Q&A - P3 Math

[Oldschool]

happyheart:

Can I know how to solve this question?


Adeline has 1450 coins. Tracy had 2740 coins. After Tracy had given some coins to Adeline, they had the same number of coins each. How many coins did each of them have at the end?
Thanks in advance.

Hi,

http://i39.tinypic.com/1t0fmw.jpg\">

Regards

[Honesty]

How about these questions.


1. A box with 12 sweets has a mass of 265g. The same box with 5 sweets in it has a mass of 195g. What is the mass of the empty box?

2. Mr Lim has a bag containing 9 yellow marbles and 13 green marbles. The total mass of the marbles is 136 grams. The total mass of 1 yellow and 1 green marbles is 12 grams. What is the mass of 1 yellow marble?

[happyheart]

Oldschool:

happyheart:

Can I know how to solve this question?


Adeline has 1450 coins. Tracy had 2740 coins. After Tracy had given some coins to Adeline, they had the same number of coins each. How many coins did each of them have at the end?
Thanks in advance.

Hi,

http://i39.tinypic.com/1t0fmw.jpg\">

Regards

:thankyou: Have a good day!

[catddy2002]

Honesty:

How about these questions.


1. A box with 12 sweets has a mass of 265g. The same box with 5 sweets in it has a mass of 195g. What is the mass of the empty box?

2. Mr Lim has a bag containing 9 yellow marbles and 13 green marbles. The total mass of the marbles is 136 grams. The total mass of 1 yellow and 1 green marbles is 12 grams. What is the mass of 1 yellow marble?

Hi,

I just try.
Maybe some parents might have better way to solve.

Q1. 12 sweets - 5 sweets = 7 sweets
265g - 195g = 70 g
7 sweets = 70 g
70/7 = 10g = weight of 1 sweet.
5 sweets = 10 X 5 = 50g
195g - 50g = 145 g = mass of the empty box

Q2. 1 yellow + 1 green = 12 g
9 sets = 9 x12 = 108 g
13 green marbles - 9 green marbles = 4 green marbles left
136g - 108g = 28g
28g / 4 green marbles = 7 g for each green marbles
13 green marbles = 91 g
136g - 91 g =45g
45g / 9 yellow marbles = 5 g

[Honesty]

catddy2002:

Honesty:

How about these questions.


1. A box with 12 sweets has a mass of 265g. The same box with 5 sweets in it has a mass of 195g. What is the mass of the empty box?

2. Mr Lim has a bag containing 9 yellow marbles and 13 green marbles. The total mass of the marbles is 136 grams. The total mass of 1 yellow and 1 green marbles is 12 grams. What is the mass of 1 yellow marble?

Hi,

I just try.
Maybe some parents might have better way to solve.

Q1. 12 sweets - 5 sweets = 7 sweets
265g - 195g = 70 g
7 sweets = 70 g
70/7 = 10g = weight of 1 sweet.
5 sweets = 10 X 5 = 50g
195g - 50g = 145 g = mass of the empty box

Q2. 1 yellow + 1 green = 12 g
9 sets = 9 x12 = 108 g
13 green marbles - 9 green marbles = 4 green marbles left
136g - 108g = 28g
28g / 4 green marbles = 7 g for each green marbles
13 green marbles = 91 g
136g - 91 g =45g
45g / 9 yellow marbles = 5 g

Yes, this is the method I used. How can we depict in models?

[catddy2002]

happyheart:

This question, logically can be solved by making the denominator the same but DS has not been taught so. How may I best approach to teach him? Pls help.


Q) John read 2/9 of a book on Monday. He then read 1/3 of the book on Tuesday. He then completed reading the rest of the book on Wednesday. What fraction of the book did he read on Wednesday?

This question is from Rosyth SA1 2012 , Q40. This paper consists of 3-4 similar fraction questions. Thanks.

Hi,

Suggest use model.

A book = 9 units
Monday = 2 units
Tue = 1/3 of the book means = 9 units / 3= 3 units
Wed = 9-2-3= 4 units
4 units = 4/9 in fraction

[The Right Equation]

Honesty:

catddy2002:

[quote=\"Honesty\"]How about these questions.


1. A box with 12 sweets has a mass of 265g. The same box with 5 sweets in it has a mass of 195g. What is the mass of the empty box?

2. Mr Lim has a bag containing 9 yellow marbles and 13 green marbles. The total mass of the marbles is 136 grams. The total mass of 1 yellow and 1 green marbles is 12 grams. What is the mass of 1 yellow marble?

Hi,

I just try.
Maybe some parents might have better way to solve.

Q1. 12 sweets - 5 sweets = 7 sweets
265g - 195g = 70 g
7 sweets = 70 g
70/7 = 10g = weight of 1 sweet.
5 sweets = 10 X 5 = 50g
195g - 50g = 145 g = mass of the empty box

Q2. 1 yellow + 1 green = 12 g
9 sets = 9 x12 = 108 g
13 green marbles - 9 green marbles = 4 green marbles left
136g - 108g = 28g
28g / 4 green marbles = 7 g for each green marbles
13 green marbles = 91 g
136g - 91 g =45g
45g / 9 yellow marbles = 5 g

Yes, this is the method I used. How can we depict in models?[/quote] http://i39.tinypic.com/2s7jo8p.jpg\">

[MathIzzzFun]

Honesty:

catddy2002:

[quote=\"Honesty\"]How about these questions.


1. A box with 12 sweets has a mass of 265g. The same box with 5 sweets in it has a mass of 195g. What is the mass of the empty box?

2. Mr Lim has a bag containing 9 yellow marbles and 13 green marbles. The total mass of the marbles is 136 grams. The total mass of 1 yellow and 1 green marbles is 12 grams. What is the mass of 1 yellow marble?

Hi,

I just try.
Maybe some parents might have better way to solve.

Q1. 12 sweets - 5 sweets = 7 sweets
265g - 195g = 70 g
7 sweets = 70 g
70/7 = 10g = weight of 1 sweet.
5 sweets = 10 X 5 = 50g
195g - 50g = 145 g = mass of the empty box

Q2. 1 yellow + 1 green = 12 g
9 sets = 9 x12 = 108 g
13 green marbles - 9 green marbles = 4 green marbles left
136g - 108g = 28g
28g / 4 green marbles = 7 g for each green marbles
13 green marbles = 91 g
136g - 91 g =45g
45g / 9 yellow marbles = 5 g

Yes, this is the method I used. How can we depict in models?[/quote]Q2-

http://i40.tinypic.com/rk3jmh.png\">

cheers.

[MathIzzzFun]

happyheart:

This question, logically can be solved by making the denominator the same but DS has not been taught so. How may I best approach to teach him? Pls help.


Q) John read 2/9 of a book on Monday. He then read 1/3 of the book on Tuesday. He then completed reading the rest of the book on Wednesday. What fraction of the book did he read on Wednesday?

This question is from Rosyth SA1 2012 , Q40. This paper consists of 3-4 similar fraction questions. Thanks.

Equivalent fractions are covered in P3 syllabus. So, in this case, the student is expected to convert 1/3 to the equivalent fraction 3/9 and then work out the remaining fraction.

cheers.

[Honesty]

:thankyou: