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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      chloecube:
      Siti knitted 1 2/5m of a scarf,on Monday,she knitted 1/4 of the length.on Tuesday, she knitted 45cm more. What fraction of the scarf was knitted altogether?


      answer is 4/7.

      anyone can help? Thks
      1 2/5 m = 1.4m = 140 cm
      1/4 of 140 cm = 35 cm
      Total knitted = 35 cm + 45 cm = 80 cm

      Fraction of scarf knitted --> 80/140 = 4/7

      cheers.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        smartmummy:
        Pls help the following qns - no urgent.Thanks


        Q4) There were 20 more pears than plums at a fruit stall.After 1/5 of the pears and 3/10 of the plums were sold, there were 46 pears and plums left.How many plums were left over.

        TIA.
        Plums --> 20 units
        Pears --> 20 units + 20

        Left:
        Plums --> 7/10 x 20 units = 14 units
        Pears --> 4/5 x (20 units + 20) = 16 units + 16

        Total of 46 pears and plums left, so

        14 units + 16 units + 16 = 46
        1 unit --> 1

        Plums left --> 14

        cheers.

        1 Reply Last reply Reply Quote 0
        • S Offline
          smartmummy
          last edited by

          MathIzzzFun:
          smartmummy:

          Pls help the following qns - no urgent.Thanks


          Q4) There were 20 more pears than plums at a fruit stall.After 1/5 of the pears and 3/10 of the plums were sold, there were 46 pears and plums left.How many plums were left over.

          TIA.

          Plums --> 20 units
          Pears --> 20 units + 20

          Left:
          Plums --> 7/10 x 20 units = 14 units
          Pears --> 4/5 x (20 units + 20) = 16 units + 16

          Total of 46 pears and plums left, so

          14 units + 16 units + 16 = 46
          1 unit --> 1

          Plums left --> 14

          cheers.

          :thankyou: so much for ur help. Appreciate much!!
          Why plums---> 20 units, can we assume plums--->10 units, do we find common multiple of 5 & 10?Thanks

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            smartmummy:
            MathIzzzFun:

            [quote=\"smartmummy\"]Pls help the following qns - no urgent.Thanks


            Q4) There were 20 more pears than plums at a fruit stall.After 1/5 of the pears and 3/10 of the plums were sold, there were 46 pears and plums left.How many plums were left over.

            TIA.

            Plums --> 20 units
            Pears --> 20 units + 20

            Left:
            Plums --> 7/10 x 20 units = 14 units
            Pears --> 4/5 x (20 units + 20) = 16 units + 16

            Total of 46 pears and plums left, so

            14 units + 16 units + 16 = 46
            1 unit --> 1

            Plums left --> 14

            cheers.

            :thankyou: so much for ur help. Appreciate much!!
            Why plums---> 20 units, can we assume plums--->10 units, do we find common multiple of 5 & 10?Thanks[/quote]yes, you can assume 10 units... I chose 20 units for easier calculation as there are 20 more pears.

            cheers.

            1 Reply Last reply Reply Quote 0
            • S Offline
              smartmummy
              last edited by

              MathIzzzFun:
              smartmummy:

              Pls help the following qns - no urgent.Thanks



              Q2)The ratio of the number of girls to the number of boys taking part in a swimming assessment was 6:5.The assessment showed that the ratio of the number of girls' swimmers to the number of girls' non-swimmers was 5:2.The ratio of the number of boys' swimmers to the number of boys' non-swimmers was 3:2.
              a)What fraction of the children were non-swimmers?
              b)If there were 30 more boys' non-swimmers than girls' non-swimmers how many swimmers were there altogether?

              TIA.

              Total girls : boys = 6 : 5 --> 42u : 35u --- total --> 77u
              Boys' swimmers : Boys' non-swimmers = 3 : 2 --> 21u : 14u

              Girls' swimmers : Girls's non-swimmers = 5 : 2 --> 30u : 12u

              Total number of non-swimmers = 14u + 12u = 26u
              a) fraction of the children who are non-swimmers = 26/77

              Total number of swimmers --> 21u + 30u = 51u
              Boys' non-swimmer --> 14u
              Girls' non-swimmer --> 12u
              2u --> 30, 1u --> 15

              Total number of swimmers --> 51 x 15 = 765

              cheers.

              How to find 42u : 35u --- total --> 77u,guess and check for G=G.swimmers + G.non swimmers, B=B.swimmers +B.non swimmers, or any short-cut? :thankyou:

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                smartmummy:
                MathIzzzFun:

                [quote=\"smartmummy\"]Pls help the following qns - no urgent.Thanks



                Q2)The ratio of the number of girls to the number of boys taking part in a swimming assessment was 6:5.The assessment showed that the ratio of the number of girls' swimmers to the number of girls' non-swimmers was 5:2.The ratio of the number of boys' swimmers to the number of boys' non-swimmers was 3:2.
                a)What fraction of the children were non-swimmers?
                b)If there were 30 more boys' non-swimmers than girls' non-swimmers how many swimmers were there altogether?

                TIA.

                Total girls : boys = 6 : 5 --> 42u : 35u --- total --> 77u
                Boys' swimmers : Boys' non-swimmers = 3 : 2 --> 21u : 14u

                Girls' swimmers : Girls's non-swimmers = 5 : 2 --> 30u : 12u

                Total number of non-swimmers = 14u + 12u = 26u
                a) fraction of the children who are non-swimmers = 26/77

                Total number of swimmers --> 21u + 30u = 51u
                Boys' non-swimmer --> 14u
                Girls' non-swimmer --> 12u
                2u --> 30, 1u --> 15

                Total number of swimmers --> 51 x 15 = 765

                cheers.

                How to find 42u : 35u --- total --> 77u,guess and check for G=G.swimmers + G.non swimmers, B=B.swimmers +B.non swimmers, or any short-cut? :thankyou:[/quote]G.swimmers + G.non-swimmers = 7, so total number of girls is a multiple of 7

                since total number of girls : total number of boys = 6:5
                we multiply by 7 to get --> 42 : 35

                cheers.

                1 Reply Last reply Reply Quote 0
                • S Offline
                  smartmummy
                  last edited by

                  OIC,got it.Thanks MathIzzzFun for your explanation,solution and time.

                  1 Reply Last reply Reply Quote 0
                  • C Offline
                    chloecube
                    last edited by

                    MathIzzzFun:
                    chloecube:

                    Siti knitted 1 2/5m of a scarf,on Monday,she knitted 1/4 of the length.on Tuesday, she knitted 45cm more. What fraction of the scarf was knitted altogether?


                    answer is 4/7.

                    anyone can help? Thks

                    1 2/5 m = 1.4m = 140 cm
                    1/4 of 140 cm = 35 cm
                    Total knitted = 35 cm + 45 cm = 80 cm

                    Fraction of scarf knitted --> 80/140 = 4/7

                    cheers.

                    thank you
                    i mis-read the sentence as she did 45cm more on tue than monday

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      doraemo
                      last edited by

                      pls help




                      (1)\tW and R collect stamps. If R gives W 15 stamps, he will have the same number of stamps as W. If W gives R 15 stamps, he will have ½ as many stamps as R. How many stamps does each of them have?


                      (2)\tIn April A,B C and D had a total of $324. In May , the savings of the 4 girls became equal when A’s savings was doubled, B’s savings was reduced by $4, C’s saving remained unchanged and D’s savings was increased by $9. What was B’s and D’s savings in April?

                      1 Reply Last reply Reply Quote 0
                      • 2 Offline
                        2Transformer
                        last edited by

                        I need your help to solve this question.



                        Question:

                        The ratio of the number of library books in School ABC to the number of library books in School XYZ was 5:4. When 1424 books from School ABC were loaned to School XYZ, the ratio of the number of books in School ABC to the number of books in School XYZ became 13:14.

                        (a) What fraction of the books in School ABC was loaned to School XYZ ?
                        (b) How many books were there in School XYZ at first?

                        1 Reply Last reply Reply Quote 0

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