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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • corneyAmberC
      corneyAmber
      last edited by

      Actually the second method i gave is the same as yours and it is not necessary to find the cost for 1, you can directly give the answer for 2 of each item.


      Also in method 1, I was not thinking of simultaneous equation, I was using common sense but I guess it looked like simultaneous equation. :lol:

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      • D
        Dharma
        last edited by

        Devnahouse:
        Hello,

        Can help me solve this one.

        The cost of 7 erasers and 3 rulers is $5.05.
        The cost of 2 erasers and 6 rulers is $3.95
        Find the cost of 2 erasers and 2 rules.

        Many thanks.
        http://www.postimage.org/image.php?v=TsKNGfA

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        • D
          Devnahouse
          last edited by

          Dharma, Thanks for taking time to explain in model form. Thanks ksi for your further clarifications. Appreciated.

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          • B
            buds
            last edited by

            Easiest method to solve this one?


            A snail climbed 1cm up a wall in Day 1,
            2cm in Day 2, 3cm in Day 3 and so on..

            Each day, it climbed 1cm more than it did
            the previous day. How many days did the
            snail take to climb 21cm?

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            • D
              Dharma
              last edited by

              buds:
              Easiest method to solve this one?


              A snail climbed 1cm up a wall in Day 1,
              2cm in Day 2, 3cm in Day 3 and so on..

              Each day, it climbed 1cm more than it did
              the previous day. How many days did the
              snail take to climb 21cm?
              Hi Buds

              Easiest way is by listing

              Day 1 => 1
              Day 2 => 1 + 2 = 3
              Day 3 => 1 + 2 + 3 = 6
              Day 4 => 1 + 2 + 3 + 4 = 10
              Day 5 => 1 + 2 + 3 + 4 + 5 = 15
              Day 6 => 1 + 2 + 3 + 4 + 5 + 6 = 21

              The snail took 6 days to climb 21cm

              But if we have a large number, eg number of days taken by the snail to climb 210cm; using listing method will be very time consuming.

              We need to establish a pattern

              This is a question a series of consecutive numbers starting from 1

              1 + 2 + 3 + ….+ N = N x (N + 1)/2

              So, to find no. of days for snail to climb 210cm

              N x (N +1 ) / 2 = 210
              N x ( N + 1 ) = 420

              We know 20 x 21 = 420

              N = 20

              So, in 20 days the snail will be able to climb 210cm

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              • M
                Muffins
                last edited by

                Hi Dharma.


                Sorry to be a buzzkill, but the actual question was 21 cm, not 210 cm…

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                • D
                  Dharma
                  last edited by

                  Muffins:
                  Hi Dharma.


                  Sorry to be a buzzkill, but the actual question was 21 cm, not 210 cm....

                  Hi Muffins,

                  To climb 21cm

                  N x (N + 1) / 2 = 21

                  N x (N + 1) = 42
                  6 x 7 = 42
                  N = 6 days

                  By using 210cm I was trying to show that it will be easier to solve the problem by finding a pattern. The listing method will
                  be just too long.

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                  • I
                    imacsg
                    last edited by

                    Can you help to explain why is it wrong.


                    I am a 3 digit number.
                    My hundreds and tens digit are the same.
                    My ones digit is 4 more than my tens digit.
                    What number can I be?

                    My son writes 448, but the teacher marked it wrong and said the correct ans is 559. I thought the ans can be either 559, 448, 337, 226 or 115

                    Thanks

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                    • S
                      singmathstutor
                      last edited by

                      imacsg:
                      Can you help to explain why is it wrong.


                      I am a 3 digit number.
                      My hundreds and tens digit are the same.
                      My ones digit is 4 more than my tens digit.
                      What number can I be?

                      My son writes 448, but the teacher marked it wrong and said the correct ans is 559. I thought the ans can be either 559, 448, 337, 226 or 115

                      Thanks
                      Based on the question that you have written, there are a few possible solutions as you have mentioned. Your son's answer is correct.

                      P.S. Can mod please transfer this post to the correct thread if needed. Thanks

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                      • I
                        imacsg
                        last edited by

                        Hi All,

                        Thanks for the prompt reply. It is P3 question. I will check with the Teacher why he insists 559 the correct answer.

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