Q&A - P5 Math
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jieheng:
Candy bars 4uS-H:
Can someone please help me with this question, thanks!
John bought 4 times as many candy bars as chocolate bars. The total mass of candy bars and chocolate bars was 1.64kg. The mass of chocolate bars was 0.84kg heavier than that of candy bars. The mass of 1 bar of chocolate was 0.228kg heavier than 1 candy bar. Find the number of chocolate bars John bought.
Chocolate bars 1u
total mass of candy bars (4u) = (1.64 - 0.84) / 2 = 0.4
the mass of candy bars (1u) = 0.4 / 4 = 0.1
total mass of chocolate bars (1u) = 0.4 + 0.84 = 1.24
Difference between the mass of 1u of chocolate bars and candy bars
= 1.24 - 0.1
=1.14
Difference between the mass of 1 pc of chocolate bars and candy bars
=0.228
No of chocolate bars = 1.14 / 0.228 = 5 (Ans)
Thank you Jieheng! -
AtoZ:
Jason [][][][][1300]jieheng:
[quote=\"AtoZ\"]Please help:
Q2. Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money. How much money was given to Jason at the beginning?
Kevin [][]
Jason [][---3700---]
Kevin [][]
3u --> 3700 - 1300 =2400
1u --> 800
Jason --> 1u + 3700 = 800 + 3700 = 4500
Why at first you drew 4 boxes for Jason and 2 boxes for Kevin
But then 1 box for Jason and 2 for kelvin ?[/quote]
If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money.
If Jason spent 1u of his money, then Kevin would spend 2u of his money ; Kevin's total money is 2u
If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money.
If Kevin spent all his money 2u , then Jason would spend double , 4u of his money and left $1300 -
Man_at_work:
Please, anybody can help? Thanks in advanceCan anyone help me with this problem? Many thanks!
4 children Amos, Bala, Chris and Darren, each have some marbles. The number of marbles that Amos has is 1/2 of the total number of marbles that Bala, Chris and Darren have. The number of marbles that Chris has is 1/4 of the total Amos,Bala and Darren have. The number of marbles that Bala has is 2/3 of the total number of marbles that Amos, Chris and Darren have. -
Mrs Tan bought 42 apples. Each apple costs $0.70 less than a pear. She spent the same amount of money on 12 pears. How much did Mrs Tan spend on buying the apples?
Please help to solve. Thanks. -
sembgal:
1A + 0.7 = 1PMrs Tan bought 42 apples. Each apple costs $0.70 less than a pear. She spent the same amount of money on 12 pears. How much did Mrs Tan spend on buying the apples?
Please help to solve. Thanks.
12A + 12*0.7 = 12P
12A + 8.4 = 12P
12A + 8.4 = 42A (the cost of 42 apples = the cost of 12 pears)
30A = 8.4
1A = 0.28
42A = 0.28*42 = 11.76
the amount of money she spent on buying the apples is $11.76 -
sembgal:
Mrs Tan bought 42 apples. Each apple costs $0.70 less than a pear. She spent the same amount of money on 12 pears. How much did Mrs Tan spend on buying the apples?
Please help to solve. Thanks.
cost of 12 pears = cost of 42 apples
cost of 1 pear = 7/2 x cost of 1 apple
cost of 1 pear --> 7 units
cost of 1 apple --> 2 units
5 units --> $0.70
1 unit --> $0.14
cost of 1 apple --> $0.28
Amount paid for the apples = 42 x $0.28 = $11.76
cheers. -
Man_at_work:
question is incomplete.. here's the approach to obtain the each's share of the marbles :
Please, anybody can help? Thanks in advanceMan_at_work:
Can anyone help me with this problem? Many thanks!
4 children Amos, Bala, Chris and Darren, each have some marbles. The number of marbles that Amos has is 1/2 of the total number of marbles that Bala, Chris and Darren have. The number of marbles that Chris has is 1/4 of the total Amos,Bala and Darren have. The number of marbles that Bala has is 2/3 of the total number of marbles that Amos, Chris and Darren have.
Amos's marbles --> 1/3 of total number -- Amos -> 1part, Bala+Chris+Darren-> 2parts, total -> 3 parts
Chris's marbles --> 1/5 of total number
Bala's marbles --> 2/5 of total number
1-1/3 -1/5-2/5 = 1/15
Darren's marbles --> 1/15 of total number
I believe you can work from here ..
cheers. -
Pls help to solve this question.
In a stadium, the number of girls is equal to the number of men. There are 252 females altogether. 7/9 of the children and 2/3 of the adults are females.
(a) Find the number of girls.
(b) Find the difference in the number of children and adults.
[Please use model approach]
TIA -
2Transformer:
(you can translate the solution to model easily)Pls help to solve this question.
In a stadium, the number of girls is equal to the number of men. There are 252 females altogether. 7/9 of the children and 2/3 of the adults are females.
(a) Find the number of girls.
(b) Find the difference in the number of children and adults.
[Please use model approach]
TIA
using equal fraction method:
7/9 children (girls) = 1/3 adults (men)
7/9 children = 7/21 adults
children --> 9 units, ----- girls : boys --> 7 units : 2 units
adults --> 21 units, ----- women : men --> 14 units : 7 units
Total number of females --> 21 units
21 units --> 252
1 unit --> 12
number of girls --> 7 x 12 = 84
Difference in number of adults and children --> (14 - 2) x 12 = 144
there are 144 more adults than children.
cheers. -
MathIzzzFun:
:thankyou: MathIzzzFun !
(you can translate the solution to model easily)2Transformer:
Pls help to solve this question.
In a stadium, the number of girls is equal to the number of men. There are 252 females altogether. 7/9 of the children and 2/3 of the adults are females.
(a) Find the number of girls.
(b) Find the difference in the number of children and adults.
[Please use model approach]
TIA
using equal fraction method:
7/9 children (girls) = 1/3 adults (men)
7/9 children = 7/21 adults
children --> 9 units, ----- girls : boys --> 7 units : 2 units
adults --> 21 units, ----- women : men --> 14 units : 7 units
Total number of females --> 21 units
21 units --> 252
1 unit --> 12
number of girls --> 7 x 12 = 84
Difference in number of adults and children --> (14 - 2) x 12 = 144
there are 144 more adults than children.
cheers.
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