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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • C Offline
      Charnic
      last edited by

      doraemo:
      Can someone help me with this ?


      Ray and Serene have a total of $1183 in their savings accounts. Serene and Tim have a total of $1124 while Ray and Tim have a total of $961.
      How much savings does Tim have?
      R+S = 1183 ----------(1)
      S+T = 1124 ---------- (2)
      R+T =961 ------------- (3)
      Add 2 and 3
      R+S+2T = 2085
      Compare the new equation to 1
      1183+2T = 2085
      2T = 902
      T = 401

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      • D Offline
        doraemo
        last edited by

        Thank you, CNS!

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        • D Offline
          doraemo
          last edited by

          Here’s another one:-

          A class has an equal number of boys and girls. ½ of the boys do not wear glasses and 15 girls do not wear glasses. 12 of the pupils wear glasses. How many pupils are there in the class?

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          • C Offline
            Charnic
            last edited by

            doraemo:
            Here's another one:-

            A class has an equal number of boys and girls. ½ of the boys do not wear glasses and 15 girls do not wear glasses. 12 of the pupils wear glasses. How many pupils are there in the class?
            Is the answer 36 ? If so, below is the working :

            U + [] = 12
            [] + 15 = 2U
            [] = 2U - 15
            Substituting the 3rd equation into the first, you would get :
            U + 2U - 15 = 12
            3U = 27
            U = 9
            Boys + girls add up to 4U

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            • D Offline
              doraemo
              last edited by

              Thank you, CNS…you’re great!

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              • C Offline
                Charnic
                last edited by

                doraemo:
                Thank you, CNS..you're great!

                No issue. Tell you something. I seem to derive more satisfaction solving maths now than to teach my own child. Her \" care-less\" attitude is driving me mad 🙂 :nunchuk:

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                • D Offline
                  doraemo
                  last edited by

                  hi CNS, any model drawing to solve this solution?

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                  • C Offline
                    Charnic
                    last edited by

                    doraemo:
                    hi CNS, any model drawing to solve this solution?

                    I dun know how to post the drawing, but it goes like this :

                    1) Draw two boxes ( gal and boy ) the same length - cos they are equal
                    2) For gals, just cut a portion, shade it and mark 15
                    3) For boys, cut equally into 2 portion and mark U on each and shade only one

                    Then you would see the unshaded portions are :

                    One U from boys and one unknown portion [] which equates 12.
                    For the gals model, yo would know [] + 15 = 2U ( cos they are the same length with boys).

                    Hope the above is clear ?

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                    • D Offline
                      doraemo
                      last edited by

                      hi CNS,

                      will get my DD to try… thank you !!!

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                      • C Offline
                        Charnic
                        last edited by

                        doraemo:
                        hi CNS,

                        will get my DD to try.... thank you !!!!!!!
                        Actually this may be too difficult for a P4 child. Am getting my child to skip this question, :xedfingers: hope it will not come out as one of the problem sums in her SA2.

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