Q&A - P5 Math

[MathIzzzFun]

PiscesLeo:

Keith puts some sweets into 3 bottles, A, B and C. The ratio of the number of sweets in bottle A and bottle B is 1:2. The ratio of the number of sweets in bottle B to bottle C is 3:2. If Keith transfers a number of sweets from bottle B to bottles A and C, she will have an equal number of sweets in the 3 bottles. The total number of sweets in bottle A will then increase by 24.


a) How many sweets were transferred from bottle B to bottle C?
b) What is the total number of sweets in the three bottles?

Please help. Thank you.

A: B --> 1:2
B: C --> 3:2

Make ratio part for B the same,
A:B:C --> 3 : 6 : 4 --> 9u : 18u : 12u -- total 39u

In the end,
A:B:C --> 13u : 13u : 13u

Number of sweets transferred from B to A --> 13u - 9u = 4u
Number of sweets transferred from B to C --> 13u - 12u = 1u

4u --> 24
1u --> 6

Number of sweets transferred from B to C --> 6
Total number of sweets in the bottles --. 39 x 6 = 234

cheers.

[smartmummy]

tianzhu:

Jamesbond:

Edmund sold cups and bowls for parties. The ratio of the price of a cup to the price of a bowl is 2:3. The price of the cup was $0.50 less than the price of the bowl. In january, Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in january were cups. Find the total no of items left after january?

pl help....

Hi

The ratio of the price of a cup to the price of a bowl is 2:3.

Cup:Bowl ----- 2:3

The price of the cup was $0.50 less than the price of the bowl.

Cup -----$1
Bowl ----- $1.5

Now you may work in dollars or change to cents. You may also use ”Number*Value” or “Grouping”

Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in January were cups.

A common multiple of 3 and 4 is 12.

Cups ------ 3 u
Bowls ----- 9 u
3u*1 + 9u*1.5 ------ 297

1u ------ 18

Number of cups ------ 54(3*18)
Number of bowls ----- 162(9*18)

3/5 ------- 216 (54+162)

2/5 ------ 144 (Number of items left after January)

Best wishes

A common multiple of 3 and 4 is 12.

Cups ------ 3 u
Bowls ----- 9 u I didn't understand here.Can anyone explain to me?

[PiscesLeo]

Thank you andyle.sg and MathIzzzFun

[tianzhu]

smartmummy:

I didn't understand here.Can anyone explain to me?

Hi

1/4 of the items sold in January were cups.

1/4 ----3/12

Cups ------ 3 u

Bowls ----- 9 u

Total ----- 12u

Best wishes

[smartmummy]

tianzhu:

smartmummy:

I didn't understand here.Can anyone explain to me?

Hi

1/4 of the items sold in January were cups.

1/4 ----3/12

Cups ------ 3 u

Bowls ----- 9 u

Total ----- 12u

Best wishes

:thankyou: tianzhu

[S-H]

Hi, can someone help me with this fraction question, thanks!


Ronald has 1/4 as many game cards as Terrence. If Terrence gives 117 game cards to Ronald, both of them will have an equal number of game cards. How many game cards must Terrence give to Ronald so that Ronald will have 5/8 as many game cards as Terrence?

[Oldschool]

S-H:

Hi, can someone help me with this fraction question, thanks!


Ronald has 1/4 as many game cards as Terrence. If Terrence gives 117 game cards to Ronald, both of them will have an equal number of game cards. How many game cards must Terrence give to Ronald so that Ronald will have 5/8 as many game cards as Terrence?

Hi,

(1) R : T = U : 4U

U + 117 = 4U - 117
U = 78

Total, 5U = 390

(2) Ronald has 5/8 as many cards as Terrence or Ronald has 5/13 of the total cards

5/13 x 390 = 150

150 - 78 = 72

Thus Terrence must give 72 cards to Ronald.

Regards

[S-H]

Hi Oldschool, thank u for your answer, but I still could not understand, can u explain in model method, thanks.

[PiscesLeo]

Tank A and tank B are identical. 5/6 of tank A and 1/4 of tank B are filled with water. The mass of tank B with its contents is 7/13 of the mass of tank A with it’s contents. The total mass of the two tanks with their contents is 1400g. Find the mass of the empty tank.


Please help. Thanks

[Oldschool]

S-H:

Hi Oldschool, thank u for your answer, but I still could not understand, can u explain in model method, thanks.

Hi,

Just like to point out that the 2nd scenario cannot be a continuous event from the 1st.

Because they are already equal when Terence gave 117 to Ronald.
So if Terence continued to give Ronald, Ronald would have more and not less than Terence.
Hence, it starts from the beginning again.

Hopefully the diagram helps.

http://i41.tinypic.com/sb2ey1.jpg\">

Regards