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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • M Offline
      mathsguru
      last edited by

      headache:
      Question : FRom his pocket money, Victor spent thrice the amount that he could save every month. When he spent $20 less, he found he could save $40. How much was his pocket money?

      Hi Headache,

      Here's my solution. Hopefully you find it clear enough to understand.

      http://www.postimage.org/image.php?v=Ts6xzHS

      πŸ™‚
      MathsGuru

      1 Reply Last reply Reply Quote 0
      • M Offline
        mathsguru
        last edited by

        YLH88:
        Hi, need ur help with the below question :


        At present, Ronald is 3 times as old as his sister. In 22 years' time, Ronald's age will be 19 years less than twice his sister's age. How old is Ronald now ?
        Hi YLH88,

        Please see my solution below. Hope it helps!

        http://www.postimage.org/image.php?v=aV1cSFU0

        πŸ™‚
        MathsGuru

        1 Reply Last reply Reply Quote 0
        • K Offline
          kiasimom
          last edited by

          Hi mathsguru,


          Happy 2010 to you. Hope you have fully recovered from your sickness.

          We look forward to having you here at KSP to help us πŸ˜‰

          Take care :celebrate:

          1 Reply Last reply Reply Quote 0
          • M Offline
            mathsguru
            last edited by

            Dad fm East:
            1) At first, Jonathan had 2/3 as many stamps as Kevan. After Jonathan bought another 8 stamps and Kevan lost 5 stamps, Jonathan now has 4/5 as many stamps as Kevan. Find the number of stamps Jonathan had at first.


            2)At a school carnival, there were 520 more girls than boys. 1/8 of the girls and 1/5 of the boys left the carnival. In the end, there were 488 more girls than boys.
            a) How many more girls left?
            b) How many children were there in the carnival at the end?
            Hi Dad fm East,

            Here you go...hope the diagrams are clear enough for you and your ds to understand! πŸ™‚

            http://www.postimage.org/image.php?v=aV1dbZui

            http://www.postimage.org/image.php?v=aV1dbW_9

            Cheers,
            MathsGuru

            1 Reply Last reply Reply Quote 0
            • M Offline
              mathsguru
              last edited by

              parentof3:
              The cost of 3 similar watches and 4 similar rings is $218. Nancy bought 4 such watches and 3 such rings for $342. What is the cost of 2 such watches and 3 such rings.

              Hi Parentof3,

              Apologies but I can't seem to solve this question. If I'm not wrong, the question probably has an error because I can't obtain 2 positive answers for the prices. My answer is $102 for 1 watch and -$22 for 1 ring which is not logical. In any case, using the answers above, 2 watches and 3 rings will cost $$138.

              Any one else who can solve this without ending up with a negative answer? Will be really insightful to see the solution!

              πŸ™‚
              MathGuru

              1 Reply Last reply Reply Quote 0
              • M Offline
                mathsguru
                last edited by

                kiasimom:
                Hi mathsguru,


                Happy 2010 to you. Hope you have fully recovered from your sickness.

                We look forward to having you here at KSP to help us πŸ˜‰

                Take care :celebrate:
                Thanks alot Kiasimom! Still coughing a little, but at least I see signs of recovery already. πŸ™‚ Water is my best friend, especially since I have to talk alot during lessons...haha...

                Happy 2010 to you too!

                Cheers,
                MathsGuru

                1 Reply Last reply Reply Quote 0
                • T Offline
                  trytry
                  last edited by

                  Before


                  girls [5u+65][5u+65][5u+65][5u+65][5u+65][5u+65][5u+65][5u+65]


                  boys [8u ][8u ][8u ][8u ][8u ]----------------------520--------------------

                  (split the boys into 40 units and rearrange the girls as above)



                  After

                  girls [5u+65][5u+65][5u+65][5u+65][5u+65][5u+65][5u+65]


                  boys [8u ][8u ][8u ][8u ]--------------------488-------------------



                  girls: 5ux7 + 65x7 = 35u + 455

                  boys: 8ux4 =32u

                  35u + 455 -32u = 488

                  3u = 488-455
                  = 33
                  1u = 33 / 3 = 11

                  Total children at the end= 32u + 35u + 455
                  = 67u + 455
                  = 67x11 + 455
                  = 737 +455
                  = 1192


                  easier to understand?

                  mathsguru:
                  Dad fm East:

                  1) At first, Jonathan had 2/3 as many stamps as Kevan. After Jonathan bought another 8 stamps and Kevan lost 5 stamps, Jonathan now has 4/5 as many stamps as Kevan. Find the number of stamps Jonathan had at first.

                  2)At a school carnival, there were 520 more girls than boys. 1/8 of the girls and 1/5 of the boys left the carnival. In the end, there were 488 more girls than boys.
                  a) How many more girls left?
                  b) How many children were there in the carnival at the end?

                  Hi Dad fm East,

                  Here you go...hope the diagrams are clear enough for you and your ds to understand! πŸ™‚

                  http://www.postimage.org/image.php?v=aV1dbZui

                  http://www.postimage.org/image.php?v=aV1dbW_9

                  Cheers,
                  MathsGuru

                  1 Reply Last reply Reply Quote 0
                  • Y Offline
                    YLH88
                    last edited by

                    Hi Mathsguru,


                    Thank you for the explanation and solution.

                    Hope you have fully recovered 😎

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      Dharma
                      last edited by

                      mathsguru:
                      parentof3:

                      The cost of 3 similar watches and 4 similar rings is $218. Nancy bought 4 such watches and 3 such rings for $342. What is the cost of 2 such watches and 3 such rings.


                      Hi Parentof3,

                      Apologies but I can't seem to solve this question. If I'm not wrong, the question probably has an error because I can't obtain 2 positive answers for the prices. My answer is $102 for 1 watch and -$22 for 1 ring which is not logical. In any case, using the answers above, 2 watches and 3 rings will cost $$138.

                      Any one else who can solve this without ending up with a negative answer? Will be really insightful to see the solution!

                      πŸ™‚
                      MathGuru

                      Hi mathsguru,

                      You’re right …. there's an error in qn. Think the cost of 3 watches & 4 rings should be $281 instead of $218.

                      3W + 4R = 281
                      4W + 3 R = 342
                      7W + 7R = 623
                      1W + 1R = 89
                      1R = 281 – 3(89) = 14
                      1W = 89 – 14 = 75

                      So, 2W + 3R = 2(75) + 3(14) = 192

                      Cost of 2 watches & 3 rings will be $192.

                      1 Reply Last reply Reply Quote 0
                      • P Offline
                        parentof3
                        last edited by

                        Dharma:
                        Hi mathsguru,


                        You’re right …. there's an error in qn. Think the cost of 3 watches & 4 rings should be $281 instead of $218.

                        3W + 4R = 281
                        4W + 3 R = 342
                        7W + 7R = 623
                        1W + 1R = 89
                        1R = 281 – 3(89) = 14
                        1W = 89 – 14 = 75

                        So, 2W + 3R = 2(75) + 3(14) = 192

                        Cost of 2 watches & 3 rings will be $192.
                        Thanks dharma & mathsguru!

                        1 Reply Last reply Reply Quote 0

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