Q&A - PSLE Math

[tianzhu]

Hifive:

Hi tianzhu


Got it. Thank you, thank you!

Hi Hifive

You're welcome.

Best wishes

[2centsworthy]

:thankyou:

WCW:

2centsworthy:

Please help to solve the following:

Ron had some chocolates and sweets. If Ron sold 18 chocolates and 24 sweets each day, there would still be 25 chocolates left when all the sweets were sold. If Ron sold 13 chocolates and 30 sweets each day, he would still have 139 chocolates left when all the sweets were sold. How many chocolates and sweets did Ron have?

My method is find the common multiple for 24 and 30. think someone might have an easier and faster way?

Common muliples of 24 and 30
120, 240, 360

C : S
18 : 24
18*15 : 24*15
+25

C : S
13 : 30
13*12 : 30*12
+139

C=295
S=360

[Daddy]

Hi,


I have a question to ask.

1. grandpa had a farm. He kept 89 goats and chickens. The total number of legs the animals had was 264 legs. How many chickens did grandpa have?

If use guess and check methode would be very long time to find the anwer. Is there any short way to solve above question?
Thanks…

[MathIzzzFun]

Daddy:

Hi,


I have a question to ask.

1. grandpa had a farm. He kept 89 goats and chickens. The total number of legs the animals had was 264 legs. How many chickens did grandpa have?

If use guess and check methode would be very long time to find the anwer. Is there any short way to solve above question?
Thanks....

Hi

use the assumptive method...

assume all are goats OR all are chickens first.

say, all are goats, then total legs = 4 x 89 = 356
\"extra\" legs = 356 - 264 = 92
the \"extra\" legs are due to counting chickens as goats.. ie 2 extra legs counted, so number of chickens = 92/2 = 46
89 - 46 = 43 goats

so, 46 chickens & 43 goats.

cheers.

[dnsy]

MathIzzzFun - Thanks!

[ozora]

need quick help:

Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
Thanks in advance

[MathIzzzFun]

ozora:

need quick help:

Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
Thanks in advance

Hi

this is a variation of the typical \"counting coins\" problem sum.

There are 120 more cups than plates...& 12 more blue boxes (cups) than red boxes (plates)

each blue box has 30 less cups than plates in red box.

make the number of boxes the same - either add red boxes, or remove blue boxes. Since we are looking for number of plates (red boxes), we remove blue boxes.

remove 12 blue boxes so that there are now equal number of boxes.
12 x 120 cups = 1440 cups, there are now 1440 - 120 = 1320 lesser cups than plates in the boxes.

each blue box has 30 less cups than plates in red boxes, 1320 / 30 = 44
there are 44 red boxes and 44+12 = 56 blue boxes

number of plates = 44 x 150 = 6600

cheers.

[ozora]

MathIzzzFun:

ozora:

need quick help:

Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
Thanks in advance

Hi

this is a variation of the typical \"counting coins\" problem sum.

There are 120 more cups than plates...& 12 more blue boxes (cups) than red boxes (plates)

each blue box has 30 less cups than plates in red box.

make the number of boxes the same - either add red boxes, or remove blue boxes. Since we are looking for number of plates (red boxes), we remove blue boxes.

remove 12 blue boxes so that there are now equal number of boxes.
12 x 120 cups = 1440 cups, there are now 1440 - 120 = 1320 lesser cups than plates in the boxes.

each blue box has 30 less cups than plates in red boxes, 1320 / 30 = 44
there are 44 red boxes and 44+12 = 56 blue boxes

number of plates = 44 x 150 = 6600

cheers.

thanks.. may i know how to get\" each blue box has 30 less cups than plates in red box.\"


it looked so easy to you but really tough on me and the kids to comprehend.

[MathIzzzFun]

ozora:

MathIzzzFun:

[quote=\"ozora\"]need quick help:

Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
Thanks in advance

Hi

this is a variation of the typical \"counting coins\" problem sum.

There are 120 more cups than plates...& 12 more blue boxes (cups) than red boxes (plates)

each blue box has 30 less cups than plates in red box.

make the number of boxes the same - either add red boxes, or remove blue boxes. Since we are looking for number of plates (red boxes), we remove blue boxes.

remove 12 blue boxes so that there are now equal number of boxes.
12 x 120 cups = 1440 cups, there are now 1440 - 120 = 1320 lesser cups than plates in the boxes.

each blue box has 30 less cups than plates in red boxes, 1320 / 30 = 44
there are 44 red boxes and 44+12 = 56 blue boxes

number of plates = 44 x 150 = 6600

cheers.

thanks.. may i know how to get\" each blue box has 30 less cups than plates in red box.\"


it looked so easy to you but really tough on me and the kids to comprehend.[/quote]Hi

..I read the question as \"Each blue box contained 120 cups and each red box contained 150 plates.\", otherwise, it is not possible to solve because there is no mention of number of cups any where.

cheers.

[pensiveowl]

Pls help us ans this problem, thanks:


In the elections committee, 40% of the members were men and the rest were women. When 210 members resigned from the club, the number
of men became 1/4 of the original number of men and the number of women decreased by 20%.
(a) How many women were in the club at first ?
(b) How many men resigned from the club ?