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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • 2 Offline
      2Transformer
      last edited by

      Oldschool:
      2Transformer:

      [quote=\"2Transformer\"]Hi, can someone help me on this question?



      Keith had a number of books for sale. He sold 560 books on Saturday. On Sunday, he sold 1/5 of the remaining books and was left with 40 books. How many books did he have at first?

      Hi,

      http://i44.tinypic.com/2zyizqg.jpg\">

      Regards[/quote]
      Oldschool :thankyou:

      1 Reply Last reply Reply Quote 0
      • 2 Offline
        2Transformer
        last edited by

        Oldschool:
        2Transformer:

        I have another question.



        A watch cost $120 more than a bag. Janet used 1/3 of her money to buy the bag and was then short of $50 to buy the watch. How much did Janet have at first?

        Hi,

        http://i44.tinypic.com/nxw3gw.jpg\">

        Regards

        :thankyou: very much, Oldschool.

        1 Reply Last reply Reply Quote 0
        • M Offline
          mwarrier19
          last edited by

          Pearlyn had $65. This amount of money was enough to buy 4 bars of chocolate and 3 packets of biscuits. She decided to buy 3 bars of chocolates and 4 packets of biscuits and had $4 left. What was the cost of one packet of biscuit?


          I am not sure on what method to be used

          1 Reply Last reply Reply Quote 0
          • O Offline
            Oldschool
            last edited by

            mwarrier19:
            Pearlyn had $65. This amount of money was enough to buy 4 bars of chocolate and 3 packets of biscuits. She decided to buy 3 bars of chocolates and 4 packets of biscuits and had $4 left. What was the cost of one packet of biscuit?


            I am not sure on what method to be used
            Hi,

            BTW, you might want to use this thread instead for posting questions/answers. Less work for the mods or admins.
            http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=68&t=25129


            You can use MD or form equations to solve the problem.

            For MD, you will be able to see that,

            4C + 3B = 65 or
            (1C) + 3C + 3B = 65

            Now, remove 1C and add (1B + $4 left), so

            1C = 1B + $4

            Then

            4B + 16 + 3B = 65
            7B = 49
            B =$7


            Regards

            1 Reply Last reply Reply Quote 0
            • M Offline
              marstolive
              last edited by

              Oldschool, thanks for help. Really appreciate.

              1 Reply Last reply Reply Quote 0
              • H Offline
                hazelwong
                last edited by

                MathIzzzFun:
                hazelwong:

                Hi, can anyone please help with this question?


                Observe the following statements:
                A+B+C=26
                A-B=6
                C-B=2
                i) Insert a pair of brackets ( ) in the number statement below to illustrate the correct working order to find the value of A
                26 – 2 – 6 ÷ 3 + 6
                ii) what is the value of A?
                Thanks :?:


                (26 - 2 - 6) ÷ 3 + 6
                ...(26-2-6) gives 3B

                A = 12

                cheers

                :thankyou:

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                • S Offline
                  Sharmum
                  last edited by

                  Hi,


                  Need help on the following 2 questions:-

                  http://i43.tinypic.com/2z9gqp4.jpg\">

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    Sharmum
                    last edited by

                    Question 2:


                    http://i39.tinypic.com/15qvq6s.jpg\">

                    :thankyou:

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                    • R Offline
                      RyanGow
                      last edited by

                      Hi its my first time in Kiasu Parents.


                      Need help on a P5 Math question:

                      1. Classes 5A and 5B have the same number of pupils. The ratio of the number of boys in 5A to the number of boys in 5B is 2:3. The ratio of the number of girls in 5A to the number of girls in 5B is 7:4.

                      a) Find the ratio of the number of boys to the number of girls in 5A.
                      b) If there are 15 fewer girls than boys in 5B, how many pupils are there in 5B?

                      Thanks much! :xedfingers:

                      1 Reply Last reply Reply Quote 0
                      • S Offline
                        smartmummy
                        last edited by

                        Sharmum:
                        Hi,


                        Need help on the following 2 questions:-

                        http://i43.tinypic.com/2z9gqp4.jpg\">
                        Let dc=u
                        so bc=2u
                        6u=108
                        u=18
                        area of bec=1/2*bc*dc
                        =1/2*2u*u
                        =18*18
                        =324cm2

                        1 Reply Last reply Reply Quote 0

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