Champion:

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Hi! Need help with this Maths Question; :thankyou:

Key is to identify that the constant is Nursha (she has the same number of books all this while).
It is easier to solve this using ratio concept in p5. But the idea is the same at p4.
1. At first, Nursha had 4 units then Patrick had 1 unit.
2. When Patrick lost 3 books, Nursha had 5 parts then Patrick had 1 part.
So, put in another way (let Nursha have 20 portions before and after,i.e. LCM of 4 and 5), then
When Nursha had 20 portions, Patrick had 5 portions.
When Patrick lost 3 books, Nursha still had 20 portions, Patrick had 4 portions.
So the 3 books lost by Patrick is 1 portion.
Therefore: At first, they had 25 portions which is 25x3 = 75 books.

If by model, drawing 20 portions for Nursha might be tedious but still possible.
Kids will slowly phase out model \"cutting\" when they learn ratios in p5.

Ice watch:

tanxexy:

Please help on this question from ACS P5 2014 SA2:


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x=3.96 <---------------【refer to the picture below】
2*3.96*7 = 55.44 <---【4 triangles area】
12*12 = 144 <---------【square area】
144 - 55.44 = 88.56 cm^2 【 the total area of the shaded part 】

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Hi, just a note in case there is any panic mode activated. The above solution pricked my interest due to its complexity and I think Ice Watch has proven the exact dimensions and areas using Pythagoras' Theorem (PT). But as P6 are not expected to learn and use the PT, I would like to think that the question might have been overlooked by the setter and it is not his/her initial intention to have the solution using the PT. I made a 12cm by 12 cm paper and did like the folding and the bottom edge did look exactly like cut into 3 equal parts of 4cm. As a parent of P6 kid, I would just point out the error to the teacher but will not go beyond the classroom and teach my kid on the above. At most, I will rephrase the question to finding \"an estimate\" of the shaded area and use TianZhu's working earlier if I really want my P6 kid to solve it.

angel:

A + A + B = 23

A + B + B = 16
Find A.

Add both up: 3A + 3B = 39
Each pair A+B = 13
Compare this to first equation: A = 23-13 = 10

Daddy

Ribbon A and Ribbon B each consists of a blue part and a green part.

Ribbon A is 80cm shorter than Ribbon B.
The green part is 34cm longer than the blue part on Ribbon A.
The blue part on Ribbon B is 26cm longer than the blue part on Ribbon A.
How much longer is the green part than the blue part on Ribbon B.

TIA!

I'm colour-coding the solving process so that it may be easier to show the solving process step-by-step as you explain the same to your kid. Sometimes, the child can understand better when processing the thought process themselves. Trust in their abilities to reason out. Hope it helps.
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Delete duplicate.

4) Mr Lee has some blue and red markers. If he sells 24 red markers, the total number of markers left will be 6 times the number of red markers left. If he sells 36 blue markers, the total number of markers left will be four times the number of red markers left. How many (markers in total)?[/quote]


I would view models as the foundation for units and parts.
Can make the child use both methods for one question until he gets more comfortable with u & p, improves on equation solving techniques then slowly kids will phase out drawing models. That being said, pictorial presentation is usually still easier to understand for kids.
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Daddy

John has some boxes. He wants to put his sweets equally into each box. If he puts 8 sweets in each box, he will have 3 sweets left. If he puts 9 sweets in each box, he will need 7 more. How many sweets does John have?


TIA!

To \"top up\" each box of 8 to 9, we need to add 1 to each box.
Using the balance of 3 sweets, he can \"top up\" only 3 boxes.
If he needs another 7 sweets, it means there are another 7 boxes of 8 sweets.
So there are 3+7 = 10 boxes.
Total no. of sweets = 8 x 10 + 3 = 83.

hypergatak:

Hi


I need help in the following question from Roysth School 2013 SA2 paper:-

Kelly bought 2 boxes of beads, 3 packets of sequins and 4 spindles of thread at $15.75. A box of beads and a packet of sequins cost $4.45. A packets of sequins and a spindle of thread cost $3.10. Find the cost of a box of beads.

Thanks in advance.

You can draw shapes (B for Beads, S for Sequins, T for Thread) for the below if you like:

2B + 3S + 4T = 15.75 (\"original equation\")

1B + 1S = 4.45
1S + 1T = 3.10
Observe the patterns above: The common item is S (Sequins) and we shall make use of equations 2 and 3 to eliminate B and T (by making the number of B and T same as the \"original equation\")

2B + 2S = 8.90
4S + 4T = 12.40
Summing these 2: 2B + 6S + 4T = 21.30
Relating this to \"original equation\", we can deduce that 3S = 21.30-15.75 (so 1S = 1.85)
so 1B = 4.45-1.85 = 2.60 (Ans)
[check: 1T = 3.10-1.85 = 1.25, all the answers satisfy/agree with the \"original equation\"]

lulu2014:

$1600 was shared between Tim and Jill. After tim used 5/7 of his money and Jill spent 1/3 of her monny, they had the same amount of money left. how mich more money did tim receive than jill?

Note that remainder is equal:
2/7 of Tim = 2/3 of Jill

Since numerators are equal (if not, needs to make numerator equal), denominator shows the number of parts each child has before spending.
So Tim has 7 units and Jill has 3 units.
Total 10units is $1600 -> 1unit is $160

Tim received 4 more units than Jill --> $160x4 = $640

Wgh2005:

Hi, hope someone can help solve this question, thank you!


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Try to add \"additional\" age in front of models.
[edited]
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