Q&A - P5 Math

[Oldschool]

mwarrier19:

Pearlyn had $65. This amount of money was enough to buy 4 bars of chocolate and 3 packets of biscuits. She decided to buy 3 bars of chocolates and 4 packets of biscuits and had $4 left. What was the cost of one packet of biscuit?


I am not sure on what method to be used

Hi,

BTW, you might want to use this thread instead for posting questions/answers. Less work for the mods or admins.
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=68&t=25129


You can use MD or form equations to solve the problem.

For MD, you will be able to see that,

4C + 3B = 65 or
(1C) + 3C + 3B = 65

Now, remove 1C and add (1B + $4 left), so

1C = 1B + $4

Then

4B + 16 + 3B = 65
7B = 49
B =$7


Regards

[marstolive]

Oldschool, thanks for help. Really appreciate.

[hazelwong]

MathIzzzFun:

hazelwong:

Hi, can anyone please help with this question?


Observe the following statements:
A+B+C=26
A-B=6
C-B=2
i) Insert a pair of brackets ( ) in the number statement below to illustrate the correct working order to find the value of A
26 – 2 – 6 ÷ 3 + 6
ii) what is the value of A?
Thanks :?:

(26 - 2 - 6) ÷ 3 + 6
...(26-2-6) gives 3B

A = 12

cheers

:thankyou:

[Sharmum]

Hi,


Need help on the following 2 questions:-

http://i43.tinypic.com/2z9gqp4.jpg\">

[Sharmum]

Question 2:


http://i39.tinypic.com/15qvq6s.jpg\">

:thankyou:

[RyanGow]

Hi its my first time in Kiasu Parents.


Need help on a P5 Math question:

1. Classes 5A and 5B have the same number of pupils. The ratio of the number of boys in 5A to the number of boys in 5B is 2:3. The ratio of the number of girls in 5A to the number of girls in 5B is 7:4.

a) Find the ratio of the number of boys to the number of girls in 5A.
b) If there are 15 fewer girls than boys in 5B, how many pupils are there in 5B?

Thanks much! :xedfingers:

[smartmummy]

Sharmum:

Hi,


Need help on the following 2 questions:-

http://i43.tinypic.com/2z9gqp4.jpg\">

Let dc=u
so bc=2u
6u=108
u=18
area of bec=1/2*bc*dc
=1/2*2u*u
=18*18
=324cm2

[smartmummy]

Sharmum:

Question 2:


http://i39.tinypic.com/15qvq6s.jpg\">

:thankyou:

area of PSQ=1/2*25*12=150cm2
area of PQRS=2*150=300cm2
PS=300/15=20cm

[Sharmum]

smartmummy:

Sharmum:

Question 2:


http://i39.tinypic.com/15qvq6s.jpg\">

:thankyou:

area of PSQ=1/2*25*12=150cm2
area of PQRS=2*150=300cm2
PS=300/15=20cm

Hi Smartmummy,

Thank you for your help !!

:salute:

[smartmummy]

RyanGow:

Hi its my first time in Kiasu Parents.


Need help on a P5 Math question:

1. Classes 5A and 5B have the same number of pupils. The ratio of the number of boys in 5A to the number of boys in 5B is 2:3. The ratio of the number of girls in 5A to the number of girls in 5B is 7:4.

a) Find the ratio of the number of boys to the number of girls in 5A.
b) If there are 15 fewer girls than boys in 5B, how many pupils are there in 5B?

Thanks much! :xedfingers:

5A:5B
Pupils n:n
Boys 2:3
4:6
6:9 make the number of pupils same

Girls 7:4
Pupils 7+6=13:4+9=13
9u-4u=15
5u=15
1u=3
13*3=39 pupils in 5B