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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • R Offline
      ruyu
      last edited by

      mathsguru:
      Dear all...


      Just to let you all know tt I'm back... :peekaboo:

      :imsorry: My sincere apologies for not being active for the past month. I've taken a 2-week break during the June hols and when I came back, I was busy conducting lessons. :faint:

      Finally can catch a breather now since school re-opened! Many thanks to all kind souls who have been helping out here...so many pages to catch up for me! πŸ˜“

      Hmm...guess I will start solving questions posted from now on instead of trying to catch up with the backlog. Hehe...Hope to seek your understanding!! :please:

      Cheers,
      MathsGuru

      Yeah Mathsguru is back!

      1 Reply Last reply Reply Quote 0
      • M Offline
        mathsguru
        last edited by

        Ngserene617:
        Hi kindly assist me for the below 3 stated questions, thanks.


        1. Alex, Bryan and Charles paid for a meal. Alex paid 1/5 of the amount Bryan and Charles paid together. Bryan paid 1/4 of the amount Alex and Charles paid. If the meal cost $205.20, how much did Alex pay ?

        2. Terry had $420 more than Sean. Sean gave Terry $72. Now, Sean has 1/7 as much money as Terry. How much money had Terry at first?

        3. 3 sisters, Amy, Bonnie and Cindy shared to buy a present for their mother. Amy paid 1/3 of the amount which Bonnie and Cindy paid. Bonnie paid 1/5 of the amount which Amy and Cindy paid. If Cindy paid $30 more than Bonnie, how much did the present cost?

        Thanks kindly help me to solve this !
        Hi Ngserene617,

        Since you have pm-ed me regarding these questions, I'm posting my solutions here for your reference (though they have been solved by other maths experts here). πŸ™‚

        Hope they can add to your child's understanding!

        Cheers,
        MathsGuru

        http://www.postimage.org/image.php?v=aVzUgIi

        http://www.postimage.org/image.php?v=aVzUjcr

        http://www.postimage.org/image.php?v=aVzUobJ

        1 Reply Last reply Reply Quote 0
        • L Offline
          livewith_vanilla
          last edited by

          Here is a question I would like some help in.


          Source: School paper
          Level: P6

          A train traveled through a 6500-metre tunnel at an average speed of 25m/s. The whole train took 4 min 30 s to pass through the tunnel completely.
          What is the length of the train?

          TIA.

          1 Reply Last reply Reply Quote 0
          • M Offline
            MOE Hater
            last edited by

            livewith_vanilla:
            Here is a question I would like some help in.


            Source: School paper
            Level: P6

            A train traveled through a 6500-metre tunnel at an average speed of 25m/s. The whole train took 4 min 30 s to pass through the tunnel completely.
            What is the length of the train?

            TIA.
            25m/s x 4 min 30 s = 25m/s x 270s = 6750m
            6750m - 6500m = 250m

            The train is 250m long.

            1 Reply Last reply Reply Quote 0
            • M Offline
              mathsguru
              last edited by

              livewith_vanilla:
              Here is a question I would like some help in.


              Source: School paper
              Level: P6

              A train traveled through a 6500-metre tunnel at an average speed of 25m/s. The whole train took 4 min 30 s to pass through the tunnel completely.
              What is the length of the train?

              TIA.
              Hi livewith_vanilla,

              Here's my solution. Hope it helps!

              πŸ™‚
              MathsGuru

              http://www.postimage.org/image.php?v=gxuHLp0

              1 Reply Last reply Reply Quote 0
              • L Offline
                livewith_vanilla
                last edited by

                mathsguru:
                livewith_vanilla:

                Here is a question I would like some help in.


                Source: School paper
                Level: P6

                A train traveled through a 6500-metre tunnel at an average speed of 25m/s. The whole train took 4 min 30 s to pass through the tunnel completely.
                What is the length of the train?

                TIA.

                Hi livewith_vanilla,

                Here's my solution. Hope it helps!

                πŸ™‚
                MathsGuru

                http://www.postimage.org/image.php?v=gxuHLp0

                Thanks very much!

                Edit: My solution was the same, though I didn't get it. Now i understand.:D

                1 Reply Last reply Reply Quote 0
                • A Offline
                  Almighty
                  last edited by

                  liketoeat:
                  Dharma:

                  [quote=\"liketoeat\"]Hi, please help me solve this question. Thank you.


                  Candle A and candle B were placed on a table. Candle A was 1.5 cm longer than candle B. Candle A and candle B were lighted at 0630 h and 0800 h respectively. They burnt down to the same length at 1030 h. At 1200 h, candle B was burnt out while A only burnt out at 1230 h. Given that the rate of burning of each candle was constant throughout, find the original length of each candle. (Ans: candle A 13.5 cm; candle B 12 cm)

                  Time ratio => A : B = 4 : 3
                  Burning rate ratio => A : B = 3 : 4

                  Time taken to burn completely
                  A : 6 hrs (0630hrs to 1230hrs)
                  B : 4 hrs (0800hrs to 1200hrs)

                  Length (A ) = 3u x 6 = 18u
                  Length (B) = 4u x 4 = 16u

                  18u – 16u = 2u = 1.5cm
                  Original Length (A) = 18u = 9 x 1.5cm = 13.5cm
                  Original Length (B) = 16u = 8 x 1.5cm = 12.0cm

                  Thank you, Dharma.[/quote]Hi Dharma,
                  Can u pls. explain how u get this step? :?
                  Time ratio => A : B = 4 : 3

                  1 Reply Last reply Reply Quote 0
                  • M Offline
                    Maths Monster
                    last edited by

                    mathsguru:
                    Dear all...


                    Just to let you all know tt I'm back... :peekaboo:

                    :imsorry: My sincere apologies for not being active for the past month. I've taken a 2-week break during the June hols and when I came back, I was busy conducting lessons. :faint:

                    Finally can catch a breather now since school re-opened! Many thanks to all kind souls who have been helping out here...so many pages to catch up for me! πŸ˜“

                    Hmm...guess I will start solving questions posted from now on instead of trying to catch up with the backlog. Hehe...Hope to seek your understanding!! :please:

                    Cheers,
                    MathsGuru
                    Now that you are back, I will stop posting in your thread. Hope I have help some people here and not be a busy body...anyway, good luck. Cheers, MM

                    Add - It comes to my notice that when I attached images to some of my previous post, I think some setting are not selected correctly in the \"Add image to post\" option. Hence resulting in unwanted image. I apologize for this. This was never intentional. I have removed all the attachments as best I can. Sorry to all for any inconvenience caused.

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      Dharma
                      last edited by

                      Almighty:
                      liketoeat:

                      [quote=\"Dharma\"]
                      Time ratio => A : B = 4 : 3
                      Burning rate ratio => A : B = 3 : 4

                      Time taken to burn completely
                      A : 6 hrs (0630hrs to 1230hrs)
                      B : 4 hrs (0800hrs to 1200hrs)

                      Length (A ) = 3u x 6 = 18u
                      Length (B) = 4u x 4 = 16u

                      18u – 16u = 2u = 1.5cm
                      Original Length (A) = 18u = 9 x 1.5cm = 13.5cm
                      Original Length (B) = 16u = 8 x 1.5cm = 12.0cm

                      Thank you, Dharma.

                      Hi Dharma,
                      Can u pls. explain how u get this step? :?
                      Time ratio => A : B = 4 : 3[/quote]Hi Almighty,

                      At 1030hrs, both candles had the same length.

                      Candles A takes 2 hrs to burn out ( 1030hrs to 1230hrs ) and candle B takes 1.5 hrs to burn out (1030hrs to 1200hrs).
                      So, Time ratio => Candle A : Candle B = 2 : 1.5 = 4 : 3

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        mathsguru
                        last edited by

                        Maths Monster:
                        Now that you are back, I will stop posting in your thread. Hope I have help some people here and not be a busy body...anyway, good luck. Cheers, MM


                        Add - It comes to my notice that when I attached images to some of my previous post, I think some setting are not selected correctly in the \"Add image to post\" option. Hence resulting in unwanted image. I apologize for this. This was never intentional. I have removed all the attachments as best I can. Sorry to all for any inconvenience caused.
                        Hey Maths Monster,

                        Please don't say that! This is not \"my\" thread. It's a learning place for everyone. Your contributions have been priceless (definitely not a busybody!!)! Please do continue to drop by as and when you feel like it and provide your inputs! πŸ™‚

                        As for the attachments, they happen to me and many others too. I'm no IT expert, so my postings are also at the \"mercy\" of the website...haha! I usually choose \"do not resize my image\"...and hopefully it comes out alright.

                        So, please don't say you're a busybody or that you have caused us any inconvenience...cos u have been nothing but a gem here! Looking forward to seeing you ard here! :please:

                        Cheers,
                        MathsGuru

                        1 Reply Last reply Reply Quote 0

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