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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • H
      Hifive
      last edited by

      Hi CoffeeCat


      Thanks for your explanation.


      Hi mathsguru

      Thanks for your model and explanation.

      Cheers.

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      • P
        persistent
        last edited by

        A group of people met a party. Each person shook hands with everyone else. Mr Li shook hands with 3 times as many men as women. Mrs Li shook hands 4 times as many men as women. How many men and how many women were there at the party?



        …Men…Women
        Clue 1…1+3 units…1 unit
        Clue 2… 4 parts…1+1 part

        1 unit = 1+1 part;
        3 units = 3+3 parts

        1+3 units = 4 parts
        1+3+3 parts = 4 parts
        1 part = 1+3 = 4

        Ans.
        Men = 4 parts = 4 x 4 = 16
        Women = 1+1 part = 1 + 4 = 5

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        • H
          Hifive
          last edited by

          Hi persistent


          Thanks for your explanation.

          Cheers

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          • E
            eric2010
            last edited by

            Tanks X and Y are each filled with some water. If water from Tank Y is poured into Tank X unitl the water in Tank X reaches the brim, there will be 8 litres of water left in Tank Y. If water from Tank X is poured into Tank Y until the water in Tank Y reaches the brim, there will be 26 litres of water left in Tank X. The ratio of the volume of Tank X to the volume of Tank Y is 5:3. How many more litres of water are needed to fill both tanks to their brim ?

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            • O
              ooptimizer
              last edited by

              You need 19 litres to fill X and Y to the brim.

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              • E
                eric2010
                last edited by

                thx, i need the steps .

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                • CoffeeCatC
                  CoffeeCat
                  last edited by

                  I will solve using algebra. Let the amt of water in tank X & Y be x and y respectively.

                  Volume of tank Y = x+y -26
                  volume of tank X = x+ y -8
                  From here i use v to represent (x+y), because what x and y is wouldn’t matter,.
                  using the ratio, v-26= (3/5) * (v-8)
                  5v - 130 = 3v -24
                  2v= 106
                  v=53
                  Total volume of Tank X + Y = 2v - (26+8) = 2v -34 = 72
                  Water needed = 72 - 53 = 19.

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                  • M
                    mathsguru
                    last edited by

                    eric2010:
                    Tanks X and Y are each filled with some water. If water from Tank Y is poured into Tank X unitl the water in Tank X reaches the brim, there will be 8 litres of water left in Tank Y. If water from Tank X is poured into Tank Y until the water in Tank Y reaches the brim, there will be 26 litres of water left in Tank X. The ratio of the volume of Tank X to the volume of Tank Y is 5:3. How many more litres of water are needed to fill both tanks to their brim ?

                    Hi Eric2010,

                    Here's my solution. Hope you can understand the diagrams... 🙂

                    Cheers,
                    MathsGuru

                    http://www.postimage.org/image.php?v=TsIeCbA

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                    • P
                      persistent
                      last edited by

                      Tanks X and Y are each filled with some water. If water from Tank Y is poured into Tank X until the water in Tank X reaches the brim, there will be 8 litres of water left in Tank Y. If water from Tank X is poured into Tank Y until the water in Tank Y reaches the brim, there will be 26 litres of water left in Tank X. The ratio of the volume of Tank X to the volume of Tank Y is 5:3. How many more litres of water are needed to fill both tanks to their brim?



                      Scenario 1

                      …Tank X…Tank Y
                      Before…5 u - A…8 l + A\t\t\t\t
                      \t\t
                      …+ A…- A
                      \t\t
                      …

                      After…5 units…8 l
                      …




                      Scenario 2

                      …Tank X…Tank Y
                      Before…\t26 l + B…\t3 u - B
                      \t\t
                      …- B…+ B
                      \t\t
                      …


                      After…26 l…3 units
                      …



                      5 u – A = 26 l + B
                      5 u – 26 l = A + B


                      8 l + A = 3 u – B
                      A + B = 3 u – 8 l

                      5 u – 26 l = 3 u – 8 l
                      5 u – 3 u = 26 l – 8 l
                      2 u = 18 l
                      1 u = 9 l


                      Ans. A + B = 3 x 9 l – 8 l = 19 l

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                      • P
                        persistent
                        last edited by

                        Tanks X and Y are each filled with some water. If water from Tank Y is poured into Tank X until the water in Tank X reaches the brim, there will be 8 litres of water left in Tank Y. If water from Tank X is poured into Tank Y until the water in Tank Y reaches the brim, there will be 26 litres of water left in Tank X. The ratio of the volume of Tank X to the volume of Tank Y is 5:3. How many more litres of water are needed to fill both tanks to their brim?



                        Scenario 1

                        …Tank X…Tank Y
                        Before…5 u - A…8 l + A\t\t\t\t
                        \t\t
                        …+ A…- A
                        \t\t
                        …

                        After…5 units…8 l
                        …




                        Scenario 2

                        …Tank X…Tank Y
                        Before…\t26 l + B…\t3 u - B
                        \t\t
                        …- B…+ B
                        \t\t
                        …


                        After…26 l…3 units
                        …



                        5 u – A = 26 l + B
                        5 u – 26 l = A + B


                        8 l + A = 3 u – B
                        A + B = 3 u – 8 l

                        5 u – 26 l = 3 u – 8 l
                        5 u – 3 u = 26 l – 8 l
                        2 u = 18 l
                        1 u = 9 l


                        Ans. A + B = 3 x 9 l – 8 l = 19 l

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