Q&A - P5 Math
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Siti knitted 1 2/5m of a scarf,on Monday,she knitted 1/4 of the length.on Tuesday, she knitted 45cm more. What fraction of the scarf was knitted altogether?
answer is 4/7.
anyone can help? Thks -
smartmummy:
Funds raised by Class 5A --> 2/5 of total ... (5A --> 1 unit, 5B & 5C --> 3 units, total 5 units)Pls help the following qns - no urgent.Thanks
Q3)During a fund raising project, class 5A raised 2/3 as much money as the total amount raised by classes 5B&5C.Class 5B raised 1/5 as much money as the total amount raised by class 5A and 5C.
a)What fraction of the funds was raised by class 5A?
b)Class 5B raised $104 less than class 5C.How much money did class 5C raise?
TIA.
Funds raised by Class 5B --> 1/6 of total ... (5B --> 1 part, 5A & 5C --> 5 parts, total 6 parts)
1 - 2/5 - 1/6 = 13/30
Funds raised by Class 5C --> 13/30 of total
13/30 total - 1/6 of total = 8/30 of total --> $104
1/30 of total --> $13
Funds raised by Class 5C --> 13 x $13 = $ 169
cheers. -
chloecube:
1 2/5 m = 1.4m = 140 cmSiti knitted 1 2/5m of a scarf,on Monday,she knitted 1/4 of the length.on Tuesday, she knitted 45cm more. What fraction of the scarf was knitted altogether?
answer is 4/7.
anyone can help? Thks
1/4 of 140 cm = 35 cm
Total knitted = 35 cm + 45 cm = 80 cm
Fraction of scarf knitted --> 80/140 = 4/7
cheers. -
smartmummy:
Plums --> 20 unitsPls help the following qns - no urgent.Thanks
Q4) There were 20 more pears than plums at a fruit stall.After 1/5 of the pears and 3/10 of the plums were sold, there were 46 pears and plums left.How many plums were left over.
TIA.
Pears --> 20 units + 20
Left:
Plums --> 7/10 x 20 units = 14 units
Pears --> 4/5 x (20 units + 20) = 16 units + 16
Total of 46 pears and plums left, so
14 units + 16 units + 16 = 46
1 unit --> 1
Plums left --> 14
cheers. -
MathIzzzFun:
:thankyou: so much for ur help. Appreciate much!!
Plums --> 20 unitssmartmummy:
Pls help the following qns - no urgent.Thanks
Q4) There were 20 more pears than plums at a fruit stall.After 1/5 of the pears and 3/10 of the plums were sold, there were 46 pears and plums left.How many plums were left over.
TIA.
Pears --> 20 units + 20
Left:
Plums --> 7/10 x 20 units = 14 units
Pears --> 4/5 x (20 units + 20) = 16 units + 16
Total of 46 pears and plums left, so
14 units + 16 units + 16 = 46
1 unit --> 1
Plums left --> 14
cheers.
Why plums---> 20 units, can we assume plums--->10 units, do we find common multiple of 5 & 10?Thanks -
smartmummy:
:thankyou: so much for ur help. Appreciate much!!
Plums --> 20 unitsMathIzzzFun:
[quote=\"smartmummy\"]Pls help the following qns - no urgent.Thanks
Q4) There were 20 more pears than plums at a fruit stall.After 1/5 of the pears and 3/10 of the plums were sold, there were 46 pears and plums left.How many plums were left over.
TIA.
Pears --> 20 units + 20
Left:
Plums --> 7/10 x 20 units = 14 units
Pears --> 4/5 x (20 units + 20) = 16 units + 16
Total of 46 pears and plums left, so
14 units + 16 units + 16 = 46
1 unit --> 1
Plums left --> 14
cheers.
Why plums---> 20 units, can we assume plums--->10 units, do we find common multiple of 5 & 10?Thanks[/quote]yes, you can assume 10 units... I chose 20 units for easier calculation as there are 20 more pears.
cheers. -
MathIzzzFun:
How to find 42u : 35u --- total --> 77u,guess and check for G=G.swimmers + G.non swimmers, B=B.swimmers +B.non swimmers, or any short-cut? :thankyou:
Total girls : boys = 6 : 5 --> 42u : 35u --- total --> 77usmartmummy:
Pls help the following qns - no urgent.Thanks
Q2)The ratio of the number of girls to the number of boys taking part in a swimming assessment was 6:5.The assessment showed that the ratio of the number of girls' swimmers to the number of girls' non-swimmers was 5:2.The ratio of the number of boys' swimmers to the number of boys' non-swimmers was 3:2.
a)What fraction of the children were non-swimmers?
b)If there were 30 more boys' non-swimmers than girls' non-swimmers how many swimmers were there altogether?
TIA.
Boys' swimmers : Boys' non-swimmers = 3 : 2 --> 21u : 14u
Girls' swimmers : Girls's non-swimmers = 5 : 2 --> 30u : 12u
Total number of non-swimmers = 14u + 12u = 26u
a) fraction of the children who are non-swimmers = 26/77
Total number of swimmers --> 21u + 30u = 51u
Boys' non-swimmer --> 14u
Girls' non-swimmer --> 12u
2u --> 30, 1u --> 15
Total number of swimmers --> 51 x 15 = 765
cheers. -
smartmummy:
How to find 42u : 35u --- total --> 77u,guess and check for G=G.swimmers + G.non swimmers, B=B.swimmers +B.non swimmers, or any short-cut? :thankyou:[/quote]G.swimmers + G.non-swimmers = 7, so total number of girls is a multiple of 7
Total girls : boys = 6 : 5 --> 42u : 35u --- total --> 77uMathIzzzFun:
[quote=\"smartmummy\"]Pls help the following qns - no urgent.Thanks
Q2)The ratio of the number of girls to the number of boys taking part in a swimming assessment was 6:5.The assessment showed that the ratio of the number of girls' swimmers to the number of girls' non-swimmers was 5:2.The ratio of the number of boys' swimmers to the number of boys' non-swimmers was 3:2.
a)What fraction of the children were non-swimmers?
b)If there were 30 more boys' non-swimmers than girls' non-swimmers how many swimmers were there altogether?
TIA.
Boys' swimmers : Boys' non-swimmers = 3 : 2 --> 21u : 14u
Girls' swimmers : Girls's non-swimmers = 5 : 2 --> 30u : 12u
Total number of non-swimmers = 14u + 12u = 26u
a) fraction of the children who are non-swimmers = 26/77
Total number of swimmers --> 21u + 30u = 51u
Boys' non-swimmer --> 14u
Girls' non-swimmer --> 12u
2u --> 30, 1u --> 15
Total number of swimmers --> 51 x 15 = 765
cheers.
since total number of girls : total number of boys = 6:5
we multiply by 7 to get --> 42 : 35
cheers. -
OIC,got it.Thanks MathIzzzFun for your explanation,solution and time.
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