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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • T Offline
      tianzhu
      last edited by

      shurley197323:
      HI, can anyone help these 2 questions ?


      (1) 6,24,60,120,210_________,________.
      Hi

      Hope this helps.

      6,24,60,120,210,336,504

      1*2*3 ------ 6
      2*3*4 ------ 24
      3*4*5 ------ 60
      4*5*6 ------ 120
      5*6*7 ------ 210

      continue and you you'll get 336 and 504

      Best wishes

      1 Reply Last reply Reply Quote 0
      • S Offline
        shurley197323
        last edited by

        Thanks Tianzhu for your help.

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          shurley197323:

          (2) Mr Tan start to read a story book from Pade 13 until he completed the whole book. If there were 66 pages altogether, what was the sum of all the no is the odd-no pages he need ?

          Thanks
          Hi

          We want to find the sum of the number of odd pages he read, not the total number of pages in the book.

          Find the sum of the number of odd pages from page 1 to page 79 (13+66) which is equal to 1600 (square of 40)

          From here, minus, the sum of the number of odd pages from page 1 to page 11 (6 pages) which is equal to 36

          The sum -------1600 - 36 ------ 1564

          Best wishes

          1 Reply Last reply Reply Quote 0
          • P Offline
            PapayaDad
            last edited by

            there were 66 pages altogether


            should count from page 1 to page 65 only? and then minus page 1 to page 9.

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            • O Offline
              Oldschool
              last edited by

              BTW, since Mr Tan start reading from Page 13, then Page 11 should also be minus away.


              Regards

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                Oldschool:
                BTW, since Mr Tan start reading from Page 13, then Page 11 should also be minus away.


                Regards
                Hi

                Thanks, I missed out 11.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • S Offline
                  shurley197323
                  last edited by

                  tianzhu:
                  shurley197323:


                  (2) Mr Tan start to read a story book from Pade 13 until he completed the whole book. If there were 66 pages altogether, what was the sum of all the no is the odd-no pages he need ?

                  Thanks

                  Hi

                  We want to find the sum of the number of odd pages he read, not the total number of pages in the book.

                  Find the sum of the number of odd pages from page 1 to page 79 (13+66) which is equal to 1600 (square of 40)

                  From here, minus, the sum of the number of odd pages from page 1 to page 11 (6 pages) which is equal to 36

                  The sum -------1600 - 36 ------ 1564

                  Best wishes

                  Thank you & Sorry, Tianzhu,
                  I still can't get ( 1600 ) & (36) ?

                  Can help to show me step by step ?

                  Thks in advance.

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    shurley197323:
                    [Thank you & Sorry, Tianzhu,

                    I still can't get ( 1600 ) & (36) ?

                    Can help to show me step by step ?

                    Thks in advance.
                    Hi

                    From 1 to 79, there are 40 number of odd numbers.

                    sum of odd numbers from 1 to nth term ------ n*n (n square)

                    40*40 ----- 1600

                    36 is the sum of odd numbers from 1 to 11 (1+3+5+7+9+11)

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      Always21
                      last edited by

                      Pls help with this


                      There are three bottles of beads. The second bottle contains 5/7 of the number of beads in the first bottle. The third bottle contains 1/2 of the number of beads in the second bottle. The difference between the number of beads in the first and third bottle is 27. What is the sum of the beads in the three bottles?

                      Really need help

                      Thanks in advance.

                      1 Reply Last reply Reply Quote 0
                      • P Offline
                        PapayaDad
                        last edited by

                        A=14u

                        B=10u
                        C=5u
                        Total=29u

                        A-C=27
                        14u-5u=27
                        9u=27
                        u=3
                        Total=29x3= 87

                        1 Reply Last reply Reply Quote 0

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