Tutor MathsGuru: Ask me for your burning Maths questions!

[Dharma]

clblinym:

Hi, Can anyone help in solving teh following math. Thank you very much.


Amy
http://postimage.org/image/ewjd3rj8/

A x B x C = 99,360

A = B + 2
B = C + 1

99,360
= 2^5 x 3^3 x 5 x 23
= (2 x 2 x 2 x 2 x 3) x (2 x 23) x (3 x 3 x 5 )
= 48 x 46 x 45
A = 48
B = 46
C = 45
No. of students in Class A = 48

[youngtay]

Hi, Muffins


Thanks

[clblinym]

Dharma:

clblinym:

Hi, Can anyone help in solving teh following math. Thank you very much.


Amy
http://postimage.org/image/ewjd3rj8/

A x B x C = 99,360

A = B + 2
B = C + 1

99,360
= 2^5 x 3^3 x 5 x 23
= (2 x 2 x 2 x 2 x 3) x (2 x 23) x (3 x 3 x 5 )
= 48 x 46 x 45
A = 48
B = 46
C = 45
No. of students in Class A = 48

Hi, Dharma

Thank you very much for the help.

[youngtay]

Hi, please help


1.Twice a number is greater than half that number by 24. Find the number.

2.Hassan and John have some money. If Hassan gives John $5, they will have the same amount of money. If John gives Hassan $5, Hassan will have twice as much money as John. How much money does each boy have?

3.You are given a big container wich is filled with 24 litres of oil and three empty containers whose capacities are 13 litres, 11 litres and 5 litres.

TIA

[Daddy]

Hi,


Please help on this question. Thanks.

1. The ratio of the number of oranges to the number of pears in Melvin’s stall was 9:5. He sold 240 oranges and 200 pears to Mr Koh. The ratio of the remaining number of oranges to the remaining pears was 12:5.
(a) How many oranges did he have left?
(b) How many oranges and pears did he have altogether at first?

Thanks
Daddy

[Brenda10]

Daddy:

Hi,


Please help on this question. Thanks.

1. The ratio of the number of oranges to the number of pears in Melvin's stall was 9:5. He sold 240 oranges and 200 pears to Mr Koh. The ratio of the remaining number of oranges to the remaining pears was 12:5.
(a) How many oranges did he have left?
(b) How many oranges and pears did he have altogether at first?

Thanks
Daddy

HI, DD working:

O : P
9 : 5
-240 -200
12 : 5


O 45u 1200
P 60u 2400
Diff 15u = 1200
1u = 80

Oranges Left 9u - 240
720 - 240 = 480

Oranges and pears at first : 14u
14 * 80 = 1120

Hopefully the answer is correct.

[firebird]

Dear friends


My son has received 4 As for his PSLE 2010 with a T score of 241. He got into SJI. Our family is very happy.

I would like thank the following tutors for their help:
1) Mathsguru
2) Dharma
3) Tianzhu
4) Vanilla cake & vanilla cake mum
5) Muffins
6) Coffeecat
7) Tang
Guan Hui
9) Trytry
10) David59

I hope I have not missed any person.

This forum helped my son to achieve an A for his maths. The above tutors answered all my question clearly. These tutors have given me the hope and confidence to guide my son in his further studies. Although A star is the best mark, but my son improved and has gained confidence in his maths. The credit goes to above tutors. These tutors were there to answer within a very short time.

Many many many many many… thanks to all.

Merry christmas and a happy new year.

With best regards
Firebird

[clblinym]

Hi, Can anyone help in solving the following 4 questions.


They are from SMOPS 2004. Thanks in advance!!
http://postimage.org/image/11lfjh0ro/

http://postimage.org/image/11liujpr8/

http://postimage.org/image/11lki3290/

http://postimage.org/image/11lm5meqs/

Is there any easier or shorter way to solve Q30? Thank you very much.


The answers are
Q19 (360 m)
Q28 (24 cm2)
Q29 (64665912)
Q30 (8, 11, 81) (12,4,84) (4, 18, 78 )


Regards,
Amy

[Dharma]

Q19


When Betty and David at Pt C, they walked 1/2 the circumference in total. When they meet for the 2nd at Pt D, they walked the circumference in total ( from Pt C to Pt D)

AC = 80m
BD = 60m

2 x AC = CB + BD
CB = 160m - 60m = 100m

Circumference = (60m + 100m) x 2 = 360m

[clblinym]

Dharma:

Q19


When Betty and David at Pt C, they walked 1/2 the circumference in total. When they meet for the 2nd at Pt D, they walked the circumference in total ( from Pt C to Pt D)

AC = 80m
BD = 60m

2 x AC = CB + BD
CB = 160m - 60m = 100m

Circumference = (60m + 100m) x 2 = 360m

It is very nice of you, Dharma. Really appreciate your great help.
Merry Christmas.