Tutor MathsGuru: Ask me for your burning Maths questions!

[wkong]

Mathmaniac:

tianzhu:

[quote]2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of money in Box B is $1.80 more than that in Box A. How much money is there in Box A?

Hi

You may use Guess and check or Number*Units to solve Q2.

You'll get 36 number of 20 cents coin and 18 number of 50 cents coin, making a difference of $1.80(more of 50 cents).

The answer is $7.20.

Best wishes

Sorry, I read the question wrongly. I thought the question said the amount of money in A is more than B, which is impossible.

A faster way of doing:

$0.20x2=$0.40
For 1 50 cent coin in B, you have 2 20 cents coins in A, and a difference of 50-40=10 cents.
So for 1.80 difference, you take 1.80/0.10=18 coins in B
So u have 2x18=36 coins in A.
36x$0.20=$7.20[/quote]Thanks Mathmaniac and tianzhu for solving Qn 2.

[clblinym]

Hi, Can anyone help in solving teh following math. Thank you very much.


Amy
http://postimage.org/image/ewjd3rj8/

[Dharma]

clblinym:

Hi, Can anyone help in solving teh following math. Thank you very much.


Amy
http://postimage.org/image/ewjd3rj8/

A x B x C = 99,360

A = B + 2
B = C + 1

99,360
= 2^5 x 3^3 x 5 x 23
= (2 x 2 x 2 x 2 x 3) x (2 x 23) x (3 x 3 x 5 )
= 48 x 46 x 45
A = 48
B = 46
C = 45
No. of students in Class A = 48

[youngtay]

Hi, Muffins


Thanks

[clblinym]

Dharma:

clblinym:

Hi, Can anyone help in solving teh following math. Thank you very much.


Amy
http://postimage.org/image/ewjd3rj8/

A x B x C = 99,360

A = B + 2
B = C + 1

99,360
= 2^5 x 3^3 x 5 x 23
= (2 x 2 x 2 x 2 x 3) x (2 x 23) x (3 x 3 x 5 )
= 48 x 46 x 45
A = 48
B = 46
C = 45
No. of students in Class A = 48

Hi, Dharma

Thank you very much for the help.

[youngtay]

Hi, please help


1.Twice a number is greater than half that number by 24. Find the number.

2.Hassan and John have some money. If Hassan gives John $5, they will have the same amount of money. If John gives Hassan $5, Hassan will have twice as much money as John. How much money does each boy have?

3.You are given a big container wich is filled with 24 litres of oil and three empty containers whose capacities are 13 litres, 11 litres and 5 litres.

TIA

[Daddy]

Hi,


Please help on this question. Thanks.

1. The ratio of the number of oranges to the number of pears in Melvin’s stall was 9:5. He sold 240 oranges and 200 pears to Mr Koh. The ratio of the remaining number of oranges to the remaining pears was 12:5.
(a) How many oranges did he have left?
(b) How many oranges and pears did he have altogether at first?

Thanks
Daddy

[Brenda10]

Daddy:

Hi,


Please help on this question. Thanks.

1. The ratio of the number of oranges to the number of pears in Melvin's stall was 9:5. He sold 240 oranges and 200 pears to Mr Koh. The ratio of the remaining number of oranges to the remaining pears was 12:5.
(a) How many oranges did he have left?
(b) How many oranges and pears did he have altogether at first?

Thanks
Daddy

HI, DD working:

O : P
9 : 5
-240 -200
12 : 5


O 45u 1200
P 60u 2400
Diff 15u = 1200
1u = 80

Oranges Left 9u - 240
720 - 240 = 480

Oranges and pears at first : 14u
14 * 80 = 1120

Hopefully the answer is correct.

[firebird]

Dear friends


My son has received 4 As for his PSLE 2010 with a T score of 241. He got into SJI. Our family is very happy.

I would like thank the following tutors for their help:
1) Mathsguru
2) Dharma
3) Tianzhu
4) Vanilla cake & vanilla cake mum
5) Muffins
6) Coffeecat
7) Tang
Guan Hui
9) Trytry
10) David59

I hope I have not missed any person.

This forum helped my son to achieve an A for his maths. The above tutors answered all my question clearly. These tutors have given me the hope and confidence to guide my son in his further studies. Although A star is the best mark, but my son improved and has gained confidence in his maths. The credit goes to above tutors. These tutors were there to answer within a very short time.

Many many many many many… thanks to all.

Merry christmas and a happy new year.

With best regards
Firebird

[clblinym]

Hi, Can anyone help in solving the following 4 questions.


They are from SMOPS 2004. Thanks in advance!!
http://postimage.org/image/11lfjh0ro/

http://postimage.org/image/11liujpr8/

http://postimage.org/image/11lki3290/

http://postimage.org/image/11lm5meqs/

Is there any easier or shorter way to solve Q30? Thank you very much.


The answers are
Q19 (360 m)
Q28 (24 cm2)
Q29 (64665912)
Q30 (8, 11, 81) (12,4,84) (4, 18, 78 )


Regards,
Amy