Q&A - P4 Math

[tracywham]

Hi, can someone help me with this question...


Each dart thrown at this target scores points according to where it hits.

http://i42.tinypic.com/315l3zm.jpg\">

Xavier hits the target with 3 darts and totaled his points. Which of these totals is possible?

(1) 11
(2) 17
(3) 22
(4) 26.

the teacher give the answer as 11 without explaining. Can someone explained to me please. Thank you

[SignorWinter]

tracywham:

Hi, can someone help me with this question...


Each dart thrown at this target scores points according to where it hits.

http://i42.tinypic.com/315l3zm.jpg\">

Xavier hits the target with 3 darts and totaled his points. Which of these totals is possible?

(1) 11
(2) 17
(3) 22
(4) 26.

the teacher give the answer as 11 without explaining. Can someone explained to me please. Thank you

It can't possibly be 11!
The smallest combination would be 3x3 = 9, next, 3 +3 +5 = 16

In fact, are any of these even possible? Unless there's a typo, or hitting somewhere that would result in a zero, then this is just.....MEH

[tracywham]

I'm also puzzled with the answer... My daughter came back with the answer from teacher as 11, moreover the teacher didn't explained anything :slapshead:

[Oldschool]

tracywham:

Hi, can someone help me with this question...


Each dart thrown at this target scores points according to where it hits.

http://i42.tinypic.com/315l3zm.jpg\">

Xavier hits the target with 3 darts and totaled his points. Which of these totals is possible?

(1) 11
(2) 17
(3) 22
(4) 26.

the teacher give the answer as 11 without explaining. Can someone explained to me please. Thank you

Hi,

The three darts can hit any of the three combination, and their respective sum is

3,3,3 --> 9
3,3,5 --> 11
3,3,8 --> 14
3,5,5 --> 13
3,5,8 --> 16
3,8,8 -->19
5,5,5 -->15
5,5,8 --> 18
5,8,8 --> 21
8,8,8 --> 24

Hence only (a) 11 .

Regards

[tracywham]

Oh... thank you so much...you enlighten me....A big thanks from my daughter too :thankyou:

[SignorWinter]

Oh heck, my math has deteriorated to the point of despair. :x

[BigDevil]

Please help with this…


Joyce, Perry, Tanya and Seetha shared a box of stickers.
After distributing all the stickers, J got thrice as many stickers as T.
If P gave 38 stickers to S, they would both have the same number
of stickers. P would then have half as many stickers as J.
If there were 280 stickers in the box in the end, how many stickers
did J and P have respectively at first.


So I figured out there is a total of 7u (J 3u, T 1u, P 1.5u+38, S 1.5u-38),
but I just couldn’t figure out how to fit 280 into the model.

[Maths Hub]

BigDevil:

Please help with this...


Joyce, Perry, Tanya and Seetha shared a box of stickers.
After distributing all the stickers, J got thrice as many stickers as T.
If P gave 38 stickers to S, they would both have the same number
of stickers. P would then have half as many stickers as J.
If there were 280 stickers in the box in the end, how many stickers
did J and P have respectively at first.


So I figured out there is a total of 7u (J 3u, T 1u, P 1.5u+38, S 1.5u-38),
but I just couldn't figure out how to fit 280 into the model.

Hi BigDevil,

The total is always the same at 280. So you can draw 4 models for the 4 of them and the total is 280.

7u --> 280
1 u--> 280/7=40
Therefore,
J--> 3 units-->3X40=120
P--> 1.5 units +38--> 98

Hope that helps.

[BigDevil]

Eh??? The way I read the question is that 280 stickers were left over after distributing the stickers.


So 280 has always been the total number? That certainly makes the problem solvable.

Thanks!

[tracywham]

Hi, need help on this:


At a durian plantation, there were a number of durians on sale. For every 16 durians bought, 2 durians were given a way free. Mr Yusoff received a total of 96 durians free while Mr Hong received 112 durians free. If there were 45 durians left, how many durians were on sale?

(is there a faster way to solve this instead of drawing tables?)