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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      doraemo:
      please help:


      1.\tThere were some orange beads and 28 red beads and green beads in a container. There were two more green beads than red beads, and 6 fewer orange beads than red. How many beads were there altogether?
      28 red beads and green beads in a container. There were two more green beads than red beads.

      Red beads --> (28-2)/2 = 13
      Green beads --> 15
      Orange beads --> 13 - 6 = 7

      Total number of beads --> 28 + 7 = 35

      cheers.

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      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        doraemo:
        please help:


        2.\tJar Y has 22 more sweets than Jar Z and Jar Z has 16 more sweets than Jar X. The total number of sweets in Jars Y and Z is 5 times the number of sweets in Jar X.

        (a)\tHow many sweets are there altogether?
        (b)\tHow many sweets should be transferred from Jar Y to the other two Jars so that there is an equal number of sweets in all three jars?

        http://i39.tinypic.com/2yo506u.png\">

        3 units --> 16 x 2 + 22 = 54
        1 unit --> 18

        Jar X --> 18 sweets
        Jar Y --> 56 sweets
        Jar Z --> 34 sweets
        Total --> 108 sweets

        108 / 3 = 36

        Number of sweets to transfer:
        Jar Y to Jar Z --> 36 - 24 = 2 sweets
        Jar Y to Jar X --> 36 - 18 = 18 sweets
        Total transferred from Jar Y to Jar X & Jar Z --> 20 sweets

        cheers.

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        • D Offline
          doraemo
          last edited by

          Thank you very much, MathIzzzFun!!!

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          • AwonderA Offline
            Awonder
            last edited by

            Hi, pls help on the following Q. Thank you.


            Mrs Tan baked 186 chocolate cookies and peanut cookies. After 1/4 chocolate cookies were sold and 1/5 of the peanut cookies were sold, she had the same number of chocolate cookies and peanut cookies left. How many cookies were sold altogether?

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            • S Offline
              S-H
              last edited by

              Can someone please help me with this question, thanks!


              John bought 4 times as many candy bars as chocolate bars. The total mass of candy bars and chocolate bars was 1.64kg. The mass of chocolate bars was 0.84kg heavier than that of candy bars. The mass of 1 bar of chocolate was 0.228kg heavier than 1 candy bar. Find the number of chocolate bars John bought.

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              • P Offline
                php
                last edited by

                Awonder:
                Hi, pls help on the following Q. Thank you.


                Mrs Tan baked 186 chocolate cookies and peanut cookies. After 1/4 chocolate cookies were sold and 1/5 of the peanut cookies were sold, she had the same number of chocolate cookies and peanut cookies left. How many cookies were sold altogether?
                Chocolate -> 1 - 1/4 = 3/4 = 12/16
                Peanut -> 1 - 1/5 = 4/5 = 12/15

                16 units + 15 units -> 186
                31 units -> 186
                1 unit -> 6

                No of cookies sold (4 units + 3 units) -> 7 x 6 = 42

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                • A Offline
                  AtoZ
                  last edited by

                  Please help:


                  Q1. Three sisters Lisa, Ming and Nora shared the cost of a present for their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?

                  Q2. Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money. How much money was given to Jason at the beginning?

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                  • M Offline
                    Man_at_work
                    last edited by

                    Can anyone help me with this problem? Many thanks!


                    4 children Amos, Bala, Chris and Darren, each have some marbles. The number of marbles that Amos has is 1/2 of the total number of marbles that Bala, Chris and Darren have. The number of marbles that Chris has is 1/4 of the total Amos,Bala and Darren have. The number of marbles that Bala has is 2/3 of the total number of marbles that Amos, Chris and Darren have.

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                    • J Offline
                      jieheng
                      last edited by

                      S-H:
                      Can someone please help me with this question, thanks!


                      John bought 4 times as many candy bars as chocolate bars. The total mass of candy bars and chocolate bars was 1.64kg. The mass of chocolate bars was 0.84kg heavier than that of candy bars. The mass of 1 bar of chocolate was 0.228kg heavier than 1 candy bar. Find the number of chocolate bars John bought.
                      Candy bars 4u
                      Chocolate bars 1u

                      total mass of candy bars (4u) = (1.64 - 0.84) / 2 = 0.4

                      the mass of candy bars (1u) = 0.4 / 4 = 0.1

                      total mass of chocolate bars (1u) = 0.4 + 0.84 = 1.24

                      Difference between the mass of 1u of chocolate bars and candy bars
                      = 1.24 - 0.1
                      =1.14

                      Difference between the mass of 1 pc of chocolate bars and candy bars
                      =0.228

                      No of chocolate bars = 1.14 / 0.228 = 5 (Ans)

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                      • J Offline
                        jieheng
                        last edited by

                        AtoZ:
                        Please help:


                        Q1. Three sisters Lisa, Ming and Nora shared the cost of a present for their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?
                        Lisa 1u
                        (Ming + Nora) 4u
                        Total 5u

                        Ming 1u
                        (Lisa + Nora) 9u
                        Total 10u

                        Make the total the same , 10u

                        Lisa 2u
                        (Ming + Nora) 8u
                        Total 10u

                        Ming 1u
                        Lisa 2u
                        Nora 7u (10u - 1u - 2u)

                        7u - 1u = 6u

                        6u --> 60
                        1u --> 10

                        10u --> 10*10 = 100

                        The present cost $100

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