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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • starlight1968sgS Offline
      starlight1968sg
      last edited by

      Hi,

      A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
      If he bought 7 cans for each dog, he would have bought 4 extra cans.
      If he bought 11 cans for each dog, he would need 28 more cans.
      (a) How many dogs were there in the pet shop?
      (b) How many cans did the owner buy?

      I am confused! 😒

      Many thanks.

      1 Reply Last reply Reply Quote 0
      • B Offline
        Brenda10
        last edited by

        starlight1968sg:
        Hi,

        A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
        If he bought 7 cans for each dog, he would have bought 4 extra cans.
        If he bought 11 cans for each dog, he would need 28 more cans.
        (a) How many dogs were there in the pet shop?
        (b) How many cans did the owner buy?

        I am confused! 😒

        Many thanks.
        Hi, the question is familar but can't recall from which paper.

        11 - 7 = 4
        4 + 28 = 32
        32 /4 = 8 (dogs)

        8 x 7 + 4 = 60 (cans the owner buy)

        Hope the abvoe useful. :lol:

        1 Reply Last reply Reply Quote 0
        • Y Offline
          Yu Xuan
          last edited by

          starlight1968sg:
          Hi,

          A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
          If he bought 7 cans for each dog, he would have bought 4 extra cans.
          If he bought 11 cans for each dog, he would need 28 more cans.
          (a) How many dogs were there in the pet shop?
          (b) How many cans did the owner buy?

          I am confused! 😒

          Many thanks.
          By giving each dog 4 more cans, he use up the extra 4 cans and needed another 28 more.

          Hence
          28 + 4 = 32
          32 / 4 = 8

          a) 8 dogs

          b) (7 * 8 ) + 4 = 60

          1 Reply Last reply Reply Quote 0
          • starlight1968sgS Offline
            starlight1968sg
            last edited by

            Brenda10:
            11 - 7 = 4

            4 + 28 = 32
            32 /4 = 8 (dogs)

            8 x 7 + 4 = 60 (cans the owner buy)

            Hope the abvoe useful. :lol:
            Why 11 - 7 ?
            Then what is \"4 + 28\"?
            Can you offer some explanations?
            Many thanks.

            1 Reply Last reply Reply Quote 0
            • V Offline
              Vanilla Cake
              last edited by

              Brenda10:
              starlight1968sg:

              Hi,

              A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
              If he bought 7 cans for each dog, he would have bought 4 extra cans.
              If he bought 11 cans for each dog, he would need 28 more cans.
              (a) How many dogs were there in the pet shop?
              (b) How many cans did the owner buy?

              I am confused! 😒

              Many thanks.

              Hi, the question is familar but can't recall from which paper.

              11 - 7 = 4
              4 + 28 = 32
              32 /4 = 8 (dogs)

              8 x 7 + 4 = 60 (cans the owner buy)

              Hope the abvoe useful. :lol:

              Hi Brenda10,
              It's from http://www.orlesson.org/orp/09Ma/2009-Math-SA2-ACS.pdf.

              Hi starlight1968sg,
              To help potential problem solvers in one way or another, pls kindly provide the source of your question and given answer even though the given answer may or may not 100% correct.

              Thanks.

              1 Reply Last reply Reply Quote 0
              • B Offline
                Brenda10
                last edited by

                starlight1968sg:
                Brenda10:

                11 - 7 = 4

                4 + 28 = 32
                32 /4 = 8 (dogs)

                8 x 7 + 4 = 60 (cans the owner buy)

                Hope the abvoe useful. :lol:

                Why 11 - 7 ?
                Then what is \"4 + 28\"?
                Can you offer some explanations?
                Many thanks.

                Hi, I'm not good in explanation and hopefully you can understand by restate the problem this way:

                To give 4 more cans (11 - 7) to reach dog, 32 more cans (4 + 28 ) would be needed

                You can refer more this kind of solutions under i-Excel Heuristic and Model Approach - Level 5. I also learn from there and remembered the steps to solve the above question as such. :oops:

                1 Reply Last reply Reply Quote 0
                • B Offline
                  Brenda10
                  last edited by

                  Vanilla Cake:
                  Hi Brenda10,

                  It's from http://www.orlesson.org/orp/09Ma/2009-Math-SA2-ACS.pdf.
                  Dear Vanilla Cake

                  Thank you. Now I check and realize we did this quesiton during June holiday that's why I found it familar.

                  1 Reply Last reply Reply Quote 0
                  • C Offline
                    Carrot
                    last edited by

                    Yu Xuan:
                    Carrot:

                    Hi thank you in advance please help me stuck on this question:


                    Mr Ho used to travel at a speed of 80km/h from town A to town B. He slowed down his speed to 60km/h and reached town B 1 1/2 hours later than usual. Find the distance between town A and Town B.

                    :?: :?: :?:
                    Thanks !

                    Speed Ratio:
                    Usual : Slower
                    80 : 60
                    4 : 3

                    Time Ratio
                    Usual : Slower
                    3 : 4

                    4u - 3u = 1 1/2h
                    1 u = 1 1/2h

                    1 1/2h * 3 = 4 1/2h
                    4 1 /2h * 80 = 360km

                    Is 360km that the answer?[/quote


                    Thank a lot. I think I understand now.
                    :boogie: πŸ˜„ πŸ˜‰

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      corvette
                      last edited by

                      Dear Gurus,

                      For the Maha Bodi 2010 Prelim question 18 (the speed question), how is the answer of 40 min derived?

                      Rosyth 2010 question 16:-
                      Machine A and B each printed a fixed number of newspapers per hour.
                      Machine B started printing earlier at a rate of 75 copies per hour. After Machine B had printed for 10 hours, Machine A had printed 340 copies. After Machine B had printed for 16 hours, Machine A had printed 886 copies.
                      a) How many copies of newspapers did Machine A print per hour?
                      b) How long would MAchine B hsve worked when both machines have printed a total of 2 750 copies?
                      Given answer is a) 92 copies per hour
                      b) 20 hours

                      Can any help how answer b is derived? Thank you for enlightening me.

                      1 Reply Last reply Reply Quote 0
                      • V Offline
                        Vanilla Cake
                        last edited by

                        corvette:
                        Dear Gurus,

                        For the Maha Bodi 2010 Prelim question 18 (the speed question), how is the answer of 40 min derived?
                        I am not any guru but just a year 2 student. Quick one while waiting for answers from KSP members. Pls refer to Uncle Observer's http://psle2010a.blogspot.com/ which he had kindly worked out the solutions for most of the 2010 P6 Prelim Maths questions from top schools.

                        Solution for Maha Bodhi 2010 P6 Prelim Q18 by http://psle2010a.blogspot.com/2010/09/maha-modhi-p6-speed-q18.html.
                        Solution for Maha Bodhi 2010 P6 Prelim Q18 by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1700 dated 09 Sep 2010 11:26
                        Solution for Maha Bodhi 2010 P6 Prelim Q18 by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1710 dated 09 Sep 2010 14:52
                        corvette:
                        Rosyth 2010 question 16:-
                        Machine A and B each printed a fixed number of newspapers per hour.
                        Machine B started printing earlier at a rate of 75 copies per hour. After Machine B had printed for 10 hours, Machine A had printed 340 copies. After Machine B had printed for 16 hours, Machine A had printed 886 copies.
                        a) How many copies of newspapers did Machine A print per hour?
                        b) How long would MAchine B hsve worked when both machines have printed a total of 2 750 copies?
                        Given answer is a) 92 copies per hour
                        b) 20 hours

                        Can any help how answer b is derived? Thank you for enlightening me.
                        Solution by http://psle2010a.blogspot.com/2010/09/rates-p6-2010-sa2-rosyth-p2-q16.html for Rosyth School 2010 P6 Prelim paper 2 Q16

                        1 Reply Last reply Reply Quote 0

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