equink:hahaha I think we might be in the same school... Q10?Can you please help me to solve this question?
10cm^3 of a hydrocarbon C4Hy was allowed to react with an excess of oxygen at 150°c and 1atm. There was an expansion of 10cm^3 in volume. Deduce the value of y.
Is the \"expansion\" stated in comparison to the volume of the hydrocarbon AND excess oxygen or to the volume of hydrocarbon AND reacted oxygen?
Anyway, I think the expansion of 10cm^3 refers to the total volume of gaseous products after complete combustion. (Ie, Vol of CO2 & H2O (g) + vol of excess unreacted O2 = 20 cm^3)
To solve,
vol of CO2 + vol of H2O (g) + vol of unreacted O2 - (10 cm^3 of C4Hy + vol of reacted & unreacted O2) = 10 cm^3
10 cm^3 = vol of CO2 + vol of H2O - 10 cm^3 - vol of reacted O2
= 40 + 10 (y/2) - 10 - 10 (4+y/4) [based on chemical equation, multiply by 10 cm^3 since 1 'mol of C4Hy gives 10 cm^3 -- since it's gas, volume can multiply throughout].
y = 8
Took me quite some time to get it too, hope this helps!
. IB sounds interesting, but heard there's a lot of coursework & PW involved.

