Q&A - PSLE Math
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A few sample PSLE-type problems to test your child’s readiness to handle the PSLE using calculator as a tool. Not difficult but quite a good thinking exercise.
1.
Anthony, Bala and Caleb had some money. Bala gave $190 to Caleb. He then received 3/13 of Anthony’s money. Caleb then received 20% of Anthony’s money. In the end, 1/7 of Anthony’s money was given to Bala. Each of them had $1200 finally. How much did Bala and Caleb have altogether at first?
2.
Bella had saved a certain amount of money. In January, she spent 30% of her savings. In February, she managed to save 1/5 of the money she had left. Then she purchased 8 pens at $3.95 each. When she heard that her parents were going for a tour, she gave them 3/8 of the amount she had left. In March, she managed to save 40% of her savings and eventually she had $6219.85 in her bank account. How much was her original savings. -
Can help me to solve this question, ST Nick 2008 P6 SA1.
There are some rubber balls and plastic balls in a bag. If 1 rubber ball were to be removed from the bag, then 1/7 of the remaining balls in the bag would be rubber balls. If 2 plastic balls were to be removed from the bag instead of 1 rubber ball, then 1/5 of the balls left behind would be rubber balls. If another 5 rubber balls were to be put into the bag, what fraction of all the balls would be rubber balls?
TIA. -
underthesea i hope you understand my working=D
rubber: Total
1u+1: 7u+1 <<< no balls taken out because I add the 1 ball back.
after taking out 2 plastics balls, no of rubber remains. no. of total -2.
new ratio
1u+1:7u-1
but we also know that the fraction after taking out 2 plastic balls is 1/5 so…
1u+1:5u+5
From here we can actually see 7u-1 and 5u+5 is the same thing.
So… 5u+5=7u-1
u=3
no. of rubber balls = u+1=4
total no of balls= 7u+1=22
Checking…
when take out 1 rubber ball
no of rubber balls= 4-1=3
total no of balls= 22-1=21
fraction= 3/21=1/7(correct)
when take out 2 plastic balls
no of rubber balls= 4 unchanged
total no of balls = 22-2=20
fraction= 4/20=1/5(correct)
Since now it is correct, we need to complete the question.
add 5 rubber balls.
no of rubber balls =4+5=9
total no of balls= 22+5=27
fraction= 9/27=1/3
The ans is 1/3=D
hope it is understandable=D -
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Thanks Guan Hui and Maths Monster for your reply.
Here’s another problem I can’t solve. Need your help.
A class has 44 pupils. 3/4 of the boys and 2/5 of the girls are short-sighted. There are 26 boys and girls short-sighted. How many more boys than girls in the class. -
underthesea:
Hi underthesea,A class has 44 pupils. 3/4 of the boys and 2/5 of the girls are short-sighted. There are 26 boys and girls short-sighted. How many more boys than girls in the class.
I am the younger sister of Vanilla Cake and your question is similar to this question posted in another forum.
Hogwarts photography club has 1150 members.20% of the men and 25% of the women are non-professional photographers. A total of 250 members are non-professional photographers. How many more men than women are there in the club?
There are 2 different solutions given and let's wait for Guan Hui and Maths Monster to come up with preferably model solutions.
Solution 1
3/4 Boys + 2/5 Girls = 26 (Short-sighted)
Multiply by 5/2,
15/8 Boys + Girls = 65
Boys + Girls = 44
7/8 Boys =21
Boys = 24
Girls = 44-24=20
Difference = 24-20 = 4
There are 4 more boys than girls in the class.
Solution 2
Boys
S : N
3 : 1
Girls
S : N
2 : 3
S: Short-sighted
N: Normal vision
Since units for boys are not the same as units for girls, let's use u for Boys' units and p for Girls' units.
3u+2p = 26 (short-sighted)
1u+3p = 18 (normal vision) - *
* - (Multiply by 3)
3u+9p = 54
9p-2p = 54-26
7p = 28
p = 4
Girls: 5p = 5x4 = 20
Boys: 44-20 = 24
Difference = 24-20 = 4
There are 4 more boys than girls in the class.
Thank you. -
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Hi,
Thanks for your reply. If, say the child doesn't know how to do this question is exam. Given that the total number of pupils is not big, can the child use Guess and Check method to solve this problem?
We know the number of boys and girls must be a whole number and the number of boys is a factor of 4 while the number of girls is a factor of 5.
So, for boys => 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
for girls = > 5, 10, 15, 20, 25, 30, 35, 40
From the above, we can figure out 24 + 20 = 44. Hence, there are 4 more boys than girls.
Do you think marks will be awarded? :? -
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