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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • L Offline
      laikiasu
      last edited by

      Hi Mathsgurus out there,


      Qn: Mrs Ong owns 3 dogs. Each dog gave birth to 3 puppies and when the puppies grew up, they each gave birth to 3 puppies. How many dogs does Mrs Ong own now?
      Ans: 18 (found in answer page) but my own answer was 39.

      Can you help tell me how to get 18? Or is there a printing error in the answer page?

      Thanks.

      Rgds,
      laikiasu

      1 Reply Last reply Reply Quote 0
      • M Offline
        Muffins
        last edited by

        laikiasu:
        Hi Mathsgurus out there,


        Qn: Mrs Ong owns 3 dogs. Each dog gave birth to 3 puppies and when the puppies grew up, they each gave birth to 3 puppies. How many dogs does Mrs Ong own now?
        Ans: 18 (found in answer page) but my own answer was 39.

        Can you help tell me how to get 18? Or is there a printing error in the answer page?

        Thanks.

        Rgds,
        laikiasu
        Hi laikiasu, I think you got 39 by this method, right?

        3 x 3 = 9
        9 x 3 = 27
        9 + 3 + 27 = 39

        It is the correct answer. 18 is wrong... 🙂

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        • N Offline
          Ngserene617
          last edited by

          mathsguru:
          Original Title: Let MathsGuru Answer Your Burning Maths Questions!


          :welcome:

          Dear Parents,

          Are you frustrated/stuck when helping your child solve his/her Maths questions? Are you inclined to use Algebra most of the time? Do you have difficulty trying to use diagrams or other heuristic methods (that Primary School students learn) to solve?

          :idea: Post your questions here and see how MathsGuru solve them to the best of her ability. Detailed solutions will be posted back in this thread.


          Hi Mathsguru,
          pls help me this ques:
          1. There were a total of 2244 men and women in the hall. 1/3 of the men is equal to 5/7 of the women.
          a) how many men were in the hall?
          b) how many more men than women were in the hall ?

          Thanks


          So start asking and watch this space!!

          Cheers :celebrate: ,
          MathsGuru

          P/S (Disclaimer, in case you're wondering...):
          Although MathsGuru is a full-time Maths tutor, this thread is meant to be an absolutely free resource for parents (or even children) with no strings attached. Just someone who's passionate about Maths and wanna spread the fun in learning Maths with others. 😄

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          • L Offline
            laikiasu
            last edited by

            Thank you Muffins!

            Yup that's how I worked out the answer. I doubted myself cos all the other answers in the exercise were correct except this one...hee.

            :celebrate: Cheers!

            1 Reply Last reply Reply Quote 0
            • A Offline
              Almighty
              last edited by

              Hi all,

              The question :
              A rectangular block of wood, 47 cm long, 38 cm wide, and 24 cm high , was cut into equal cubes of edge 4 cm.
              a) What was the maximum number of 4cm cubes which I could cut?
              b) What was the total surface area of the remaining piece of wood?

              a) my answer : 594 cubes
              b) Book answer : 256cm2. My answer is different.Can anyone halp on
              section(B)
              Thankyou in advance…

              1 Reply Last reply Reply Quote 0
              • Y Offline
                Yu Xuan
                last edited by

                1. There were a total of 2244 men and women in the hall. 1/3 of the men is equal to 5/7 of the women.

                a) how many men were in the hall?
                b) how many more men than women were in the hall ?


                Let me try…

                To start off, make the numerator of both fractions equal and the denominators will represent the total units for men and women respectively.

                Men –> 1/3 = 5/15
                Women –> 5/7
                Total –> 7 units + 15 units = 22 units

                Part (a)
                22 units –> 2244
                15 units –> 2244/22 * 15 = 1530

                Part (b)
                15 units - 7 units = 8 units
                8 units –> 2244/22 * 8 = 816

                1 Reply Last reply Reply Quote 0
                • N Offline
                  Ngserene617
                  last edited by

                  Yu Xuan:
                  1. There were a total of 2244 men and women in the hall. 1/3 of the men is equal to 5/7 of the women.

                  a) how many men were in the hall?
                  b) how many more men than women were in the hall ?


                  Let me try...

                  To start off, make the numerator of both fractions equal and the denominators will represent the total units for men and women respectively.

                  Men --> 1/3 = 5/15
                  Women --> 5/7
                  Total --> 7 units + 15 units = 22 units

                  Part (a)
                  22 units --> 2244
                  15 units --> 2244/22 * 15 = 1530

                  Part (b)
                  15 units - 7 units = 8 units
                  8 units --> 2244/22 * 8 = 816
                  Thank you , Yu Xuan 🙂

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                  • B Offline
                    Bommu99
                    last edited by

                    Hi Mathsguru,


                    Would greatly appreciate your help to solve these 2 questions which are among the SMOPS sample questions.

                    Thanks,

                    Bommu99
                    http://www.postimage.org/image.php?v=gx11D_jS

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      Dharma
                      last edited by

                      Bommu99:
                      Hi Mathsguru,


                      Would greatly appreciate your help to solve these 2 questions which are among the SMOPS sample questions.

                      Thanks,

                      Bommu99
                      http://www.postimage.org/image.php?v=gx11D_jS
                      Q1
                      (1 + 2/1) x (1 + 2/2) x (1 + 2/3) x (1 + 2/4) x (1 + 2/5) x … x (1 + 2/26) x (1 + 2/27)
                      = 3/1 x 4/2 x 5/3 x 6/4 x 7/5 x … x 28/26 x 29 /27
                      = ½ x 28 x 29
                      = 406

                      Q3

                      Diagram A
                      Area of Shaded square = 50cm2
                      Area isosceles triangle = 2 x 50cm2 = 100cm2
                      Length of 2 equal side of triangle = a
                      ½ x a x a = 100
                      a^2 = 200
                      Base of triangle = sqrt (200 + 200) = 20
                      Height of triangle = 3h
                      ½ x 20 x 3h = 100
                      3h = 10cm

                      Diagram B
                      Side of shaded square = 2/3 x 3h = 20/3cm
                      Area of shaded square = 400/9 = 44 4/9cm2

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                      • N Offline
                        Ngserene617
                        last edited by

                        Dharma:
                        Bommu99:

                        Hi Mathsguru,


                        Would greatly appreciate your help to solve these 2 questions which are among the SMOPS sample questions.

                        Thanks,

                        Bommu99
                        http://www.postimage.org/image.php?v=gx11D_jS

                        Q1
                        (1 + 2/1) x (1 + 2/2) x (1 + 2/3) x (1 + 2/4) x (1 + 2/5) x … x (1 + 2/26) x (1 + 2/27)
                        = 3/1 x 4/2 x 5/3 x 6/4 x 7/5 x … x 28/26 x 29 /27

                        = ½ x 28 x 29
                        = 40.


                        Q3

                        Diagram A


                        Area of Shaded square = 50cm2
                        Area isosceles triangle = 2 x 50cm2 = 100cm2
                        Length of 2 equal side of triangle = a
                        ½ x a x a = 100
                        a^2 = 200
                        Base of triangle = sqrt (200 + 200) = 20
                        Height of triangle = 3h
                        ½ x 20 x 3h = 100

                        3h = 10cm

                        Diagram B
                        Side of shaded square = 2/3 x 3h = 20/3cm
                        Area of shaded square = 400/9 = 44 4/9cm2[/quo

                        Hi MathsGuru,

                        I need help for this question:
                        1. Mr Gunalan has 640 books. 3/4 of them are storybooks and the remaining books are magazines and journals. 3/5 of the remaining books are magazines.
                        a) how many magazines does he have?
                        b) He wants to buy more magazines so that the number of the magazines he has will increase to 20% of the total number of books. How many more magazines must he buy?

                        1 Reply Last reply Reply Quote 0

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