Tutor MathsGuru: Ask me for your burning Maths questions!

[Dharma]

clblinym:

Hi, Parents


Can anyone help solve the following math question. Many thanks.

The answer given is 5:2.

Amy
http://www.postimage.org/image.php?v=aVi95Tr

Ratio of Area of AEB : Area of AEC : Area of ADE = 1 : 4 : 2

Area of ABC = 1/2 X AB x Perpendicular Height
Area of ADC = 1/2 x DC x Perpendicular Height

AB : DC = Area of ABC : Area of ADC = (1+4 ) : 2 = 5 : 2

[Dharma]

super star:

Please help me with this problem

cinema admission tickets for children were priced at $8 each.there were 20 more than girls inthe cinema for the movie. For the second movie ,the number of boys decreased by 10% but the number of girls increased by 5%.if there were 408 children at the second movie, how much money was collected from the sales of admission ticket for the first movie?

Movie 1
Boys : 20u
Girls : 20u + 20

Movie 2
Boys : 18u + 18
Girls : 21u

18u + 18 + 21u = 408
39u = 390
1u = 10

Collection for Movie 1 = (40u + 20) x $8 = 420 x $8 = $3,360

[catddy2002]

starlight1968sg:

catddy2002:

1) 3/4 of a cake was cut into 8 pieces. What fraction f the cake is each of the 8 pieces?


1) 1/8
2) 3/8
3) 3/32
4) 29/32 ( )

2) What is twice the sum of 20 hundreths, 5 tenths and 17 ones?

1) 17.25
2) 17.70
3) 222
4) 2022 ( )

1) (3/4) / 8 = (3 / 4) * (1 /8 ) = 3/32
2) 20 hundredths = 0.20,
5 tenths = 0.5
17 ones = 17
the sum is 17.7.
Then twice is 17.7 * 2 = ???

Thanks, starlight1968sg!

For question 2, I did what you stated before asking this question in this forum. But the ans not in the mulitple choice, so i state in this forum to confirm that I'm right. That's printing error for this question.

[acehkr3009]

Hi,


Need some help on this question.

Not sure why question appear so small.

Here is the retype of the question:

If W & Y is the mid-point of AB and CD respectively, and Z & X are any points along AD and BC respectively. What is the fraction of the shaded portion ?

Thanks.

http://www.postimage.org/image.php?v=Ts7ucsS

[acehkr3009]

Hi Parents,


Here is a question fr my son’s math assignment, which I think may be incorrect…need your advise…

The average of a set of 4 numbers is M. If 79 is added to this set of number, the average becomes M + 3. What is the value of M?

Thanks.

[atutor2001]

acehkr3009:

Hi Parents,


Here is a question fr my son's math assignment, which I think may be incorrect...need your advise..

The average of a set of 4 numbers is M. If 79 is added to this set of number, the average becomes M + 3. What is the value of M?

Thanks.

Hi, if I am not wrong M=64. The working goes like this :

New average (M+3) = 79 - (3x4) = 67
Old average (M) = 67 - 3 = 64

[Muffins]

Wow, thanks.


Was a little :? :?: with that problem. Couldn't figure out the connection between the working I had gotten, but you condensed it into two main steps. :thankyou: :thankyou:

[Tang]

atutor2001:

acehkr3009:

Hi Parents,


Here is a question fr my son's math assignment, which I think may be incorrect...need your advise..

The average of a set of 4 numbers is M. If 79 is added to this set of number, the average becomes M + 3. What is the value of M?

Thanks.

Hi, if I am not wrong M=64. The working goes like this :

New average (M+3) = 79 - (3x4) = 67
Old average (M) = 67 - 3 = 64

Hi,


Total of 4 numbers --> 4M

Total of 5 numbers --> 5M + 5 x 3 = 5M + 15

So 5th number --> 5M + 15 - 4M = M + 15

M + 15 --> 79
M --> 79 - 15 = 64

[beauty queen]

Please help me with this question,


There are some black and white marbles in a bag. If 20 black marbles are removed from the bag, the total number of marbles left will be 7 times the number of black marbles left. If 50 white marbles are removed from the bag, the total number of marbles left will be 5 times the number of black marbles left. How many marbles are there in the bag.

[clblinym]

Dharma:

clblinym:

Hi, Parents


Can anyone help solve the following math question. Many thanks.

The answer given is 5:2.

Amy
http://www.postimage.org/image.php?v=aVi95Tr

Ratio of Area of AEB : Area of AEC : Area of ADE = 1 : 4 : 2

Area of ABC = 1/2 X AB x Perpendicular Height
Area of ADC = 1/2 x DC x Perpendicular Height

AB : DC = Area of ABC : Area of ADC = (1+4 ) : 2 = 5 : 2

Dear Dharma,
Thank you so much for your great help.
My son and I fully understand your explanation.
We really appreciate your helpfullness.

I just want to check with you if it is a typo for the sentence.
Ratio of Area of AEB : Area of AEC : Area of ADC = 1 : 4 : 2