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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • S Offline
      super star
      last edited by

      thanks Dharma

      Dharma:
      livewith_vanilla:

      Hi Superstar,


      Your questions seem to come from Henry Park Preliminary Paper 2 2009.

      The solution for Q14 as stated on the answer key is:

      105%G+90% G+18=408
      195%G+18=408
      100%G=390/195x100=200
      200x2+20=420
      420x8=3360

      Ans: $3360

      For reference, the question is as of below:

      Cinema admission tickets for children were priced at $8 each.there were 20 more than girls inthe cinema for the movie. For the second movie ,the number of boys decreased by 10% but the number of girls increased by 5%.if there were 408 children at the second movie, how much money was collected from the sales of admission ticket for the first movie?

      For Q15, the answer key did not provide any solutions. But I'm able to solve (A). The answers are (a)5:1 and (b)150

      For reference, the question is as of below:
      A librarian counted the number of adults in the library and found that 2/5 of the number of women was equal to 2 times the number of men.when another 12 men entered the library and 45 women left the library, the ratio of the number of women to the number of men became 5:2.

      (A) what was the ratio of the number of women at first to the number of men at first?give youir answer in its simplest form.

      (B)find the number of women in the library at first.

      2/5W=2 M
      1/5W=1 M

      W:M
      5:1

      Ans: 5:1

      However, I am too unable to solve (B). The answer I got was 105 and not 150. Thus my apologies.

      Are you a primary 6 student or a parent?

      Hi superstar and livewith_vanilla,

      Hope this helps.

      At first
      Ratio => Women : Men = 5 : 1

      At last
      Ratio => Women : Men = 5u - 45 : 1u + 12 = 5 : 2

      10u – 90 = 5u + 60
      5u = 150
      1u = 30

      No. of women at first = 5u = 5 x 30 = 150

      1 Reply Last reply Reply Quote 0
      • L Offline
        livewith_vanilla
        last edited by

        super star:
        Hi livewith_vanilla

        Thank you very much
        Iam a parent who is studying p6 :lol:
        please explain how u got 105%G+90% G+18=408
        I cannot understand what how u got 90%G+18
        livewith_vanilla:

        Hi Superstar,

        Your questions seem to come from Henry Park Preliminary Paper 2 2009.

        The solution for Q14 as stated on the answer key is:

        105%G+90% G+18=408
        195%G+18=408
        100%G=390/195x100=200
        200x2+20=420
        420x8=3360

        Ans: $3360

        For reference, the question is as of below:

        Cinema admission tickets for children were priced at $8 each.there were 20 more than girls inthe cinema for the movie. For the second movie ,the number of boys decreased by 10% but the number of girls increased by 5%.if there were 408 children at the second movie, how much money was collected from the sales of admission ticket for the first movie?

        For Q15, the answer key did not provide any solutions. But I'm able to solve (A). The answers are (a)5:1 and (b)150

        For reference, the question is as of below:
        A librarian counted the number of adults in the library and found that 2/5 of the number of women was equal to 2 times the number of men.when another 12 men entered the library and 45 women left the library, the ratio of the number of women to the number of men became 5:2.

        (A) what was the ratio of the number of women at first to the number of men at first?give youir answer in its simplest form.

        (B)find the number of women in the library at first.

        2/5W=2 M
        1/5W=1 M

        W:M
        5:1

        Ans: 5:1

        However, I am too unable to solve (B). The answer I got was 105 and not 150. Thus my apologies.

        Are you a primary 6 student or a parent?

        A parent studying p6? wow

        If you draw the model,

        You will see that at first,

        girls=100%
        boys=100%+20

        On the second day,

        girls increase by 5%, thus the final percentage of girls is 105%.

        boys decrease by 10%, this final percentage is 90%+(90/100x20)

        1 Reply Last reply Reply Quote 0
        • C Offline
          clblinym
          last edited by

          Hi, Parents


          Can anyone help solve the following math question. Many thanks.

          The answer given is 5:2.

          Amy
          http://www.postimage.org/image.php?v=aVi95Tr

          1 Reply Last reply Reply Quote 0
          • C Offline
            catddy2002
            last edited by

            Hi,


            How to solve this questions:

            1) 3/4 of a cake was cut into 8 pieces. What fraction f the cake is each of the 8 pieces?

            1) 1/8
            2) 3/8
            3) 3/32
            4) 29/32 ( )

            2) What is twice the sum of 20 hundreths, 5 tenths and 17 ones?

            1) 17.25
            2) 17.70
            3) 222
            4) 2022 ( )

            1 Reply Last reply Reply Quote 0
            • starlight1968sgS Offline
              starlight1968sg
              last edited by

              catddy2002:
              1) 3/4 of a cake was cut into 8 pieces. What fraction f the cake is each of the 8 pieces?


              1) 1/8
              2) 3/8
              3) 3/32
              4) 29/32 ( )

              2) What is twice the sum of 20 hundreths, 5 tenths and 17 ones?

              1) 17.25
              2) 17.70
              3) 222
              4) 2022 ( )
              1) (3/4) / 8 = (3 / 4) * (1 /8 ) = 3/32
              2) 20 hundredths = 0.20,
              5 tenths = 0.5
              17 ones = 17
              the sum is 17.7.
              Then twice is 17.7 * 2 = ???

              1 Reply Last reply Reply Quote 0
              • M Offline
                maths6a
                last edited by

                Dharma:
                maths6a:

                Hi Can anyone help with this question?

                How many 3-digit number combinations are there on a 3-digit number lock if all the 3-digits used are different and the numbers are greater than 800?

                Thanks.

                Digit in hundreds place => 8 or 9
                Digit in tens place => 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9
                Digit in ones place => 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9

                Since the 3 digits used are different, you have 2 choices for hundreds place, 9 choices for tens place(1 choice already selected for 100s place) and 8 choices for the ones place (2 choices already chosen for 100s and 10s place)

                No. of combinations = 2 x 9 x 8 = 144

                Thanks for your solution. Will study it.

                1 Reply Last reply Reply Quote 0
                • D Offline
                  Dharma
                  last edited by

                  clblinym:
                  Hi, Parents


                  Can anyone help solve the following math question. Many thanks.

                  The answer given is 5:2.

                  Amy
                  http://www.postimage.org/image.php?v=aVi95Tr
                  Ratio of Area of AEB : Area of AEC : Area of ADE = 1 : 4 : 2

                  Area of ABC = 1/2 X AB x Perpendicular Height
                  Area of ADC = 1/2 x DC x Perpendicular Height

                  AB : DC = Area of ABC : Area of ADC = (1+4 ) : 2 = 5 : 2

                  1 Reply Last reply Reply Quote 0
                  • D Offline
                    Dharma
                    last edited by

                    super star:
                    Please help me with this problem

                    cinema admission tickets for children were priced at $8 each.there were 20 more than girls inthe cinema for the movie. For the second movie ,the number of boys decreased by 10% but the number of girls increased by 5%.if there were 408 children at the second movie, how much money was collected from the sales of admission ticket for the first movie?
                    Movie 1
                    Boys : 20u
                    Girls : 20u + 20

                    Movie 2
                    Boys : 18u + 18
                    Girls : 21u

                    18u + 18 + 21u = 408
                    39u = 390
                    1u = 10

                    Collection for Movie 1 = (40u + 20) x $8 = 420 x $8 = $3,360

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      catddy2002
                      last edited by

                      starlight1968sg:
                      catddy2002:

                      1) 3/4 of a cake was cut into 8 pieces. What fraction f the cake is each of the 8 pieces?


                      1) 1/8
                      2) 3/8
                      3) 3/32
                      4) 29/32 ( )

                      2) What is twice the sum of 20 hundreths, 5 tenths and 17 ones?

                      1) 17.25
                      2) 17.70
                      3) 222
                      4) 2022 ( )


                      1) (3/4) / 8 = (3 / 4) * (1 /8 ) = 3/32
                      2) 20 hundredths = 0.20,
                      5 tenths = 0.5
                      17 ones = 17
                      the sum is 17.7.
                      Then twice is 17.7 * 2 = ???


                      Thanks, starlight1968sg! πŸ˜„

                      For question 2, I did what you stated before asking this question in this forum. But the ans not in the mulitple choice, so i state in this forum to confirm that I'm right. That's printing error for this question.

                      1 Reply Last reply Reply Quote 0
                      • A Offline
                        acehkr3009
                        last edited by

                        Hi,


                        Need some help on this question.

                        Not sure why question appear so small.

                        Here is the retype of the question:

                        If W & Y is the mid-point of AB and CD respectively, and Z & X are any points along AD and BC respectively. What is the fraction of the shaded portion ?

                        Thanks.

                        http://www.postimage.org/image.php?v=Ts7ucsS

                        1 Reply Last reply Reply Quote 0

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