Tutor MathsGuru: Ask me for your burning Maths questions!
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Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks. -
starlight1968sg:
Hi, the question is familar but can't recall from which paper.Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks.
11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol: -
starlight1968sg:
By giving each dog 4 more cans, he use up the extra 4 cans and needed another 28 more.Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks.
Hence
28 + 4 = 32
32 / 4 = 8
a) 8 dogs
b) (7 * 8 ) + 4 = 60 -
Brenda10:
Why 11 - 7 ?11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol:
Then what is \"4 + 28\"?
Can you offer some explanations?
Many thanks. -
Brenda10:
Hi Brenda10,
Hi, the question is familar but can't recall from which paper.starlight1968sg:
Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks.
11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol:
It's from http://www.orlesson.org/orp/09Ma/2009-Math-SA2-ACS.pdf.
Hi starlight1968sg,
To help potential problem solvers in one way or another, pls kindly provide the source of your question and given answer even though the given answer may or may not 100% correct.
Thanks. -
starlight1968sg:
Hi, I'm not good in explanation and hopefully you can understand by restate the problem this way:
Why 11 - 7 ?Brenda10:
11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol:
Then what is \"4 + 28\"?
Can you offer some explanations?
Many thanks.
To give 4 more cans (11 - 7) to reach dog, 32 more cans (4 + 28 ) would be needed
You can refer more this kind of solutions under i-Excel Heuristic and Model Approach - Level 5. I also learn from there and remembered the steps to solve the above question as such. :oops: -
Vanilla Cake:
Dear Vanilla CakeHi Brenda10,
It's from http://www.orlesson.org/orp/09Ma/2009-Math-SA2-ACS.pdf.
Thank you. Now I check and realize we did this quesiton during June holiday that's why I found it familar. -
Yu Xuan:
Speed Ratio:Carrot:
Hi thank you in advance please help me stuck on this question:
Mr Ho used to travel at a speed of 80km/h from town A to town B. He slowed down his speed to 60km/h and reached town B 1 1/2 hours later than usual. Find the distance between town A and Town B.
:?: :?: :?:
Thanks !
Usual : Slower
80 : 60
4 : 3
Time Ratio
Usual : Slower
3 : 4
4u - 3u = 1 1/2h
1 u = 1 1/2h
1 1/2h * 3 = 4 1/2h
4 1 /2h * 80 = 360km
Is 360km that the answer?[/quote
Thank a lot. I think I understand now.
:boogie:
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Dear Gurus,
For the Maha Bodi 2010 Prelim question 18 (the speed question), how is the answer of 40 min derived?
Rosyth 2010 question 16:-
Machine A and B each printed a fixed number of newspapers per hour.
Machine B started printing earlier at a rate of 75 copies per hour. After Machine B had printed for 10 hours, Machine A had printed 340 copies. After Machine B had printed for 16 hours, Machine A had printed 886 copies.
a) How many copies of newspapers did Machine A print per hour?
b) How long would MAchine B hsve worked when both machines have printed a total of 2 750 copies?
Given answer is a) 92 copies per hour
b) 20 hours
Can any help how answer b is derived? Thank you for enlightening me. -
corvette:
I am not any guru but just a year 2 student. Quick one while waiting for answers from KSP members. Pls refer to Uncle Observer's http://psle2010a.blogspot.com/ which he had kindly worked out the solutions for most of the 2010 P6 Prelim Maths questions from top schools.Dear Gurus,
For the Maha Bodi 2010 Prelim question 18 (the speed question), how is the answer of 40 min derived?
Solution for Maha Bodhi 2010 P6 Prelim Q18 by http://psle2010a.blogspot.com/2010/09/maha-modhi-p6-speed-q18.html.
Solution for Maha Bodhi 2010 P6 Prelim Q18 by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1700 dated 09 Sep 2010 11:26
Solution for Maha Bodhi 2010 P6 Prelim Q18 by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1710 dated 09 Sep 2010 14:52corvette:
Solution by http://psle2010a.blogspot.com/2010/09/rates-p6-2010-sa2-rosyth-p2-q16.html for Rosyth School 2010 P6 Prelim paper 2 Q16Rosyth 2010 question 16:-
Machine A and B each printed a fixed number of newspapers per hour.
Machine B started printing earlier at a rate of 75 copies per hour. After Machine B had printed for 10 hours, Machine A had printed 340 copies. After Machine B had printed for 16 hours, Machine A had printed 886 copies.
a) How many copies of newspapers did Machine A print per hour?
b) How long would MAchine B hsve worked when both machines have printed a total of 2 750 copies?
Given answer is a) 92 copies per hour
b) 20 hours
Can any help how answer b is derived? Thank you for enlightening me.
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