Q&A - P5 Math
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chloecube:
Three team A,B&C participated in a competition. There were 34 pupils in team B & C. If 22 pupil were not in team B n 28 pupil were in team C,how many pupil were there altogether in the three teams?
22 pupils not in Team B means
Team A & C --> 22
28 pupils not in Team C means
Team A & B --> 28
Team B & C --> 34
Total number of pupils in Team A & B & C --> (22 + 28 + 34) / 2 = 42
cheers. -
PiscesLeo:
BeginningKeith puts some sweets into 3 bottles, A, B and C. The ratio of the number of sweets in bottle A and bottle B is 1:2. The ratio of the number of sweets in bottle B to bottle C is 3:2. If Keith transfers a number of sweets from bottle B to bottles A and C, she will have an equal number of sweets in the 3 bottles. The total number of sweets in bottle A will then increase by 24.
a) How many sweets were transferred from bottle B to bottle C?
b) What is the total number of sweets in the three bottles?
Please help. Thank you.
A
c
3:6:4
End
A
c
1:1:1
Realize that the total is unchanged
A
c:t
3:6:4:13
1:1:1:3
Change to
A
c:t
9:18:12:39
13:13:13:39
Cheers -
PiscesLeo:
A: B --> 1:2Keith puts some sweets into 3 bottles, A, B and C. The ratio of the number of sweets in bottle A and bottle B is 1:2. The ratio of the number of sweets in bottle B to bottle C is 3:2. If Keith transfers a number of sweets from bottle B to bottles A and C, she will have an equal number of sweets in the 3 bottles. The total number of sweets in bottle A will then increase by 24.
a) How many sweets were transferred from bottle B to bottle C?
b) What is the total number of sweets in the three bottles?
Please help. Thank you.
B: C --> 3:2
Make ratio part for B the same,
A:B:C --> 3 : 6 : 4 --> 9u : 18u : 12u -- total 39u
In the end,
A:B:C --> 13u : 13u : 13u
Number of sweets transferred from B to A --> 13u - 9u = 4u
Number of sweets transferred from B to C --> 13u - 12u = 1u
4u --> 24
1u --> 6
Number of sweets transferred from B to C --> 6
Total number of sweets in the bottles --. 39 x 6 = 234
cheers. -
tianzhu:
A common multiple of 3 and 4 is 12.
HiJamesbond:
Edmund sold cups and bowls for parties. The ratio of the price of a cup to the price of a bowl is 2:3. The price of the cup was $0.50 less than the price of the bowl. In january, Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in january were cups. Find the total no of items left after january?
pl help....
The ratio of the price of a cup to the price of a bowl is 2:3.
Cup:Bowl ----- 2:3
The price of the cup was $0.50 less than the price of the bowl.
Cup -----$1
Bowl ----- $1.5
Now you may work in dollars or change to cents. You may also use ”Number*Value” or “Grouping”
Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in January were cups.
A common multiple of 3 and 4 is 12.
Cups ------ 3 u
Bowls ----- 9 u
3u*1 + 9u*1.5 ------ 297
1u ------ 18
Number of cups ------ 54(3*18)
Number of bowls ----- 162(9*18)
3/5 ------- 216 (54+162)
2/5 ------ 144 (Number of items left after January)
Best wishes
Cups ------ 3 u
Bowls ----- 9 u I didn't understand here.Can anyone explain to me? -
Thank you andyle.sg and MathIzzzFun
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smartmummy:
I didn't understand here.Can anyone explain to me?
Hi
1/4 of the items sold in January were cups.
1/4 ----3/12
Cups ------ 3 u
Bowls ----- 9 u
Total ----- 12u
Best wishes -
tianzhu:
:thankyou: tianzhusmartmummy:
I didn't understand here.Can anyone explain to me?
Hi
1/4 of the items sold in January were cups.
1/4 ----3/12
Cups ------ 3 u
Bowls ----- 9 u
Total ----- 12u
Best wishes -
Hi, can someone help me with this fraction question, thanks!
Ronald has 1/4 as many game cards as Terrence. If Terrence gives 117 game cards to Ronald, both of them will have an equal number of game cards. How many game cards must Terrence give to Ronald so that Ronald will have 5/8 as many game cards as Terrence? -
S-H:
Hi,Hi, can someone help me with this fraction question, thanks!
Ronald has 1/4 as many game cards as Terrence. If Terrence gives 117 game cards to Ronald, both of them will have an equal number of game cards. How many game cards must Terrence give to Ronald so that Ronald will have 5/8 as many game cards as Terrence?
(1) R : T = U : 4U
U + 117 = 4U - 117
U = 78
Total, 5U = 390
(2) Ronald has 5/8 as many cards as Terrence or Ronald has 5/13 of the total cards
5/13 x 390 = 150
150 - 78 = 72
Thus Terrence must give 72 cards to Ronald.
Regards -
Hi Oldschool, thank u for your answer, but I still could not understand, can u explain in model method, thanks.
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