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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • M Offline
      mwarrier19
      last edited by

      Pearlyn had $65. This amount of money was enough to buy 4 bars of chocolate and 3 packets of biscuits. She decided to buy 3 bars of chocolates and 4 packets of biscuits and had $4 left. What was the cost of one packet of biscuit?


      I am not sure on what method to be used

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      • O Offline
        Oldschool
        last edited by

        mwarrier19:
        Pearlyn had $65. This amount of money was enough to buy 4 bars of chocolate and 3 packets of biscuits. She decided to buy 3 bars of chocolates and 4 packets of biscuits and had $4 left. What was the cost of one packet of biscuit?


        I am not sure on what method to be used
        Hi,

        BTW, you might want to use this thread instead for posting questions/answers. Less work for the mods or admins.
        http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=68&t=25129


        You can use MD or form equations to solve the problem.

        For MD, you will be able to see that,

        4C + 3B = 65 or
        (1C) + 3C + 3B = 65

        Now, remove 1C and add (1B + $4 left), so

        1C = 1B + $4

        Then

        4B + 16 + 3B = 65
        7B = 49
        B =$7


        Regards

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        • M Offline
          marstolive
          last edited by

          Oldschool, thanks for help. Really appreciate.

          1 Reply Last reply Reply Quote 0
          • H Offline
            hazelwong
            last edited by

            MathIzzzFun:
            hazelwong:

            Hi, can anyone please help with this question?


            Observe the following statements:
            A+B+C=26
            A-B=6
            C-B=2
            i) Insert a pair of brackets ( ) in the number statement below to illustrate the correct working order to find the value of A
            26 – 2 – 6 ÷ 3 + 6
            ii) what is the value of A?
            Thanks :?:


            (26 - 2 - 6) ÷ 3 + 6
            ...(26-2-6) gives 3B

            A = 12

            cheers

            :thankyou:

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            • S Offline
              Sharmum
              last edited by

              Hi,


              Need help on the following 2 questions:-

              http://i43.tinypic.com/2z9gqp4.jpg\">

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              • S Offline
                Sharmum
                last edited by

                Question 2:


                http://i39.tinypic.com/15qvq6s.jpg\">

                :thankyou:

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                • R Offline
                  RyanGow
                  last edited by

                  Hi its my first time in Kiasu Parents.


                  Need help on a P5 Math question:

                  1. Classes 5A and 5B have the same number of pupils. The ratio of the number of boys in 5A to the number of boys in 5B is 2:3. The ratio of the number of girls in 5A to the number of girls in 5B is 7:4.

                  a) Find the ratio of the number of boys to the number of girls in 5A.
                  b) If there are 15 fewer girls than boys in 5B, how many pupils are there in 5B?

                  Thanks much! :xedfingers:

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                  • S Offline
                    smartmummy
                    last edited by

                    Sharmum:
                    Hi,


                    Need help on the following 2 questions:-

                    http://i43.tinypic.com/2z9gqp4.jpg\">
                    Let dc=u
                    so bc=2u
                    6u=108
                    u=18
                    area of bec=1/2*bc*dc
                    =1/2*2u*u
                    =18*18
                    =324cm2

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                    • S Offline
                      smartmummy
                      last edited by

                      Sharmum:
                      Question 2:


                      http://i39.tinypic.com/15qvq6s.jpg\">

                      :thankyou:
                      area of PSQ=1/2*25*12=150cm2
                      area of PQRS=2*150=300cm2
                      PS=300/15=20cm

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                      • S Offline
                        Sharmum
                        last edited by

                        smartmummy:
                        Sharmum:

                        Question 2:


                        http://i39.tinypic.com/15qvq6s.jpg\">

                        :thankyou:

                        area of PSQ=1/2*25*12=150cm2
                        area of PQRS=2*150=300cm2
                        PS=300/15=20cm


                        Hi Smartmummy,

                        Thank you for your help !!

                        :salute:

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