Q&A - P5 Math
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Can someone please help me with this question, thanks!
John bought 4 times as many candy bars as chocolate bars. The total mass of candy bars and chocolate bars was 1.64kg. The mass of chocolate bars was 0.84kg heavier than that of candy bars. The mass of 1 bar of chocolate was 0.228kg heavier than 1 candy bar. Find the number of chocolate bars John bought. -
Awonder:
Chocolate -> 1 - 1/4 = 3/4 = 12/16Hi, pls help on the following Q. Thank you.
Mrs Tan baked 186 chocolate cookies and peanut cookies. After 1/4 chocolate cookies were sold and 1/5 of the peanut cookies were sold, she had the same number of chocolate cookies and peanut cookies left. How many cookies were sold altogether?
Peanut -> 1 - 1/5 = 4/5 = 12/15
16 units + 15 units -> 186
31 units -> 186
1 unit -> 6
No of cookies sold (4 units + 3 units) -> 7 x 6 = 42 -
Please help:
Q1. Three sisters Lisa, Ming and Nora shared the cost of a present for their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?
Q2. Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money. How much money was given to Jason at the beginning? -
Can anyone help me with this problem? Many thanks!
4 children Amos, Bala, Chris and Darren, each have some marbles. The number of marbles that Amos has is 1/2 of the total number of marbles that Bala, Chris and Darren have. The number of marbles that Chris has is 1/4 of the total Amos,Bala and Darren have. The number of marbles that Bala has is 2/3 of the total number of marbles that Amos, Chris and Darren have. -
S-H:
Candy bars 4uCan someone please help me with this question, thanks!
John bought 4 times as many candy bars as chocolate bars. The total mass of candy bars and chocolate bars was 1.64kg. The mass of chocolate bars was 0.84kg heavier than that of candy bars. The mass of 1 bar of chocolate was 0.228kg heavier than 1 candy bar. Find the number of chocolate bars John bought.
Chocolate bars 1u
total mass of candy bars (4u) = (1.64 - 0.84) / 2 = 0.4
the mass of candy bars (1u) = 0.4 / 4 = 0.1
total mass of chocolate bars (1u) = 0.4 + 0.84 = 1.24
Difference between the mass of 1u of chocolate bars and candy bars
= 1.24 - 0.1
=1.14
Difference between the mass of 1 pc of chocolate bars and candy bars
=0.228
No of chocolate bars = 1.14 / 0.228 = 5 (Ans) -
AtoZ:
Lisa 1uPlease help:
Q1. Three sisters Lisa, Ming and Nora shared the cost of a present for their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?
(Ming + Nora) 4u
Total 5u
Ming 1u
(Lisa + Nora) 9u
Total 10u
Make the total the same , 10u
Lisa 2u
(Ming + Nora) 8u
Total 10u
Ming 1u
Lisa 2u
Nora 7u (10u - 1u - 2u)
7u - 1u = 6u
6u --> 60
1u --> 10
10u --> 10*10 = 100
The present cost $100 -
AtoZ:
Jason [][][][][1300]Please help:
Q2. Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money. How much money was given to Jason at the beginning?
Kevin [][]
Jason [][---3700---]
Kevin [][]
3u --> 3700 - 1300 =2400
1u --> 800
Jason --> 1u + 3700 = 800 + 3700 = 4500 -
jieheng:
Thank you for the easy solution.
Lisa 1uAtoZ:
Please help:
Q1. Three sisters Lisa, Ming and Nora shared the cost of a present for their father. Lisa paid 1/4 of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost?
(Ming + Nora) 4u
Total 5u
Ming 1u
(Lisa + Nora) 9u
Total 10u
Make the total the same , 10u
Lisa 2u
(Ming + Nora) 8u
Total 10u
Ming 1u
Lisa 2u
Nora 7u (10u - 1u - 2u)
7u - 1u = 6u
6u --> 60
1u --> 10
10u --> 10*10 = 100
The present cost $100 -
jieheng:
Jason [][][][][1300]AtoZ:
Please help:
Q2. Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money. How much money was given to Jason at the beginning?
Kevin [][]
Jason [][---3700---]
Kevin [][]
3u --> 3700 - 1300 =2400
1u --> 800
Jason --> 1u + 3700 = 800 + 3700 = 4500
Why at first you drew 4 boxes for Jason and 2 boxes for Kevin
But then 1 box for Jason and 2 for kelvin ? -
jieheng:
Candy bars 4uS-H:
Can someone please help me with this question, thanks!
John bought 4 times as many candy bars as chocolate bars. The total mass of candy bars and chocolate bars was 1.64kg. The mass of chocolate bars was 0.84kg heavier than that of candy bars. The mass of 1 bar of chocolate was 0.228kg heavier than 1 candy bar. Find the number of chocolate bars John bought.
Chocolate bars 1u
total mass of candy bars (4u) = (1.64 - 0.84) / 2 = 0.4
the mass of candy bars (1u) = 0.4 / 4 = 0.1
total mass of chocolate bars (1u) = 0.4 + 0.84 = 1.24
Difference between the mass of 1u of chocolate bars and candy bars
= 1.24 - 0.1
=1.14
Difference between the mass of 1 pc of chocolate bars and candy bars
=0.228
No of chocolate bars = 1.14 / 0.228 = 5 (Ans)
Thank you Jieheng!
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