Q&A - P4 Math

[SAHM Chew]

Mr George raises pigs and chickens on his farm. The total number of legs of pigs and chickens is 1126. The number of pigs is 488 less than the number of chickens. How many chickens are there on his farm?


Please help to solve. Thanks.

[PapayaDad]

Assume 1 pig and 489 chicken

Pig legs = 4
Chicken legs = 489 x 2 = 978
Total legs = 982 ; not correct need 1126 - 982 = 144 more legs

If we add 1 pig, we need to and 1 chicken (to maintain "pigs is 488 less than the number of chickens") ; net result is 6 legs being added

144/6 = 24

So we need to add 24 pigs into out initial assumption ie. there are 25 pigs
so chicken is 25 + 488 = 513

Check
25 pigs = 100 legs
513 chicken = 1026
total is 1126…correct

[SAHM Chew]

Always21:

Please help me with this question



A gardener had 1/2 a bag of soil. He used 5/8 of it to fill up a pot. What fraction of the soil was left?

Thank you in advance.

Is the ans 3/16?

[The Right Equation]

SAHM Chew:

Always21:

Please help me with this question



A gardener had 1/2 a bag of soil. He used 5/8 of it to fill up a pot. What fraction of the soil was left?

Thank you in advance.

Is the ans 3/16?

yes it is.

[shurley197323]

HI, can anyone help these 2 questions ?


(1) 6,24,60,120,210_________,________.

(2) Mr Tan start to read a story book from Pade 13 until he completed the whole book. If there were 66 pages altogether, what was the sum of all the no is the odd-no pages he need ?

Thanks

[tianzhu]

shurley197323:

HI, can anyone help these 2 questions ?


(1) 6,24,60,120,210_________,________.

Hi

Hope this helps.

6,24,60,120,210,336,504

1*2*3 ------ 6
2*3*4 ------ 24
3*4*5 ------ 60
4*5*6 ------ 120
5*6*7 ------ 210

continue and you you'll get 336 and 504

Best wishes

[shurley197323]

Thanks Tianzhu for your help.

[tianzhu]

shurley197323:

(2) Mr Tan start to read a story book from Pade 13 until he completed the whole book. If there were 66 pages altogether, what was the sum of all the no is the odd-no pages he need ?

Thanks

Hi

We want to find the sum of the number of odd pages he read, not the total number of pages in the book.

Find the sum of the number of odd pages from page 1 to page 79 (13+66) which is equal to 1600 (square of 40)

From here, minus, the sum of the number of odd pages from page 1 to page 11 (6 pages) which is equal to 36

The sum -------1600 - 36 ------ 1564

Best wishes

[PapayaDad]

there were 66 pages altogether


should count from page 1 to page 65 only? and then minus page 1 to page 9.

[Oldschool]

BTW, since Mr Tan start reading from Page 13, then Page 11 should also be minus away.


Regards