than Kayla, how much money does Oliver have than Kayla?

Thanks in advance!

Using equal fraction/equalizing numerator method:

1/3 of Oliver's money = 2/3 of Kayla's money
2/6 of Oliver's money = 2/3 of Kayla's money

Oliver's money --> 6 units
Kayla's money --> 3 units

a) If Oliver has $60 more than Kayla,
6 units - 3 units = 3 units --> $60
1 unit --> $20

Oliver's money --> 6 x $20 = $120

b) If Oliver has $120 more than Kayla,
6 units - 3 units = 3 units --> $120
1 unit --> $40

Oliver's money --> 6 x $40 = $ 240

cheers.

[MathIzzzFun]

babies:

Anyone to help me in the questions?


Kamal bought 143 red markers and black markers. After he gave away the same number of red markers and black markers, he was left with 3/7 of the red markers and 1/3 of the black markers. How many black markers did he have left?

Thanks in advance!

same number of red and black markers were given away, so

4/7 of red markers = 2/3 of black markers
4/7 of red markers = 4/6 of black markers

red markers --> 7 units
black markers --> 6 units
Total number of markers --> 13 units

13 units --> 143
1 unit = 11

Number of black markers --> 66
Number of black markers left --> 1/3 x 66 = 22

cheers.

[Lizzyho]

Draw a model with 10 equal parts.


1/5 of the beads were sold on the second day=2 parts

3/10 of the cards (I think you meant beads) were sold on the third day=3 parts

ratio of the beads sold on the first day to the total number of beads sold on the next 3 days was 1:7=total beads should be divided into 8 (1+7) parts. Thus we need to share out the original 10 parts into 8 parts=10/8=1 1/4. This means that for each of the original part, you need to further divide into 4 smaller parts. Thus day 1=1original part+1small part (sorry I don’t know how to draw out on the computer, hope you understand)

number of beads sold on the fourth day was 14 more than that sold on the second day=remaining parts=3 original parts+3small parts
Thus 1 original part+3small parts=7small parts=14 beads. 1 small part=2 beads.

a) Total number of beads in the box=2x4x10=80 beads
b) No. of beads sold on day 4=16+14=30 beads
No. of beads sold on day 1=4+2=6
24 more beads were sold on day 4 than day 1

Think I’m correct, hope you understand

[MathIzzzFun]

marstolive:

Hi appreciate your assistance on the following question.



A box of beads was sold out in 4 days. 1/5 of the beads were sold on the second day. 3/10 of the beads were sold on the third day. The number of beads sold on the fourth day was 14 more than that sold on the second day. The ratio of the beads sold on the first day to the total number of beads sold on the next 3 days was 1:7.

a) What was the total number of beads in the box?
b) how many more beads were sold on day 4 than on day 1?

:nailbite:

using fractions:

Day 2 --> 1/5 of beads = 8/40 of beads
Day 3 --> 3/10 of beads =12/40 of beads
Day 4 --> 8/40 of beads + 14 beads
Day 2+Day3+Day 4 --> 28/40 of beads + 14 beads

Day 1 --> 1/8 of beads = 5/40 of beads

Day 1 + Day 2+Day3+Day 4
= 28/40 of beads + 14 beads + 5/40 of beads
= 33/40 of beads + 14 beads

7/40 of beads --> 14 beads
1/40 of beads --> 2 beads
a) Total number of beads --> 40 x 2 = 80 beads
b) Day 4 --> 8 x 2 + 14 = 30 beads
Day 1 --> 5 x 2 = 10 beads

30 beads - 10 beads = 20 beads --> 20 more bead were sold on Day 4 than on Day 1.

cheers.

[MathIzzzFun]

marstolive:

1) Tim,Dan and Henry were given some marbles.

Tim received 1/6 of the marbles.
Dan 's share of the marbles was 6/11 of Henry.
Tim and Dan received 94 marbles altogether.
a) How many marbles were given to Henry?
b) How many marbles did the three of them receive?


Can someone help to solve the above using units/ratio method?
Thanks in advance n in a milion.

Tim : total = 1: 6 --> Tim : Dan + Henry = 1 : 5
Dan : Henry = 6 : 11 --> Dan : Henry : Dan + Henry = 6 : 11 : 17

Dan+Henry : Tim : Dan : Henry --> 85u : 17u : 30u : 55u
Tim + Dan --> 47u --- 94 marbles
1u --> 2 marbles

a) Henry --> 110 marbles
b) total --> 110 marbles + 94 marble = 204 marbles

cheers.

[babies]

Thank you MathIzzzFun!

[pensiveowl]

Pls help with this question thanks:


The ratio of the number of donuts in Box A to the number of donuts in Box B was 3 : 2. After 4 donuts had been removed from Box A, the number of donuts became the same in both boxes. How many donuts were there in Box B?

[php]

pensiveowl:

Pls help with this question thanks:


The ratio of the number of donuts in Box A to the number of donuts in Box B was 3 : 2. After 4 donuts had been removed from Box A, the number of donuts became the same in both boxes. How many donuts were there in Box B?

3u - 4 -> 2u
1u -> 4

Box B has 2u (2 x 4) = 8 donuts